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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#212171 | #6638. Treelection | sinsop90 | WA | 86ms | 6632kb | C++14 | 904b | 2023-10-13 10:42:09 | 2023-10-13 10:42:09 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
const int maxn = 3e5 + 5;
int T, f[maxn], fa[maxn], sz[maxn], n, vis[maxn];
bool check(int x) {
for(int i = n;i >= 1;i--) {
f[i] = max(0, f[i] - x);
if(fa[i]) f[fa[i]] += f[i] + 1;
}
return (f[1] > 0);
}
void solve() {
cin >> n;
for(int i = 2;i <= n;i++) cin >> fa[i];
for(int i = n;i >= 1;i--) sz[fa[i]] += sz[i] + 1;
int l = 1, r = n, res = 1;
while(l <= r) {
int mid = (l + r) >> 1;
if(!check(mid)) r = mid - 1;
else l = mid + 1, res = mid;
}
// cout << res << endl;
check(res - 1);
if(f[1] == 1) {
vis[1] = 1;
for(int i = 2;i <= n;i++) vis[i] = vis[fa[i]] & f[i];
}
for(int i = 1;i <= n;i++) {
if(sz[i] > res || (sz[i] == res && vis[i])) cout << 1;
else cout << 0;
}
cout << '\n';
}
int main() {
ios::sync_with_stdio(0);
cin.tie(0), cout.tie(0);
cin >> T;
while(T --) solve();
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 5732kb
input:
2 4 1 2 3 5 1 1 2 2
output:
1100 10000
result:
ok 2 lines
Test #2:
score: -100
Wrong Answer
time: 86ms
memory: 6632kb
input:
10 100000 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 10...
output:
111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111...
result:
wrong answer 2nd lines differ - expected: '111111111111111111111111111111...0000000000000000000000000000000', found: '111111111111111111111111111111...0000000000000000000000000000000'