QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#211805#5422. Perfect PalindromehazeAC ✓12ms3920kbC++201.0kb2023-10-12 21:24:202023-10-12 21:24:20

Judging History

你现在查看的是最新测评结果

  • [2023-10-12 21:24:20]
  • 评测
  • 测评结果:AC
  • 用时:12ms
  • 内存:3920kb
  • [2023-10-12 21:24:20]
  • 提交

answer

#include<bits/stdc++.h>
#define irep(i,l,r) for(int i = l; i <= r; ++i)
#define drep(i,r,l) for(int i = r; i >= l; --i)
#define ceil(pp,qq) (((pp)>0)^((qq)>0)?-Abs(pp)/Abs(qq):(pp)%(qq)?(pp)/(qq)+1:(pp)/(qq))
#define floor(pp,qq) (((pp)>0)^((qq)>0)?-ceil(Abs(pp),Abs(qq)):(pp)/(qq))
#define ll long long
#define LL __int128
using namespace std;
ll Abs(ll x){return x > 0 ? x : - x;}
inline ll read(){
	char ch = getchar();
	ll s = 0; bool w = 0;
	while(!isdigit(ch)){if(ch == '-')w = 1;ch = getchar();}
	while(isdigit(ch))s = (s << 3) + (s << 1) + (ch ^ 48), ch = getchar();
	return w ? - s : s;
}

const int itinf = 1e9;
const ll llinf = 4e18;
const int mod = 1000000007;
const int N = 500009;

inline int mul(int nma, int nmb){
	return ((1ll * nma * nmb % mod) + mod) % mod;
}

int main(){
	int T = read();
	while(T --){
		string s;
		int sum = 0;
		cin >> s;
		vector<int>cnt(26);
		for(char ch : s){
			cnt[ch - 'a'] ++;
			sum = max(sum, cnt[ch - 'a']);
		}
		printf("%d\n", s.length() - sum);
	}
	return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3752kb

input:

2
abcb
xxx

output:

2
0

result:

ok 2 number(s): "2 0"

Test #2:

score: 0
Accepted
time: 12ms
memory: 3920kb

input:

11107
lfpbavjsm
pdtlkfwn
fmb
hptdswsoul
bhyjhp
pscfliuqn
nej
nxolzbd
z
clzb
zqomviosz
u
ek
vco
oymonrq
rjd
ktsqti
mdcvserv
x
birnpfu
gsgk
ftchwlm
bzqgar
ovj
nsgiegk
dbolme
nvr
rpsc
fprodu
eqtidwto
j
qty
o
jknssmabwl
qjfv
wrd
aa
ejsf
i
npmmhkef
dzvyon
p
zww
dp
ru
qmwm
sc
wnnjyoepxo
hc
opvfepiko
inuxx...

output:

8
7
2
8
4
8
2
6
0
3
7
0
1
2
5
2
4
6
0
6
2
6
5
2
5
5
2
3
5
6
0
2
0
8
3
2
0
3
0
6
5
0
1
1
1
2
1
8
1
7
5
3
4
4
1
8
5
5
8
8
6
3
0
2
3
2
1
5
0
0
9
3
3
4
8
4
0
4
2
6
6
0
8
7
4
3
9
3
4
2
5
8
8
8
6
1
4
4
2
7
2
8
6
4
4
8
7
8
4
9
3
8
0
7
7
2
6
0
0
5
4
0
7
5
4
2
1
6
7
5
2
4
4
7
3
3
2
5
4
8
5
0
3
5
1
2
3
0
4
7
...

result:

ok 11107 numbers