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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#208881#4478. Jo loves countinglhzawaAC ✓546ms37916kbC++141.5kb2023-10-09 21:43:112023-10-09 21:43:11

Judging History

你现在查看的是最新测评结果

  • [2023-10-09 21:43:11]
  • 评测
  • 测评结果:AC
  • 用时:546ms
  • 内存:37916kb
  • [2023-10-09 21:43:11]
  • 提交

answer

#include<bits/stdc++.h>
using LL = long long;
using LLL = __int128;
constexpr LL mod = 29LL << 57 | 1LL;
constexpr LL M(LL a, LL b) {
	a %= mod, b %= mod;
	return LLL(a) * LLL(b) % mod;
}
constexpr LL J(LL a, LL b) {
	a %= mod, b %= mod;
	return a >= b ? a - b : mod + a - b; 
}
constexpr LL qpow(LL a, LL b) {
	a %= mod;
	LL v = 1;
	for (; b; b >>= 1, a = M(a, a))
		if (b & 1) v = M(v, a);
	return v;
}
constexpr LL inv2 = qpow(2LL, mod - 2);
const int maxm = 1e6, maxp = 78948;
const LL maxn = LL(1e12);
int m;
int p[maxm + 1];
LL h[maxp + 1][42];
LL n;
LL ans;
void dfs(int w, LL x, LL v) {
	if (! v) return ;
	if (w > m || x * p[w] > n || x * p[w] * p[w] > n) {
		ans = (ans + M(v, M(M(n / x, n / x + 1), inv2))) % mod;
		return ;
	}
	for (int i = 0; x <= n; x *= p[w], i++) dfs(w + 1, x, M(v, h[w][i]));
}
std::bitset<maxm + 1> vis;
LL stp[100];
int main() {
	for (int i = 2; i <= maxm; i++) {
		if (! vis[i]) {
			p[++m] = i;
			LL x = 1LL * i * i;
			h[m][0] = 1LL, h[m][1] = 0LL;
			for (int j = 2; x <= maxn; j++, x *= i) {
				LL v = M(x, qpow(j, mod - 2));
				LL P = i;
				for (int k = j - 1; ~ k; k--, P = M(P, i)) v = J(v, M(P, h[m][k]));
				h[m][j] = v;
			} 
		}
		for (int j = 1; j <= m && i * p[j] <= maxm; j++) {
			vis[i * p[j]] = 1;
			if (i % p[j] == 0) break;
		}
	}
	int T;
	scanf("%d", &T);
	for (; T; T--) {
		scanf("%lld", &n);
		ans = 0;
		dfs(1, 1LL, 1LL);
		printf("%lld\n", M(ans, qpow(n, mod - 2)));
	}
	return 0;
} 

详细

Test #1:

score: 100
Accepted
time: 546ms
memory: 37916kb

input:

12
4
959139
9859
125987
209411
965585325539
213058376259
451941492387
690824608515
934002691939
1000000000000
1

output:

2
2544652967005436170
1531132428015608197
4112905740393076193
2210911161352244432
3734327250979959061
3166689602614938339
2205751131915532448
1440445581699720020
350511728590182760
1099683734530790325
1

result:

ok 12 lines