QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#220678 | #6309. Aqre | ucup-team1883# | WA | 3ms | 5908kb | C++14 | 2.9kb | 2023-10-20 17:43:01 | 2023-10-20 17:43:01 |
Judging History
answer
#include <iostream>
const int N = 1005;
const int pat[][4][4] = {
{
{1, 1, 0, 1},
{1, 0, 1, 1},
{1, 1, 1, 0},
{0, 1, 1, 1}
},
{
{1, 1, 1, 0},
{1, 0, 1, 1},
{0, 1, 1, 1},
{1, 1, 0, 1}
},
{
{1, 1, 1, 0},
{1, 1, 0, 1},
{0, 1, 1, 1},
{1, 0, 1, 1}
},
{
{1, 1, 0, 1},
{1, 1, 1, 0},
{1, 0, 1, 1},
{0, 1, 1, 1}
}
};
int ans[N][N], now[N][N];
int main() {
int T;
scanf("%d", &T);
while (T--) {
int n, m;
scanf("%d %d", &n, &m);
int mx = 0;
if (n < 4 && m < 4) {
for (int i = 0; i < n; ++i) {
for (int j = 0; j < m; ++j) {
ans[i][j] = 1;
}
}
mx = n * m;
}
if (n == 3 && m % 4 == 3) {
static const int shaber[3][4] = {
{1, 1, 1, 0},
{1, 1, 1, 0},
{1, 0, 1, 1}
};
int sum = 0;
for (int i = 0; i < n; ++i) {
for (int j = 0; j < m; ++j) {
ans[i][j] = shaber[i][j % 4];
sum += ans[i][j];
}
}
printf("%d\n", sum);
for (int i = 0; i < n; ++i) {
for (int j = 0; j < m; ++j) {
printf("%d", ans[i][j]);
}
puts("");
}
continue;
}
if (m == 3 && n % 4 == 3) {
static const int shaber[4][3] = {
{1, 1, 1},
{1, 1, 0},
{1, 1, 1},
{0, 0, 1}
};
int sum = 0;
for (int i = 0; i < n; ++i) {
for (int j = 0; j < m; ++j) {
ans[i][j] = shaber[i % 4][j];
sum += ans[i][j];
}
}
printf("%d\n", sum);
for (int i = 0; i < n; ++i) {
for (int j = 0; j < m; ++j) {
printf("%d", ans[i][j]);
}
puts("");
}
continue;
}
for (int k = 0; k < 4; ++k) {
if (m == 2 && k != 0) continue;
if (n == 2 && k != 1) continue;
for (int i = 0; i < n; ++i) {
for (int j = 0; j < m; ++j) {
now[i][j] = pat[k][i % 4][j % 4];
}
}
if (k == 0 && n % 4 == 2 && m % 4 == 3) {
now[n - 1][m - 1] = 0;
}
if (k == 1 && n % 4 == 3 && m % 4 == 2) {
now[n - 1][m - 1] = 0;
}
if (k == 2 && n % 4 == 0) {
now[n - 1][0] = 0;
}
if (k == 3 && m % 4 == 0) {
now[0][m - 1] = 0;
}
int sum = 0;
for (int i = 0; i < n; ++i) {
for (int j = 0; j < m; ++j) {
sum += now[i][j];
}
}
if (sum > mx) {
for (int i = 0; i < n; ++i) {
for (int j = 0; j < m; ++j) {
ans[i][j] = now[i][j];
}
}
mx = sum;
}
}
printf("%d\n", mx);
for (int i = 0; i < n; ++i) {
for (int j = 0; j < m; ++j) {
printf("%d", ans[i][j]);
}
puts("");
}
}
return 0;
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 1ms
memory: 5908kb
input:
3 2 2 3 4 3 8
output:
4 11 11 9 1101 1011 1110 18 11011101 10111011 11101110
result:
ok ok (3 test cases)
Test #2:
score: -100
Wrong Answer
time: 3ms
memory: 5808kb
input:
361 2 2 2 3 2 4 2 5 2 6 2 7 2 8 2 9 2 10 2 11 2 12 2 13 2 14 2 15 2 16 2 17 2 18 2 19 2 20 3 2 3 3 3 4 3 5 3 6 3 7 3 8 3 9 3 10 3 11 3 12 3 13 3 14 3 15 3 16 3 17 3 18 3 19 3 20 4 2 4 3 4 4 4 5 4 6 4 7 4 8 4 9 4 10 4 11 4 12 4 13 4 14 4 15 4 16 4 17 4 18 4 19 4 20 5 2 5 3 5 4 5 5 5 6 5 7 5 8 5 9 5 1...
output:
4 11 11 6 111 111 6 1110 1011 8 11101 10111 9 111011 101110 11 1110111 1011101 12 11101110 10111011 14 111011101 101110111 15 1110111011 1011101110 17 11101110111 10111011101 18 111011101110 101110111011 20 1110111011101 1011101110111 21 11101110111011 10111011101110 23 111011101110111 1011101110111...
result:
wrong answer ans finds a larger answer (test case 21)