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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#217691#5109. Spider WalkqzezWA 548ms150112kbC++142.1kb2023-10-17 10:15:272023-10-17 10:15:27

Judging History

你现在查看的是最新测评结果

  • [2023-10-17 10:15:27]
  • 评测
  • 测评结果:WA
  • 用时:548ms
  • 内存:150112kb
  • [2023-10-17 10:15:27]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
using ll=long long;
template<typename T>
ostream& operator << (ostream &out,const vector<T>&x){
	if(x.empty())return out<<"[]";
	out<<'['<<x[0];
	for(int len=x.size(),i=1;i<len;i++)out<<','<<x[i];
	return out<<']';
}
template<typename T>
vector<T> ary(const T *a,int l,int r){
	return vector<T>{a+l,a+1+r};
}
template<typename T>
void debug(T x){
	cerr<<x<<'\n';
}
template<typename T,typename ...S>
void debug(T x,S ...y){
	cerr<<x<<' ',debug(y...);
}
const int N=2e5+10,M=5e5+10,V=N+M*2,INF=1e9;
int n,m,k,s,d[M],t[M],dis[V];
vector<int>p[N],id[N];
vector<pair<int,int> >to[V];
void add(int u,int v,int w){
	// if(!w)debug(u,v,w);
	to[u].push_back({v,w});
}
#define v e.first
#define w e.second
void dij(int s,int *d){
	deque<int>q;
	fill(d+1,d+1+k,INF),q.push_back(s),d[s]=0;
	for(int u;!q.empty();){
		u=q.front(),q.pop_front();
		for(auto e:to[u]){
			if(d[v]>d[u]+w){
				d[v]=d[u]+w;
				if(w)q.push_back(v);
				else q.push_front(v);
			}
		}
	}
}
#undef v
#undef w
int main(){
	scanf("%d%d%d",&n,&m,&s);
	for(int i=1;i<=m;i++){
		scanf("%d%d",&d[i],&t[i]);
		p[t[i]].push_back(d[i]);
		p[t[i]%n+1].push_back(d[i]);
	}
	for(int i=1;i<=n;i++){
		sort(p[i].begin(),p[i].end());
		p[i].push_back(INF);
		id[i].assign(p[i].size(),0);
		iota(id[i].begin(),id[i].end(),k+1);
		k+=id[i].size();
	}
	// debug(s);
	s=id[s].back();
	for(int i=1;i<=m;i++){
		int u=t[i],v=t[i]%n+1;
		// debug(p[u],p[v],d[i]);
		int x=lower_bound(p[u].begin(),p[u].end(),d[i])-p[u].begin();
		int y=lower_bound(p[v].begin(),p[v].end(),d[i])-p[v].begin();
		add(id[u][x+1],id[v][y],0),add(id[v][y+1],id[u][x],0);
	}
	// debug(id[3],p[3]);
	// debug(id[4],p[4]);
	// debug(id[5],p[5]);
	// debug(id[6],p[6]);
	for(int u=1;u<=n;u++){
		int v=u%n+1;
		int l1=p[u].size(),l2=p[v].size();
		for(int i=0,j=0;i<l1&&j<l2;){
			add(id[u][i],id[v][j],1),add(id[v][j],id[u][i],1);
			if(p[u][i]<p[v][j])i++;
			else j++;
		}
	}
	dij(s,dis);
	for(int i=1;i<=n;i++)printf("%d\n",dis[id[i][0]]);
	return 0;
}

详细

Test #1:

score: 100
Accepted
time: 233ms
memory: 150112kb

input:

200000 500000 116205
1 2
2 3
3 4
4 5
5 6
6 7
7 8
8 9
9 10
10 11
11 12
12 13
13 14
14 15
15 16
16 17
17 18
18 19
19 20
20 21
21 22
22 23
23 24
24 25
25 26
26 27
27 28
28 29
29 30
30 31
31 32
32 33
33 34
34 35
35 36
36 37
37 38
38 39
39 40
40 41
41 42
42 43
43 44
44 45
45 46
46 47
47 48
48 49
49 50
50...

output:

2
1
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
...

result:

ok 200000 lines

Test #2:

score: -100
Wrong Answer
time: 548ms
memory: 148328kb

input:

200000 500000 200000
1 148896
2 178903
3 36800
4 98361
5 79634
6 29266
7 51632
8 166082
9 66246
10 145043
11 41644
12 81858
13 87530
14 199625
15 127160
16 49786
17 181673
18 48403
19 30274
20 101455
21 105100
22 52149
23 22810
24 79308
25 191579
26 96365
27 154697
28 45255
29 64965
30 192604
31 330...

output:

1
0
1
1
2
2
3
3
4
5
5
6
6
6
7
8
8
9
9
8
9
10
10
11
12
12
12
11
12
13
13
14
14
15
16
17
17
18
19
19
18
19
19
20
20
21
21
22
22
23
24
24
25
25
26
26
27
27
28
28
29
30
31
31
32
33
33
32
33
33
33
34
35
34
35
36
36
37
37
37
38
39
38
39
40
41
41
42
42
43
43
44
44
45
46
46
47
48
48
49
49
50
50
49
50
51
51
...

result:

wrong answer 11th lines differ - expected: '6', found: '5'