#include <bits/stdc++.h>

using namespace std;
typedef long long ll;
const double pi = acos(-1.0);//高精度圆周率
const double eps = 1e-8;//偏差值
const int maxp = 1010;//点的数量
#define db double
//判断是否等于零，返回0为等于零，返回-1为小于，1为大于
int sgn(double x) {
	if (fabs(x) < eps)return 0;
	else return x < 0 ? -1 : 1;
}

//判断是否相等，返回0为相等，返回-1为小于，1为大于
int dcmp(double x, double y) {
	if (fabs(x - y) < eps)return 0;
	else return x < y ? -1 : 1;
}

//三维几何
struct Point3 {
	double x, y, z;
	Point3() {}
	Point3(double x, double y, double z) : x(x), y(y), z(z) {}
	Point3 operator+(Point3 B) { return Point3(x + B.x, y + B.y, z + B.z); }
	Point3 operator-(Point3 B) { return Point3(x - B.x, y - B.y, z + B.z); }
	Point3 operator*(double k) { return Point3(x * k, y * k, z * k); }//放大k倍
	Point3 operator/(double k) { return Point3(x / k, y / k, z / k); }//缩小k倍
	bool operator==(Point3 B) { return sgn(x - B.x) == 0 && sgn(y - B.y) == 0 && sgn(z - B.z) == 0; }
};

typedef Point3 Vector3;
//两点距离
double Distance(Point3 A, Point3 B) { return sqrt((A.x - B.x) * (A.x - B.x) + (A.y - B.y) * (A.y - B.y) + (A.z - B.z) * (A.z - B.z));}

struct Line3 {
	Point3 p1, p2;
	Line3() {}
	//根据端点确定直线
	Line3(Point3 p1, Point3 p2) : p1(p1), p2(p2) {}
};

typedef Line3 Segment3;
//向量点积
double Dot(Vector3 A, Vector3 B) { return A.x * B.x + A.y * B.y + A.z * B.z;}

//向量长度
double vector_length(Vector3 A) { return sqrt(Dot(A, A));}

//向量长度平方
double vector_length_square(Vector3 A) { return Dot(A, A);}

//向量夹角
double Angle(Vector3 A, Vector3 B) {
	return acos(Dot(A, B) / vector_length(A) / vector_length(B));
}

//向量叉积；大于0，B在A逆时针方向；等于0，A、B重合
Vector3 Cross(Vector3 A, Vector3 B) { return Point3 (A.y * B.z - A.z * B.y, A.z * B.x - A.x * B.z, A.x * B.y - A.y * B.x);}

//三点构成平行四边形面积(A为公共点)
double Area2(Point3 A, Point3 B, Point3 C) {
	return vector_length(Cross(B - A, C - A));
}

//判断p是否在三角形ABC内,可以用Area2来计算;如果点p在三角形内部,那么用电p对三角形ABC进行刨分,形成的3个三角形的面积应和直接计算ABC的面积相等

// dcmp(Area2(p, A, B) + Area2(p, B, C) + Area2(p, C, A), Area2(A, B, C)) == 0;

//点在直线上
bool Point_line_relation(Point3 p, Segment3 v) {
	return sgn(vector_length(Cross(v.p1 - p, v.p2 - p))) == 0 && sgn(Dot(v.p1 - p, v.p2 - p)) == 0;
}

//点到直线的距离
double Dis_point_line(Point3 p, Line3 v) {
	return vector_length(Cross(v.p2 - v.p1, p - v.p1) / Distance(v.p1, v.p2));
}

//点在直线上的投影
Point3 Point_line_proj(Point3 p, Line3 v) {
	double k = Dot(v.p2 - v.p1, p - v.p1) / vector_length_square(v.p2 - v.p1);
	return v.p1 + (v.p2 - v.p1) * k;
}

//点到线段的距离
double Dis_point_seg(Point3 p, Segment3 v) {
	if (sgn(Dot(p - v.p1, v.p2 - v.p1)) < 0 || sgn(Dot(p - v.p2, v.p1 - v.p2)) < 0) //点的投影不在线段上
		return min(Distance(p, v.p1), Distance(p, v.p2));
	return Dis_point_line(p, v); //点的投影在线段上
}

//三维 : 平面
struct Plane {
	Point3 p1, p2, p3;
	Plane() {}
	Plane(Point3 p1, Point3 p2, Point3 p3) : p1(p1) , p2(p2), p3(p3) {}
};

//平面法向量
Point3 pvec(Point3 A, Point3 B, Point3 C) { return Cross(B - A, C - A); }
Point3 pvec(Plane f) { return Cross(f.p2 - f.p1, f.p3 - f.p1); }

//四点共平面
bool Point_on_plane(Point3 A, Point3 B, Point3 C, Point3 D) {
	return sgn(Dot(pvec(A, B, C), D - A)) == 0;
}

//两平面平行
int parallel(Plane f1, Plane f2) {
	return vector_length(Cross(pvec(f1), pvec(f2))) < eps;
}

//两平面垂直
int vertical(Plane f1, Plane f2) {
	return sgn(Dot(pvec(f1), pvec(f2))) == 0;
}

//直线与平面的交点p,返回值是交点的个数
int Line_cross_plane(Line3 u, Plane f, Point3 &p) {
	Point3 v = pvec(f); //平面的法向量
	double x = Dot(v, u.p2 - f.p1);
	double y = Dot(v, u.p1 - f.p1);
	double d = x - y;
	if (sgn(x) == 0 && sgn(y) == 0) return -1; //v在f上
	if (sgn(d) == 0) return 0; //v与f平行
	p = ((u.p1 * x) - (u.p2 * y)) / d; //v与f相交
	return 1;
}

//四面体有向体积X6
double volume4(Point3 A, Point3 B, Point3 C, Point3 D) {
	return Dot(Cross(B - A, C - A), D - A);
}

Point3 p[55];

int main() {
	int n;
	cin >> n;
	for (int i = 1; i <= n; i++) {
		int x, y, z;
		cin >> x >> y >> z;
		p[i] = Point3(x, y, z);
	}
	db ans = 1e18;
	for (int i = 1; i <= n; i++) {
		for (int j = 1; j <= n; j++) {
			for (int k = 1; k <= n; k++) {
				if (i == j || i == k || j == k) continue;
				Vector3 a = p[j] - p[i], b = p[k] - p[i];
				Vector3 v1 = Cross(a, b);
				db maxn = -1e18;
				db minn = 1e18;
				for (int ii = 1; ii <= n; ii++) {
					Vector3 v2 = p[ii] - p[i];
					db k = Dot(v1, v2) / vector_length(v1);
					maxn = max(maxn, k);
					minn = min(minn, k);
				}
				ans = min(ans, maxn - minn);
			}
		}
	}
	printf("%.10f\n", ans);
}