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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#203246 | #6744. Square | euphria# | AC ✓ | 19ms | 3492kb | C++20 | 1.2kb | 2023-10-06 16:22:57 | 2023-10-06 16:22:57 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
#define fi first
#define se second
#define endl '\n'
using ll = long long;
using ull = unsigned long long;
using PII = pair<int, int>;
using PLL = pair<ll, ll>;
const int N = 1e6 + 10;
const int M = 131;
const int INF = 0x3f3f3f3f;
const long long LNF = 0x3f3f3f3f3f3f3f3f;
const long long mod = 1e9 + 7;
ll cal(ll x){
ll res = sqrt(2ll * x);
while(res * (res + 1) < 2ll * x) res++;
while(res * (res - 1) > 2ll * x) res--;
return res;
}
void solve(){
ll x, y; cin >> x >> y;
if(x >= y){
cout << x - y << '\n'; return ;
}
ll a = cal(x), b = x - a * (a - 1) / 2 - 1;
ll c = cal(y), d = y - c * (c - 1) / 2 - 1;
//cout << a << ' ' << b << ' ' << c << ' ' << d << '\n';
ll num1 = a - b, num2 = c - d;
//cout << num1 << ' ' << num2 << '\n';
if(num1 <= num2){
cout << c - a + num2 - num1 << '\n';
}
else{
cout << c - a + 1 + b + c - d << '\n';
}
}
int main(){
ios::sync_with_stdio(false);
cin.tie(nullptr);
cout << fixed << setprecision(12);
int t = 1;
cin >> t;
while(t--){
solve();
}
return 0 - 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 3444kb
input:
2 5 1 1 5
output:
4 3
result:
ok 2 number(s): "4 3"
Test #2:
score: 0
Accepted
time: 19ms
memory: 3492kb
input:
100000 1 1 1 2 1 3 1 4 1 5 1 6 1 7 1 8 1 9 1 10 1 11 1 12 1 13 1 14 1 15 1 16 1 17 1 18 1 19 1 20 1 21 1 22 1 23 1 24 1 25 1 26 1 27 1 28 1 29 1 30 1 31 1 32 1 33 1 34 1 35 1 36 1 37 1 38 1 39 1 40 1 41 1 42 1 43 1 44 1 45 1 46 1 47 1 48 1 49 1 50 1 51 1 52 1 53 1 54 1 55 1 56 1 57 1 58 1 59 1 60 1 ...
output:
0 2 1 4 3 2 6 5 4 3 8 7 6 5 4 10 9 8 7 6 5 12 11 10 9 8 7 6 14 13 12 11 10 9 8 7 16 15 14 13 12 11 10 9 8 18 17 16 15 14 13 12 11 10 9 20 19 18 17 16 15 14 13 12 11 10 22 21 20 19 18 17 16 15 14 13 12 11 24 23 22 21 20 19 18 17 16 15 14 13 12 26 25 24 23 22 21 20 19 18 1 0 2 2 1 3 4 3 2 4 6 5 4 3 5 ...
result:
ok 100000 numbers