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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#220678#6309. Aqreucup-team1883#WA 3ms5908kbC++142.9kb2023-10-20 17:43:012023-10-20 17:43:01

Judging History

你现在查看的是最新测评结果

  • [2023-10-20 17:43:01]
  • 评测
  • 测评结果:WA
  • 用时:3ms
  • 内存:5908kb
  • [2023-10-20 17:43:01]
  • 提交

answer

#include <iostream>

const int N = 1005;
const int pat[][4][4] = {
  {
    {1, 1, 0, 1},
    {1, 0, 1, 1},
    {1, 1, 1, 0},
    {0, 1, 1, 1}
  },
  {
    {1, 1, 1, 0},
    {1, 0, 1, 1},
    {0, 1, 1, 1},
    {1, 1, 0, 1}
  },
  {
    {1, 1, 1, 0},
    {1, 1, 0, 1},
    {0, 1, 1, 1},
    {1, 0, 1, 1}
  },
  {
    {1, 1, 0, 1},
    {1, 1, 1, 0},
    {1, 0, 1, 1},
    {0, 1, 1, 1}
  }
};

int ans[N][N], now[N][N];

int main() {
  int T;
  scanf("%d", &T);
  while (T--) {
    int n, m;
    scanf("%d %d", &n, &m);
    int mx = 0;
    if (n < 4 && m < 4) {
      for (int i = 0; i < n; ++i) {
        for (int j = 0; j < m; ++j) {
          ans[i][j] = 1;
        }
      }
      mx = n * m;
    }
    if (n == 3 && m % 4 == 3) {
      static const int shaber[3][4] = {
        {1, 1, 1, 0},
        {1, 1, 1, 0},
        {1, 0, 1, 1}
      };
      int sum = 0;
      for (int i = 0; i < n; ++i) {
        for (int j = 0; j < m; ++j) {
          ans[i][j] = shaber[i][j % 4];
          sum += ans[i][j];
        }
      }
      printf("%d\n", sum);
      for (int i = 0; i < n; ++i) {
        for (int j = 0; j < m; ++j) {
          printf("%d", ans[i][j]);
        }
        puts("");
      }
      continue;
    }
    if (m == 3 && n % 4 == 3) {
      static const int shaber[4][3] = {
        {1, 1, 1},
        {1, 1, 0},
        {1, 1, 1},
        {0, 0, 1}
      };
      int sum = 0;
      for (int i = 0; i < n; ++i) {
        for (int j = 0; j < m; ++j) {
          ans[i][j] = shaber[i % 4][j];
          sum += ans[i][j];
        }
      }
      printf("%d\n", sum);
      for (int i = 0; i < n; ++i) {
        for (int j = 0; j < m; ++j) {
          printf("%d", ans[i][j]);
        }
        puts("");
      }
      continue;
    }
    for (int k = 0; k < 4; ++k) {
      if (m == 2 && k != 0) continue;
      if (n == 2 && k != 1) continue;
      for (int i = 0; i < n; ++i) {
        for (int j = 0; j < m; ++j) {
          now[i][j] = pat[k][i % 4][j % 4];
        }
      }
      if (k == 0 && n % 4 == 2 && m % 4 == 3) {
        now[n - 1][m - 1] = 0;
      }
      if (k == 1 && n % 4 == 3 && m % 4 == 2) {
        now[n - 1][m - 1] = 0;
      }
      if (k == 2 && n % 4 == 0) {
        now[n - 1][0] = 0;
      }
      if (k == 3 && m % 4 == 0) {
        now[0][m - 1] = 0;
      }
      int sum = 0;
      for (int i = 0; i < n; ++i) {
        for (int j = 0; j < m; ++j) {
          sum += now[i][j];
        }
      }
      if (sum > mx) {
        for (int i = 0; i < n; ++i) {
          for (int j = 0; j < m; ++j) {
            ans[i][j] = now[i][j];
          }
        }
        mx = sum;
      }
    }
    printf("%d\n", mx);
    for (int i = 0; i < n; ++i) {
      for (int j = 0; j < m; ++j) {
        printf("%d", ans[i][j]);
      }
      puts("");
    }
  }
  return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 1ms
memory: 5908kb

input:

3
2 2
3 4
3 8

output:

4
11
11
9
1101
1011
1110
18
11011101
10111011
11101110

result:

ok ok (3 test cases)

Test #2:

score: -100
Wrong Answer
time: 3ms
memory: 5808kb

input:

361
2 2
2 3
2 4
2 5
2 6
2 7
2 8
2 9
2 10
2 11
2 12
2 13
2 14
2 15
2 16
2 17
2 18
2 19
2 20
3 2
3 3
3 4
3 5
3 6
3 7
3 8
3 9
3 10
3 11
3 12
3 13
3 14
3 15
3 16
3 17
3 18
3 19
3 20
4 2
4 3
4 4
4 5
4 6
4 7
4 8
4 9
4 10
4 11
4 12
4 13
4 14
4 15
4 16
4 17
4 18
4 19
4 20
5 2
5 3
5 4
5 5
5 6
5 7
5 8
5 9
5 1...

output:

4
11
11
6
111
111
6
1110
1011
8
11101
10111
9
111011
101110
11
1110111
1011101
12
11101110
10111011
14
111011101
101110111
15
1110111011
1011101110
17
11101110111
10111011101
18
111011101110
101110111011
20
1110111011101
1011101110111
21
11101110111011
10111011101110
23
111011101110111
1011101110111...

result:

wrong answer ans finds a larger answer (test case 21)