QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#205160#7567. Joining Catsucup-team1325#TL 1ms3488kbC++172.6kb2023-10-07 15:01:482023-10-07 15:01:48

Judging History

你现在查看的是最新测评结果

  • [2023-10-07 15:01:48]
  • 评测
  • 测评结果:TL
  • 用时:1ms
  • 内存:3488kb
  • [2023-10-07 15:01:48]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;

typedef long long ll; typedef unsigned long long ull;
const int inf = 1e9; const ll llnf = 4e18;

template< class Tp > void chkmax( Tp &x , Tp y ) { x = max( x , y ); }
template< class Tp > void chkmin( Tp &x , Tp y ) { x = min( x , y ); }

void solve( ) {
	int n , k; cin >> n >> k;
	vector< int > a( n + 1 ); for( int i = 1; i <= n; i ++ ) cin >> a[i];
	vector< ll > b( k + 2 ); for( int j = 1; j <= k; j ++ ) cin >> b[j]; b[k + 1] = llnf;
	vector< ll > sa( n + 1 ); for( int i = 1; i <= n; i ++ ) sa[i] = sa[i - 1] + a[i];

	vector< vector< pair< ll , int > > > B( k + 2 );
	for( int i = k + 1; i >= 1; i -- ) {
		vector< int > ord; for( int j = i; j <= k + 1; j ++ ) ord.emplace_back( j );
		sort( ord.begin( ) , ord.end( ) , [&] ( int j1 , int j2 ) -> bool { return b[j1] < b[j2]; } );
		int minj = k + 1; for( int j = ( int ) ord.size( ) - 1; j >= 0; j -- ) chkmin( minj , ord[j] ) , B[i].emplace_back( b[ord[j]] , minj ); reverse( B[i].begin( ) , B[i].end( ) );
	}

	auto least = [&] ( int j , ll v ) -> int { return lower_bound( B[j].begin( ) , B[j].end( ) , make_pair( v , -1 ) ) -> second; } ;

	vector< vector< int > > f( n + 1 , vector< int >( n + 1 ) ) , g1( n + 1 , vector< int >( n + 1 ) ) , g2( n + 1 , vector< int >( n + 1 ) );
	for( int i = 1; i <= n; i ++ ) f[i][i] = 0 , g1[i][i] = i , g2[i][i] = i;
	for( int L = n; L >= 1; L -- ) for( int R = L + 1; R <= n; R ++ ) {
		int f1 = least( 1 , sa[R] - sa[L] ); g1[L][R] = L;
		for( int M = max( L , g1[L][R - 1] - 5 ); M <= min( R - 1 , g1[L + 1][R] + 5 ); M ++ )
			if( f[L][M] <= k ) { int curf = least( f[L][M] + 1 , sa[R] - sa[M] ); if( f1 > curf ) f1 = curf , g1[L][R] = M; }
		for( int M = max( L , g2[L][R - 1] - 5 ); M <= min( R - 1 , g2[L + 1][R] + 5 ); M ++ )
			if( f[L][M] <= k ) { int curf = least( f[L][M] + 1 , sa[R] - sa[M] ); if( f1 > curf ) f1 = curf , g1[L][R] = M; }

		int f2 = least( 1 , sa[R - 1] - sa[L - 1] ); g2[L][R] = R;
		for( int M = max( L + 1 , g2[L][R - 1] - 5 ); M <= min( R , g2[L + 1][R] + 5 ); M ++ )
			if( f[M][R] <= k ) { int curf = least( f[M][R] + 1 , sa[M - 1] - sa[L - 1] ); if( f2 > curf ) f2 = curf , g2[L][R] = M; }
		for( int M = max( L + 1 , g1[L][R - 1] - 5 ); M <= min( R , g1[L + 1][R] + 5 ); M ++ )
			if( f[M][R] <= k ) { int curf = least( f[M][R] + 1 , sa[M - 1] - sa[L - 1] ); if( f2 > curf ) f2 = curf , g2[L][R] = M; }

		f[L][R] = min( f1 , f2 );
	}
	cout << ( f[1][n] <= k ? "Yes" : "No" ) << "\n";
}

int main( ) {
	ios::sync_with_stdio( 0 ), cin.tie( 0 ), cout.tie( 0 );
	int T = 1; while( T -- ) solve( ); return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 3424kb

input:

5 2
1 1 1 1 1
2 2

output:

Yes

result:

ok answer is YES

Test #2:

score: 0
Accepted
time: 0ms
memory: 3440kb

input:

6 7
3 2 1 1 2 3
2 2 2 2 2 2 2

output:

No

result:

ok answer is NO

Test #3:

score: 0
Accepted
time: 0ms
memory: 3488kb

input:

7 4
1 2 3 4 3 2 1
3 3 3 3

output:

Yes

result:

ok answer is YES

Test #4:

score: 0
Accepted
time: 0ms
memory: 3444kb

input:

5 1
5 4 3 2 1
10

output:

Yes

result:

ok answer is YES

Test #5:

score: -100
Time Limit Exceeded

input:

5000 5000
775487425 856128884 277783434 903422359 477267301 475103384 297595527 426167697 732858986 408894759 274205836 78265305 841664344 827278645 235744961 539622829 661053351 709331224 497285040 688977639 794889854 890450616 730989757 164925481 519732355 5132018 793806705 617096813 966338860 838...

output:


result: