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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#226116 | #7580. Milk Candy | ucup-team004# | AC ✓ | 80ms | 3728kb | C++20 | 4.3kb | 2023-10-25 16:08:46 | 2023-10-25 16:08:47 |
Judging History
answer
#include <bits/stdc++.h>
using i64 = long long;
constexpr int N = 100;
constexpr int inf = 1E9;
int f[N];
void init(int n) {
std::iota(f, f + n, 0);
}
int find(int x) {
while (x != f[x]) {
x = f[x] = f[f[x]];
}
return x;
}
int merge(int a, int b) {
a = find(a);
b = find(b);
if (a == b) {
return 0;
}
f[b] = a;
return 1;
}
void solve() {
int n, m;
std::cin >> n >> m;
n += 1;
std::vector<std::array<int, 4>> edges;
std::vector<int> k(m);
int C = 0;
init(n);
for (int i = 0; i < m; i++) {
int c;
std::cin >> c >> k[i];
k[i] = c - k[i];
for (int j = 0; j < c; j++) {
int x, y, w;
std::cin >> x >> y >> w;
if (x > y) {
std::swap(x, y);
}
x--;
C += merge(x, y);
edges.push_back({x, y, w, i});
}
}
if (C != n - 1) {
std::cout << -1 << "\n";
return;
}
int l = edges.size();
std::vector<int> in(l);
while (true) {
std::vector<int> cnt(m);
for (int i = 0; i < l; i++) {
if (in[i]) {
cnt[edges[i][3]] += 1;
}
}
std::vector<int> f1(l), f2(l);
for (int i = 0; i < l; i++) {
if (!in[i]) {
int j = edges[i][3];
f1[i] = cnt[j] < k[j];
init(n);
int c = 0;
for (int j = 0; j < l; j++) {
if (!in[j] && j != i) {
c += merge(edges[j][0], edges[j][1]);
}
}
f2[i] = (c == n - 1);
}
}
std::vector g(l, std::vector<int>(l));
for (int i = 0; i < l; i++) {
if (in[i]) {
for (int j = 0; j < l; j++) {
if (!in[j]) {
int u = edges[j][3];
g[i][j] = (cnt[u] + 1 - (edges[i][3] == u) <= k[u]);
init(n);
int c = 0;
for (int k = 0; k < l; k++) {
if ((!in[k] && k != j) || k == i) {
c += merge(edges[k][0], edges[k][1]);
}
}
g[j][i] = (c == n - 1);
}
}
}
}
std::queue<int> q;
std::vector<int> inq(l), prv(l, -1);
std::vector<std::pair<int, int>> dis(l, {-inf, -inf});
for (int i = 0; i < l; i++) {
if (f1[i]) {
dis[i] = {edges[i][2], 0};
q.push(i);
inq[i] = 1;
}
}
int t = -1;
while (!q.empty()) {
int x = q.front();
q.pop();
if (f2[x] && (t == -1 || dis[x] > dis[t])) {
t = x;
}
inq[x] = 0;
for (int y = 0; y < l; y++) {
if (g[x][y]) {
std::pair<int, int> ndis = {dis[x].first + (in[y] ? -1 : 1) * edges[y][2], dis[x].second - 1};
if (ndis > dis[y]) {
dis[y] = ndis;
prv[y] = x;
if (!inq[y]) {
q.push(y);
inq[y] = 1;
}
}
}
}
}
if (t == -1) {
break;
}
for (int i = t; i != -1; i = prv[i]) {
in[i] ^= 1;
}
}
int tot = std::count(in.begin(), in.end(), 1);
if (tot != std::accumulate(k.begin(), k.end(), 0)) {
std::cout << -1 << "\n";
} else {
i64 sum = 0;
for (int i = 0; i < l; i++) {
if (!in[i]) {
sum += edges[i][2];
}
}
std::cout << sum << "\n";
}
}
int main() {
std::ios::sync_with_stdio(false);
std::cin.tie(nullptr);
int t;
std::cin >> t;
while (t--) {
solve();
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3644kb
input:
2 2 2 1 1 1 2 1 3 2 1 1 10 2 2 100 1 2 1000 2 2 1 1 1 1 1 1 1 1 1 2
output:
111 -1
result:
ok 2 number(s): "111 -1"
Test #2:
score: 0
Accepted
time: 80ms
memory: 3728kb
input:
10 50 55 1 1 1 1 829226 1 1 2 2 485572 1 1 3 3 541135 1 1 4 4 683672 1 1 5 5 221134 1 1 6 6 589289 1 1 7 7 853944 1 1 8 8 463334 2 1 9 9 212920 24 34 4065 2 2 10 10 920920 40 43 559059 1 1 11 11 467880 1 1 12 12 561361 2 1 13 13 218407 29 48 226199 1 1 14 14 353783 1 1 15 15 875637 1 1 16 16 122290 ...
output:
29640398 40230474 -1 12149117 9430424 13935806 14440341 8331917 15753760 16573955
result:
ok 10 numbers