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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#211078#59. Determinant of A+BzThankto_zy60 0ms0kbC++145.2kb2023-10-12 08:33:402023-10-12 08:33:41

Judging History

你现在查看的是测评时间为 2023-10-12 08:33:41 的历史记录

  • [2024-05-05 11:54:08]
  • hack成功,自动添加数据
  • (/hack/617)
  • [2024-05-05 11:38:15]
  • hack成功,自动添加数据
  • (/hack/616)
  • [2024-03-04 04:46:38]
  • 管理员手动重测本题所有提交记录
  • 测评结果:0
  • 用时:0ms
  • 内存:0kb
  • [2024-03-04 04:35:40]
  • hack成功,自动添加数据
  • (/hack/552)
  • [2023-10-12 08:33:41]
  • 评测
  • 测评结果:0
  • 用时:0ms
  • 内存:0kb
  • [2023-10-12 08:33:40]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std; 
const int mod=998244353;
class mint{
	private:
		int x;
		long long ksm(long long w,int y)
		{
			if(!y)return 1;
			if(y%2==0)return ksm(w*w%mod,y>>1);
			return w*ksm(w*w%mod,y>>1)%mod;
		}
	public:
		void read()
		{
			int fl=0;x=0;
			char ch=getchar();
			while(ch<'0'||ch>'9')
			{
				if(ch=='-')fl=1;
				ch=getchar();
			}
			while('0'<=ch&&ch<='9')
			{
				x=(10ll*x+ch-'0')%mod;
				ch=getchar();
			}
			if(fl&&x)ch=mod-x;
		}
		void print(){cout<<x;}
		void operator=(long long y)
		{
			x=y%mod;
			if(x<0)x+=mod;
		}
		mint operator+(mint y)const{mint a;a.x=x+y.x;if(a.x>=mod)a.x-=mod;return a;}
		mint operator~(void){mint a;a.x=x;if(a.x)a.x=mod-a.x;return a;}
		mint operator-(mint y)const{mint a;a=x;return a+(~y);}
		mint operator*(mint y)const{mint a;a.x=1ll*x*y.x%mod;return a;}
		mint inv(){mint a;a.x=ksm(x,mod-2);return a;}
		mint operator/(mint y)const{mint a;a=x;return a*(y.inv());}
		int val(){return x;}
		mint &operator++(void){x++;if(x==mod)x=0;return *this;}
		mint &operator--(void){x--;if(x==-1)x=mod-1;return *this;}
		mint &operator+=(mint y){x+=y.x;if(x>=mod)x-=mod;return *this;}
		mint &operator-=(mint y){x-=y.x;if(x<0)x+=mod;return *this;}
		mint &operator*=(mint y){x=1ll*x*y.x%mod;return *this;}
		mint &operator/=(mint y){x=1ll*x*(y.inv()).x%mod;return *this;}
		friend istream &operator >>(istream&,mint&);
		friend ostream &operator <<(ostream&,mint);
};
istream &operator >>(istream& input,mint& x){
	x.read();
	return input;
}
ostream &operator <<(ostream& output,mint x){
	x.print();
	return output;
}
mint m0[505][505],m1[505][505];
mint a[505][505];
mint pl[505][505];
mint ans[505];
//求a的特征多项式 
void char_poly(int n)
{
	//hessenberg
	for(int i=1;i<=n;i++)
	{
		int p=-1;
		for(int j=i+1;j<=n;j++)
		{
			if(a[j][i].val())
			{
				p=j;
				break;
			}
		}
		if(p==-1)continue;
		swap(a[i+1],a[p]);
		for(int j=1;j<=n;j++)swap(a[j][i+1],a[j][p]);
		for(int j=i+2;j<=n;j++)
		{
			mint v=a[j][i]/a[i+1][i];
			for(int k=1;k<=n;k++)a[j][k]-=a[i+1][k]*v;
			for(int k=1;k<=n;k++)a[k][i+1]+=a[k][j]*v;
		}
	}
	pl[0][0]=1;
	for(int i=1;i<=n;i++)
	{
		for(int j=1;j<i;j++)
		{
			mint v=~a[j][i];
			for(int k=j+1;k<=i;k++)v*=a[k][k-1];
			for(int k=0;k<=n;k++)pl[i][k]+=pl[j-1][k]*v;
		}
		for(int j=1;j<=i;j++)pl[i][j]+=pl[i-1][j-1];
		for(int j=0;j<=i;j++)pl[i][j]-=pl[i-1][j]*a[i][i];
	}
	for(int i=0;i<=n;i++)ans[i]=pl[n][i];
}
mint g[505][505];
mint h[505][505];
//h=g^-1
void matriv(int n)
{
	for(int i=1;i<=n;i++)h[i][i]=1;
	for(int i=1;i<=n;i++)
	{
		int p=-1;
		for(int j=i;j<=n;j++)
		{
			if(g[i][j].val())
			{
				p=j;
				break;
			}
		}
		for(int j=1;j<=n;j++)
		{
			swap(g[i][j],g[p][j]);
			swap(h[i][j],h[p][j]); 
		}
		mint iv=g[i][i].inv();
		for(int j=1;j<=n;j++)
		{
			g[i][j]=g[i][j]*iv;
			h[i][j]=h[i][j]*iv;
		}
		if(p==-1)continue;
		for(int j=i+1;j<=n;j++)
		{
			mint v=g[j][i];
			for(int k=1;k<=n;k++)
			{
				g[j][k]-=g[i][k]*v;
				h[j][k]-=h[i][k]*v;
			}
		}
	}
	for(int i=n;i>=1;i--)
	{
		for(int j=i-1;j>=1;j--)
		{
			mint v=g[j][i];
			for(int k=1;k<=n;k++)
			{
				g[j][k]-=g[i][k]*v;
				h[j][k]-=h[i][k]*v;
			}
		}
	}
}
mint r[505][505];
//r=g*h
void product(int n)
{
	for(int i=1;i<=n;i++)
	{
		for(int j=1;j<=n;j++)
		{
			r[i][j]=0;
		}
	}
	for(int i=1;i<=n;i++)
	{
		for(int j=1;j<=n;j++)
		{
			for(int k=1;k<=n;k++)
			{
				r[i][j]+=g[i][k]*h[k][j];
			}
		}
	}
}
//det of h
mint det(int n)
{
	mint ret;
	ret=1;
	for(int i=1;i<=n;i++)
	{
		int p=-1;
		for(int j=1;j<=n;j++)
		{
			if(h[i][j].val())
			{
				p=j;
				break;
			}
		}
		if(p==-1)continue;
		if(p!=i)
		{
			swap(h[i],h[p]);
			ret=~ret;
		}
		for(int j=i+1;j<=n;j++)
		{
			mint v=h[j][i]/h[i][i];
			for(int k=1;k<=n;k++)
			{
				h[j][k]-=h[i][k]*v;
			}
		}
	}
	for(int i=1;i<=n;i++)ret*=h[i][i];
	return ret;
}
mt19937 rnd(time(0));
mint sum[505];
mint cho[505][505];
mint mi[505];
int main()
{
	int n;
	std::ios::sync_with_stdio(false);
	std::cin.tie(nullptr);
	cin>>n;
	for(int i=1;i<=n;i++)
	{
		for(int j=1;j<=n;j++)
		{
			cin>>m0[i][j];
		}
	}
	for(int i=1;i<=n;i++)
	{
		for(int j=1;j<=n;j++)
		{
			cin>>m1[i][j];
		}
	}
	mint w;
	w=rnd()%(mod-1)+1;
//	w=1;
	for(int i=1;i<=n;i++)
	{
		for(int j=1;j<=n;j++)
		{
			g[i][j]=m0[i][j]-w*m1[i][j];
		}
	}
	matriv(n);
	for(int i=1;i<=n;i++)
	{
		for(int j=1;j<=n;j++)
		{
			g[i][j]=m1[i][j];
		}
	}
	product(n);
	for(int i=1;i<=n;i++)
	{
		for(int j=1;j<=n;j++)
		{
			a[i][j]=~r[i][j];
		}
	}
	char_poly(n);
	mint _v=det(n).inv();
	for(int i=0;i<=n;i++)sum[i]=ans[n-i]*_v;
//	for(int i=0;i<=n;i++)cout<<sum[i]<<" ";
//	cout<<endl;
	cho[0][0]=1;
	for(int i=1;i<=n;i++)
	{
		cho[i][0]=1;
		for(int j=1;j<=i;j++)
		{
			cho[i][j]=cho[i-1][j-1]+cho[i-1][j];
		}
	}
	mi[0]=1;
	for(int i=1;i<=n;i++)mi[i]=mi[i-1]*w;
	for(int i=1;i<=n;i++)ans[i]=0;
	ans[0]=sum[0];
	for(int i=1;i<=n;i++)
	{
		for(int j=0;j<=i;j++)
		{
			ans[j]+=mi[i-j]*cho[i][j]*sum[i];
		}
	}
	for(int i=0;i<=n;i++)cout<<ans[i].val()<<" ";
	return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Subtask #1:

score: 0
Time Limit Exceeded

Test #1:

score: 0
Time Limit Exceeded

input:

50
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 179093706 0 0 0 0 0 873235003 0 873022990 0 0 0 0 150372208 0 0 0 0 0 0 0 0
540031202 441544333 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 30490606 0 23238599 0 0 0 0 0 0 0 0 0 0 0 0 0...

output:


result:


Subtask #2:

score: 0
Time Limit Exceeded

Test #51:

score: 0
Time Limit Exceeded

input:

500
0 0 0 0 0 482890969 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1077401 0 0 210804413 0 508044994 0 0 0 398405351 0 0 0 0 0 0 0 171917316 0 0 0 0 0 0 0 0 0 0 0 429230725 0 0 0 0 0 45665526 0 0 0 925078893 0 0 396149045 0 0 0 595858405 0 0 0 0 0 57208...

output:


result:


Subtask #3:

score: 0
Skipped

Dependency #1:

0%