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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#209903 | #7110. Kuririn MIRACLE | PetroTarnavskyi# | TL | 18ms | 3712kb | C++17 | 1.3kb | 2023-10-10 19:14:53 | 2023-10-10 19:14:53 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define FOR(i, a, b) for(int i = (a); i < (b); i++)
#define RFOR(i, a, b) for(int i = (a) - 1; i >= (b); i--)
#define SZ(a) int(a.size())
#define ALL(a) a.begin(), a.end()
#define PB push_back
#define MP make_pair
#define F first
#define S second
typedef long long LL;
typedef vector<int> VI;
typedef pair<int, int> PII;
typedef long double db;
const int M = 400000;
const db PI = acos(-1.0);
void solve()
{
db v, r, d;
cin >> v >> r >> d;
db ans = d / v;
const db dt = ans / M;
db phiP = PI - v / (2 * r) * sqrt(3) * dt, phiPP = PI;
FOR(i, 2, M + 1)
{
db t = i * dt;
db siP = sin(phiP);
db der = -v / (2 * r) * (sqrt(3 + siP * siP) - siP);
db phi = phiPP + 2 * dt * der;
if (phi < PI / 2)
{
db a = d - 2 * r - v * t;
if (a < 0)
break;
db si = sin(phi), co = cos(phi);
db l = sqrt(4 * r * r + a * a - 4 * r * a * co);
db siBeta = 2 * r * si / l;
db beta = asin(siBeta);
if (2 * cos(phi + beta) >= co)
{
ans = min(ans, t + l / (2 * v));
break;
}
}
phiPP = phiP;
phiP = phi;
}
cout << ans << "\n";
//cerr << ans - 8.310579933902352 << "\n";
}
int main()
{
ios::sync_with_stdio(0);
cin.tie(0);
cout << fixed << setprecision(15);
int t;
cin >> t;
while (t--)
solve();
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 18ms
memory: 3712kb
input:
1 2.00 3 30.0
output:
8.310579934056235
result:
ok found '8.3105799', expected '8.3105799', error '0.0000000'
Test #2:
score: -100
Time Limit Exceeded
input:
100 8.66 6.05 71.59 8.44 8.67 82.55 4.23 9.68 24.74 6.63 9.95 7.45 1.2 7.27 97.55 2.08 2.94 31.61 8.48 5.56 20.16 7.35 5.55 52.48 1.35 8.15 51.23 3.88 9.02 72.37 7.03 1.97 57.03 1.78 4.44 93.44 5.5 6.11 52.94 1.09 9.64 69.01 1.01 3.54 16.78 1.63 4.55 44.06 5.82 5.51 5.92 5.62 2.93 76.01 4.75 4.43 73...