QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#216971 | #6434. Paimon Sorting | indogent | AC ✓ | 327ms | 4480kb | C++14 | 1.1kb | 2023-10-16 10:07:58 | 2023-10-16 10:07:58 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 5;
int f[N], bit[N];
int n;
void add(int x) {
for (int i = x; i <= n; i += (i & (-i)))
bit[i]++;
};
int query(int x) {
int res = 0;
while (x > 0) {
res += bit[x];
x -= (x & (-x));
}
return res;
};
void solve() {
cin >> n;
for (int i = 0; i <= n; i++)
f[i] = bit[i] = 0;
long long cur = 0;
int tot = 0, owe = 0, dx = 0;
for (int i = 0, x; i < n; i++) {
cin >> x;
f[i] = x;
if (query(x) == query(x - 1))
add(x), ++tot;
else if (dx == 0 && f[i] == f[0]) {
dx = 1;
}
if (f[i] > f[0]) {
swap(f[i], f[0]);
++cur;
cur += owe;
owe = 0;
dx = 0;
}
owe += dx;
cur += tot - query(f[i]);
cout << cur;
cout << (i != n - 1 ? ' ' : '\n');
}
}
int main() {
ios::sync_with_stdio(false);
int t;
cin >> t;
while (t--) {
solve();
}
return 0;
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 0ms
memory: 3644kb
input:
3 5 2 3 2 1 5 3 1 2 3 1 1
output:
0 2 3 5 7 0 2 4 0
result:
ok 3 lines
Test #2:
score: 0
Accepted
time: 327ms
memory: 4480kb
input:
6107 19 10 13 8 8 11 18 12 9 15 19 6 13 11 11 17 9 14 2 18 12 1 8 10 2 10 2 6 1 5 9 5 7 16 14 4 2 15 12 14 10 3 2 9 15 4 12 9 5 15 10 3 2 5 6 7 8 6 1 6 4 18 6 5 12 12 11 2 10 10 5 10 13 15 13 10 17 7 11 2 1 1 2 1 1 3 2 1 2 17 11 15 3 10 7 15 15 10 5 17 3 3 14 13 11 11 2 3 2 2 3 7 6 1 7 5 3 5 1 7 2 1...
output:
0 2 4 6 7 9 11 16 17 19 28 31 36 41 43 51 55 67 68 0 2 4 6 6 8 10 14 17 18 22 25 0 1 3 5 7 8 11 16 22 26 26 31 33 37 42 42 0 1 3 5 7 9 11 17 19 23 0 1 3 3 4 8 10 12 16 18 27 29 30 34 36 42 46 55 0 0 0 0 1 1 0 2 4 6 9 9 9 11 15 21 27 33 35 38 42 46 55 0 0 3 0 1 3 5 8 10 14 0 1 3 4 6 9 9 0 1 1 3 7 11 ...
result:
ok 6107 lines