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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#229772#7640. Colorful Cyclesucup-team2303#WA 141ms81760kbC++171.7kb2023-10-28 16:52:402023-10-28 16:52:41

Judging History

你现在查看的是最新测评结果

  • [2024-07-04 22:58:32]
  • hack成功,自动添加数据
  • (/hack/728)
  • [2023-10-28 16:52:41]
  • 评测
  • 测评结果:WA
  • 用时:141ms
  • 内存:81760kb
  • [2023-10-28 16:52:40]
  • 提交

answer

// #pragma GCC optimize("O3")
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
// #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,avx2,tune=native")
#include <bits/stdc++.h>
using namespace std;

#define PB emplace_back
// #define int long long
#define ll long long
#define vi vector<int>
#define siz(a) ((int) ((a).size()))
#define rep(i, a, b) for (int i = (a); i <= (b); ++i)
#define per(i, a, b) for (int i = (a); i >= (b); --i)
void print(vi n) {rep(i, 0, siz(n) - 1) cerr << n[i] << " \n"[i == siz(n) - 1];}

const int N = 1e6;
int T, a, b, in[N + 5], vis[N + 5];
vi st[3][N + 5];
struct pii {int x, y, z;} s[N + 5];

bool find(int n) {
	rep(i, 0, 2) for(int x : st[i][n]) vis[x] = i;
	bool res = 0;
	rep(i, 0, 2) for(int x : st[i][n]) {
		rep(j, 0, 2) if(i != j) for(int y : st[j][x])
		if(vis[y] != -1 && vis[y] != j && vis[y] != i) res = 1;
		if(res) break;
	}
	rep(i, 0, 2) for(int x : st[i][n]) vis[x] = -1;
	return res;
}

signed main() {
	// freopen(".in", "r", stdin);
	// freopen(".out", "w", stdout);
	ios::sync_with_stdio(0);
	cin.tie(0), cout.tie(0);
	memset(vis, -1, sizeof(vis));
	for(cin >> T; T--; ) {
		cin >> a >> b;
		rep(i, 1, a) st[0][i].clear(), st[1][i].clear(), st[2][i].clear(), in[i] = 0;
		int x, y, z;
		rep(i, 1, b) {
			cin >> x >> y >> z;
			s[i] = pii {x, y, z};
			++in[x], ++in[y];
		}
		rep(i, 1, b) {
			auto [x, y, z] = s[i];
			if(in[x] > in[y] || (in[x] == in[y] && x < y)) st[z - 1][x].PB(y);
			else st[z - 1][y].PB(x);
		}
		bool ans = 0;
		rep(i, 1, a) if(find(i)) {
			ans = 1;
			break;
		}
		ans ? cout << "Yes\n" : cout << "No\n";
	}
	return cerr << endl << 1.0 * clock() / CLOCKS_PER_SEC << endl, 0;
}

Details

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Test #1:

score: 100
Accepted
time: 8ms
memory: 81760kb

input:

2
3 3
1 2 3
2 3 1
1 3 2
5 6
1 2 1
2 3 1
1 3 2
3 4 3
3 5 3
4 5 3

output:

Yes
No

result:

ok 2 token(s): yes count is 1, no count is 1

Test #2:

score: -100
Wrong Answer
time: 141ms
memory: 79756kb

input:

100000
7 10
7 2 2
6 4 2
6 1 2
7 1 3
3 4 1
6 7 1
2 6 3
3 1 2
5 3 1
2 1 1
7 10
5 7 3
7 1 1
4 6 3
6 3 1
3 4 3
4 2 2
3 2 3
1 3 3
3 7 1
1 4 2
7 10
5 6 3
3 5 2
7 2 3
7 3 3
1 2 2
4 3 2
7 4 2
6 1 2
2 6 1
7 5 2
7 10
7 1 3
7 5 3
6 4 1
7 6 1
1 4 1
3 4 2
2 7 2
1 3 1
3 5 3
5 1 3
7 10
6 7 2
3 4 3
1 4 2
5 3 2
7 4 ...

output:

Yes
No
No
No
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
No
No
Yes
No
Yes
No
No
Yes
Yes
No
Yes
No
Yes
No
Yes
No
No
Yes
Yes
Yes
Yes
No
No
Yes
No
No
No
Yes
Yes
Yes
Yes
No
No
No
Yes
Yes
Yes
No
No
No
Yes
No
Yes
Yes
Yes
No
Yes
No
No
Yes
Yes
Yes
No
Yes
Yes
Yes
Yes
Yes
No
No
No
No
No
Yes
Yes
No
Yes
No
No
No
Yes
No
Y...

result:

wrong answer expected YES, found NO [2nd token]