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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#215890 | #6442. Secret of Tianqiu Valley | veg# | WA | 1ms | 3688kb | C++14 | 980b | 2023-10-15 14:14:32 | 2023-10-15 14:14:32 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
int n;
char s[100005], t[100005];
int ans[100005], flag;
void f(int x) {
t[x] ^= 1;
t[x+1] ^= 1;
t[x+2] ^= 1;
}
void check(int A, int B) {
memcpy(t + 1, s + 1, n);
vector<int> ans;
int cnt = 0;
if (A) t[n-1]^=1,t[n]^=1,t[1]^=1, ans.push_back(n);
if (B) t[n]^=1,t[1]^=1,t[2]^=1, ans.push_back(1);
for (int i = 1; i <= n - 2; ++i) {
if (!t[i]) {
f(i);
ans.push_back(i+1);
}
}
if (!t[n-1]||!t[n]) return;
printf("%d\n%d", ans.size(),ans[0]);
for (int i = 1; i< ans.size(); ++i) printf(" %d", ans[i]);
puts("");
flag = 1;
}
int main() {
int T;
cin >> T;
while (T--) {
scanf("%d%s", &n, s + 1);
int p = 1;
for (int i = 1; i <= n; ++i) p &= (s[i] ^= 0x30);
if (p) {
puts("2\n1 1");
continue;
}
flag = 0;
if (!flag) check(0, 0);
if (!flag) check(1, 0);
if (!flag) check(0, 1);
if (!flag) check(1, 1);
if (!flag) puts("0");
}
return 0;
}
详细
Test #1:
score: 0
Wrong Answer
time: 1ms
memory: 3688kb
input:
2 5 00000 3 001
output:
5 5 1 2 3 4 0
result:
wrong answer ignite ignited torch (test case 1)