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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#207242 | #7560. Computer Network | w4p3r | ML | 1ms | 9648kb | C++20 | 2.1kb | 2023-10-08 12:19:43 | 2023-10-08 12:19:43 |
Judging History
answer
#include<bits/stdc++.h>
#define inf 2e9
#define eps 1e-6
#define FOR(i, a, b) for(int i = a; i <= b; i ++)
#define REP(i, a, b) for(int i = a; i >= b; i --)
#define pb push_back
#define fr first
#define sd second
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
inline ll read()
{
char ch = getchar();
ll s = 0, w = 1;
while (ch < '0' || ch > '9') {if (ch == '-')w = -1; ch = getchar();}
while (ch >= '0' && ch <= '9') {s = s * 10 + ch - '0'; ch = getchar();}
return s * w;
}
#define N 1000010
int ans = inf;
int n;
int a[N], b[N];
int pa[N], qa[N], ta[N];
int lowbit(const int x) {return x & (-x);}
int qry(int l, int r)
{
if (l > r)return inf;
else return min(__builtin_popcount(l), qry(l + lowbit(l), r));
}
void upd(int K)
{
FOR(i, 1, n)
{
qa[i] = qa[i] | ((pa[i] & 1) << K);
pa[i] >>= 1;
}
}
int main()
{
// freopen("C.in", "r", stdin);
// freopen("C.out", "w", stdout);
n = read();
FOR(i, 1, n)a[i] = read();
FOR(i, 1, n)b[i] = read();
FOR(i, 1, n)pa[i] = a[i];
FOR(K, 0, 30)
{
map<int, vector<int>>ma;
FOR(i, 1, n)ta[i] = pa[i];
int d = ta[1] - b[1], num = 0;
FOR(i, 1, n)num += ((ta[i] - b[i]) == d);
FOR(i, 1, n)if (qa[i])ma[(1 << K) - qa[i]].push_back(i);
// cout << "GG:" << K << endl;
// FOR(i, 1, n)cout << pa[i] << ' '; cout << endl;
// FOR(i, 1, n)cout << qa[i] << ' '; cout << endl;
int lst = 0;
for (auto [w, v] : ma)
{
if (d <= 0 && num == n)ans = min(ans, -d + K + qry(lst, w - 1));
for (int x : v)
{
if (x > 1)
{
num -= ((ta[x] - b[x]) == d);
ta[x] ++;
num += ((ta[x] - b[x]) == d);
}
else
{
ta[x] ++;
d = ta[x] - b[x], num = 0;
FOR(i, 1, n)num += ((ta[i] - b[i]) == d);
}
}
// cout << "EEEEE:" << w << " " << d << ' ' << num << endl;
// FOR(i, 1, n)cout << ta[i] << ' '; cout << endl;
lst = w;
}
if (d <= 0 && num == n)ans = min(ans, -d + K + qry(lst, (1 << K) - 1));
upd(K);
}
if (ans < inf)cout << ans << '\n';
else cout << "-1\n";
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 9648kb
input:
5 1 2 3 4 5 6 6 6 6 7
output:
9
result:
ok 1 number(s): "9"
Test #2:
score: 0
Accepted
time: 1ms
memory: 9576kb
input:
3 2 3 4 1 2 3
output:
-1
result:
ok 1 number(s): "-1"
Test #3:
score: 0
Accepted
time: 0ms
memory: 9568kb
input:
2 65536 65537 1 2
output:
32
result:
ok 1 number(s): "32"
Test #4:
score: -100
Memory Limit Exceeded
input:
1 0 28