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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#212121#5407. 基础图论练习题Rong70 0ms14316kbC++144.5kb2023-10-13 09:25:002023-10-13 09:25:00

Judging History

你现在查看的是最新测评结果

  • [2023-10-13 09:25:00]
  • 评测
  • 测评结果:0
  • 用时:0ms
  • 内存:14316kb
  • [2023-10-13 09:25:00]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
int T, n;
int E[5005][5005];
int firs[5005], nex[25000005], to[25000005], tot;
char s[2005];
int idx, dfn[5005], low[5005], bel[5005], sz[5005], cnt, sta[5005], top;
int ct[5005][5005], fw[5005][5005], rd_in_Scc[5005];
vector < int > vet[5005];
bool ins[5005];
long long Ans;
void Clear (){
    for (int i = 1;i <= n;++ i)
        for (int j = 1;j <= n;++ j)
            E[i][j] = fw[i][j] = 0;
    for (int i = 1;i <= n;++ i){
        bel[i] = 0;
        sz[i] = 0;
        rd_in_Scc[i] = 0;
        vet[i].clear ();
        firs[i] = 0;
        dfn[i] = low[i] = 0;
    }
    cnt = 0;
    tot = 0;
    idx = 0;
    Ans = 0;
}
void Add (int u, int v){
    E[u][v] = 1;
    E[v][u] = - 1;
    ++ tot;
    nex[tot] = firs[u];
    firs[u] = tot;
    to[tot] = v;
}
int Represent (char a){
    if (a >= '0' && a <= '9')
        return a - '0';
    else
        return 10 + a - 'A';
}
void Tarjan (int u){
    if (dfn[u] > 0)
        return ;
    low[u] = dfn[u] = ++ idx;
    sta[++ top] = u;
    ins[u] = true;
    for (int e = firs[u], v;e;e = nex[e]){
        v = to[e];
        if (dfn[v] == 0){
            Tarjan (v);
            low[u] = min (low[u], low[v]);
        } else
        if (ins[v])
            low[u] = min (low[u], dfn[v]);
    }
    if (dfn[u] == low[u]){
        int v;
        ++ cnt;
        do {
            v = sta[top --];
            ++ sz[cnt];
            bel[v] = cnt;
            ins[v] = false;
            vet[cnt].push_back (v);
        } while (u != v);
        for (int p = 0;p < (int) vet[cnt].size ();++ p)
            for (int e = firs[vet[cnt][p]];e;e = nex[e])
                if (bel[to[e]] == cnt)
                    ++ rd_in_Scc[to[e]];
        for (int p = 0;p < (int) vet[cnt].size ();++ p)
            ++ ct[cnt][rd_in_Scc[vet[cnt][p]]];
        for (int i = sz[cnt];i >= 0;-- i)
            if (rd_in_Scc[i] == 0)
                fw[cnt][i] = i;
            else
                fw[cnt][i] = fw[cnt][i + 1];
    }
}
const long long mod = 1e9 + 7;
long long Qpow (long long a, long long p){
    long long Res = 1;
    while (p > 0){
        if (p & 1)
            Res = Res * a % mod;
        a = a * a % mod;
        p >>= 1;
    }
    return Res;
}
int main (){
    scanf ("%d", &T);
    while (T --){
        scanf ("%d", &n);
        for (int i = 2;i <= n;++ i){
            int l = (i - 1) / 4 + 1;
            scanf ("\n%s", s + 1);
            for (int j = 1;j <= l;++ j){
                for (int k = 4 * j - 3, x = Represent (s[j]);k <= 4 * j && k < i;++ k, x >>= 1)
                    if (x & 1)
                        Add (i, k);
                    else
                        Add (k, i);
            }
        }
        for (int i = 1;i <= n;++ i)
            Tarjan (i);
        for (int i = 1;i <= n;++ i){
            long long w = Qpow (2, (i - 1) * (i - 2) / 2);
            for (int j = 1;j < i;++ j){
                int u = i, v = j;
                if (E[u][v] < 0)
                    swap (u, v);
                if (bel[u] != bel[v]){
                    if (bel[u] - 1 == bel[v])
                        (Ans += w * cnt % mod) %= mod;
                    else
                        (Ans += w * (cnt - (bel[u] - bel[v])) % mod) %= mod;
                } else {
                    int rep = bel[u];
                    int p = 0, lim = sz[rep];
                    -- ct[rep][rd_in_Scc[u]];
                    ++ rd_in_Scc[u];
                    ++ ct[rep][rd_in_Scc[u]];
                    -- ct[rep][rd_in_Scc[v]];
                    -- rd_in_Scc[v];
                    ++ ct[rep][rd_in_Scc[v]];
                    if (ct[rep][rd_in_Scc[u] - 1] == 0)
                        lim = min (lim, rd_in_Scc[u] - 1);
                    if (ct[rep][rd_in_Scc[v] + 1] == 0)
                        lim = min (lim, rd_in_Scc[v] + 1);
                    while (ct[rep][p] > 0){
                        p = fw[rep][p + 1];
                        p = min (p, lim);
                    }
                    -- ct[rep][rd_in_Scc[u]];
                    -- rd_in_Scc[u];
                    ++ ct[rep][rd_in_Scc[u]];
                    -- ct[rep][rd_in_Scc[v]];
                    ++ rd_in_Scc[v];
                    ++ ct[rep][rd_in_Scc[v]];
                    (Ans += w * (cnt + p) % mod) %= mod;
                }
                (w <<= 1) %= mod;
            }
        }
        printf ("%lld\n", Ans);
        return 0;
        Clear ();
    }
    return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Subtask #1:

score: 0
Wrong Answer

Test #1:

score: 0
Wrong Answer
time: 0ms
memory: 14316kb

input:

10000
100
1
2
2
8
C0
F0
27
78
AE1
C01
511
D87
EF20
3873
2742
73D0
DC9B0
FB2A3
9C011
9B4E0
95DC00
A7B980
F43531
6A6245
5347BE0
1A6C8A1
88E46D6
64CF3AE
D25F63C1
C894E4C3
1C0AFD73
EC1C3F9A
087CE17C0
22149A380
B28038AF1
B9CA21C7F
D78F5307C1
49045489A2
72C4DE6FD1
7713F40D05
EEE8878EEC1
310E62812B1
DA9D5B...

output:

281603732

result:

wrong answer Answer contains longer sequence [length = 10000], but output contains 1 elements

Subtask #2:

score: 0
Skipped

Dependency #1:

0%

Subtask #3:

score: 0
Skipped

Dependency #1:

0%

Subtask #4:

score: 0
Skipped

Dependency #1:

0%

Subtask #5:

score: 0
Skipped

Dependency #1:

0%