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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#212379#6433. Klee in Solitary ConfinementOMoonStars#WA 8ms54816kbC++142.1kb2023-10-13 15:25:322023-10-13 15:25:32

Judging History

你现在查看的是最新测评结果

  • [2023-10-13 15:25:32]
  • 评测
  • 测评结果:WA
  • 用时:8ms
  • 内存:54816kb
  • [2023-10-13 15:25:32]
  • 提交

answer

#include<algorithm>
#include<array>
#include<bitset>
#include<cmath>
#include<cstdio>
#include<cstring>
#include<iomanip>
#include<iostream>
#include<map>
#include<numeric>
#include<queue>
#include<set>
#include<unordered_map>
#define fi first
#define se second
#define pb push_back
#define mp make_pair
#define endl '\n'
using namespace std;
using ll=long long;
using db=double;
using pii=pair<int,int>;
const int inf=0x3f3f3f3f;
const int mod=998244353;
const int N=2e6+10,M=1e6;
int a[N];
vector<int>pos[N];//i的所有出现位置
bool vis[N];//以i为众数是否已计算
int mer[N];//a[i]和a[i]-k归并后的位置数组
int dp[N];
int main()
{
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    int n,m;
    cin >> n >> m;
    for(int i=1;i<=n;i++)
    {
        cin >> a[i];
        pos[a[i]+M].pb(i);//-1e6~1e6映射到0~2e6
    }
    int ans=0;
    for(int i=1;i<=n;i++)
        ans=max(ans,(int)pos[a[i]+M].size());//原序列的众数
    for(int i=1;i<=n;i++)//枚举众数
        if(!vis[a[i]+M]&&a[i]+M-m>=0&&a[i]+M-m<=2e6&&pos[a[i]+M-m].size())//以该数为众数未计算且a[i]-k存在于原序列
        {
            vis[a[i]+M]=true;//记录状态
            int j=0,k=0,idx=1;
            while(j<pos[a[i]+M].size()&&k<pos[a[i]+M-m].size())
            {
                if(pos[a[i]+M][j]<pos[a[i]+M-m][k])
                {
                    mer[idx++]=-1;
                    j++;
                }
                else
                {
                    mer[idx++]=1;
                    k++;
                }
            }
            while(j<pos[a[i]+M].size())
            {
                mer[idx++]=-1;
                j++;
            }
            while(k<pos[a[i]+M-m].size())
            {
                mer[idx++]=1;
                k++;
            }
            int maxdp=0;
            for(j=1;j<idx;j++)
            {
                dp[j]=max(dp[j-1]+mer[j],0);
                maxdp=max(maxdp,dp[j]);
            }
            ans=max(ans,(int)pos[a[i]+M].size()+maxdp);
        }
    cout << ans << endl;
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 3ms
memory: 54760kb

input:

5 2
2 2 4 4 4

output:

5

result:

ok 1 number(s): "5"

Test #2:

score: 0
Accepted
time: 3ms
memory: 54704kb

input:

7 1
3 2 3 2 2 2 3

output:

6

result:

ok 1 number(s): "6"

Test #3:

score: 0
Accepted
time: 4ms
memory: 54644kb

input:

7 1
2 3 2 3 2 3 3

output:

5

result:

ok 1 number(s): "5"

Test #4:

score: 0
Accepted
time: 3ms
memory: 52536kb

input:

9 -100
-1 -2 1 2 -1 -2 1 -2 1

output:

3

result:

ok 1 number(s): "3"

Test #5:

score: 0
Accepted
time: 8ms
memory: 54652kb

input:

200 121649
0 527189 -1000000 -306471 -998939 527189 -1000000 -1000000 0 527189 0 527189 0 527189 -306471 -998939 -306471 -306471 -306471 0 0 527189 527189 1000000 527189 -1000000 1000000 648838 -1000000 -998939 -998939 -998939 0 1000000 -1000000 -998939 527189 1000000 648838 -1000000 1000000 648838 ...

output:

37

result:

ok 1 number(s): "37"

Test #6:

score: 0
Accepted
time: 8ms
memory: 54816kb

input:

200 -454379
-385892 454379 -1000000 373644 -665078 -1000000 -1000000 454379 0 1000000 373644 -1000000 1000000 -385892 -1000000 373644 0 -665078 0 -665078 -1000000 -665078 -385892 -665078 -385892 454379 -665078 -385892 -1000000 454379 1000000 -385892 373644 454379 -1000000 -385892 -1000000 -385892 -1...

output:

40

result:

ok 1 number(s): "40"

Test #7:

score: -100
Wrong Answer
time: 7ms
memory: 54660kb

input:

200 0
451272 -1000000 677452 677452 0 18908 451272 677452 -233144 677452 451272 18908 -1000000 18908 -1000000 0 451272 0 -233144 677452 1000000 451272 1000000 18908 -1000000 0 -233144 451272 1000000 18908 677452 0 677452 0 677452 1000000 -233144 18908 451272 -1000000 -233144 18908 1000000 0 0 -23314...

output:

36

result:

wrong answer 1st numbers differ - expected: '35', found: '36'