#include <bits/stdc++.h>
using namespace std;

typedef long long ll;

ll ceilsq(ll x){
	ll sz=sqrtl(x);
	for (;(sz)*(sz)<x;) sz++;
	for (;(sz-1)*(sz-1)>=x;) sz--;
	return sz; 	
}

typedef long long db;

struct point{
	db x,y,z;
	point operator + (const point &k1){return (point){x+k1.x,y+k1.y,z+k1.z};}
	point operator - (const point &k1){return (point){x-k1.x,y-k1.y,z-k1.z};}
	db abs(){return ceilsq(x*x+y*y+z*z);}
	db abs2(){return x*x+y*y+z*z;}
	db dis(point k){return ((*this)-k).abs();}
	db dis2(point k){return ((*this)-k).abs2();}
};

struct circle{
	point o;
	db r;
};

const int maxn=100000;
const int base=1000001;
int n,k;
circle a[maxn+50];
vector<db> ans;

ll getid(ll x,ll y,ll z){
	return (x*base+y)*base+z;
}
void check(db mid){
	ans.clear();
	db pre2R=2e9;
	unordered_map<ll,vector<int>> dict;
	for (int i=1;i<=n;i++){
		if (a[i].r*4+mid*2<pre2R){
			pre2R=a[i].r*2+mid;
			dict.clear();
			for (int j=1;j<i;j++){
				ll id=getid(a[j].o.x,a[j].o.y,a[j].o.z);
				dict[id].push_back(j);
			}
		}
		ll nowx=a[i].o.x/pre2R;
		ll nowy=a[i].o.y/pre2R;
		ll nowz=a[i].o.z/pre2R;
		for (ll dx=-1;dx<=1;dx++){
			if (nowx+dx<0) continue;
			for (ll dy=-1;dy<=1;dy++){
				if (nowy+dy<0) continue;
				for (ll dz=-1;dz<=1;dz++){
					if (nowz+dz<0) continue;
					ll id=getid(nowx+dx,nowy+dy,nowz+dz);
					if (dict.count(id)){
						for (auto j:dict[id]){
							db d=a[i].o.dis(a[j].o)-a[i].r-a[j].r;
							d=max(d,(db)0);
							if (d<=mid){
								ans.push_back(d);
								if ((int)ans.size()==k) return;	
							}
						}
					}
				}	
			}	
		}
		ll id=getid(nowx,nowy,nowz);
		dict[id].emplace_back(i);
	}
}

void solve(){
	cin >> n >> k;
	for (int i=1;i<=n;i++)
		cin >> a[i].o.x >> a[i].o.y >> a[i].o.z >> a[i].r;
	sort(a+1,a+n+1,
		[&](const circle &A,const circle &B){
			return A.r>B.r;	
		}
	);	
	db l=0,r=1e7;
	while (l<r){
		db mid=(l+r)/2;
		check(mid);
		if ((int)ans.size()==k) r=mid;
		else l=mid+1;
	}
	if (l>1){
		check(l-1);
		while ((int)ans.size()!=k) ans.push_back(l);	
	}
	sort(ans.begin(),ans.end());
	for (auto e:ans) cerr << e << "\n";
}

int main(){
	ios_base::sync_with_stdio(false);
	int Tcase=3;
	cin >> Tcase;
	for (;Tcase--;){
		solve();
	}
	return 0;	
}