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#202310#6644. Red Black Gridarseny_y#RE 0ms3684kbC++233.6kb2023-10-05 21:54:272023-10-05 21:54:28

Judging History

你现在查看的是最新测评结果

  • [2023-10-05 21:54:28]
  • 评测
  • 测评结果:RE
  • 用时:0ms
  • 内存:3684kb
  • [2023-10-05 21:54:27]
  • 提交

answer

//I wrote this code 4 u today
#include <bits/stdc++.h>

template<class t> using vc = std::vector<t>;

#define nd node*
#define pnd pair<nd, nd>

//using namespace std;
typedef long long ll;

template<const ll MOD>
struct mod_mul : std::multiplies<const ll> {
    ll operator()(const ll a, const ll b) {
        return (a * b) % MOD;
    }
};


template<typename T>
inline void sort(T &a) {
    sort(a.begin(), a.end());
}

template<typename T>
inline void unique(T &a) {
    a.resize(unique(a.begin(), a.end()) - a.begin());
}

template<typename T>
inline void reverse(T &a) {
    reverse(a.begin(), a.end());
}

const ll INF = 9023372036854775808ll;
const ll MOD = 1000000007ll;

std::pair<int, int> q[4] = {{0,  1},
                            {1,  0},
                            {0,  -1},
                            {-1, 0}};

int a[3005][3005];
int max = 0;

int n, k;

int lz = 0;
bool hra = false;
bool gen(int i, int j, int dep = 0) {
    if (dep > 6) return false;
    if (j == n) ++i, j = 0;
    if (i == n) {
        return false;
    }
    if (max < k) return false;
    if (max == k) {
        for (int i = 0; i < n; ++i) {
            for (int j = 0; j < n; ++j) std::cout << (a[i][j] ? 'B' : 'R');
            std::cout << '\n';
        }
        return true;
    }
    int hru1 = 0;
    for (auto [d1, d2]: q) {
        int i1 = i + d1, j1 = j + d2;
        if (i1 != -1 && j1 != -1 && i1 != n && j1 != n) hru1 += a[i][j] != a[i1][j1];
    }
    a[i][j] ^= 1;
    int hru2 = 0;
    for (auto [d1, d2]: q) {
        int i1 = i + d1, j1 = j + d2;
        if (i1 != -1 && j1 != -1 && i1 != n && j1 != n) hru2 += a[i][j] != a[i1][j1];
    }
    a[i][j] ^= 1;
    if (hru2 < hru1) {
        max += hru2 - hru1;
        a[i][j] ^= 1;
        if (gen(i, j + 1, dep + 1)) return true;
        a[i][j] ^= 1;
        max -= hru2 - hru1;
        if (gen(i, j + 1, dep + 1)) return true;
    } else {
        if (gen(i, j + 1,dep + 1)) return true;
        a[i][j] ^= 1;
        max += hru2 - hru1;
        if (gen(i, j + 1, dep + 1)) return true;
        a[i][j] ^= 1;
        max -= hru2 - hru1;
    }
    return false;
}

bool heh(int cnt) {
    for (int i = 0; i < n; ++i) {
        for (int j = 0; j < n; ++j) {
            a[i][j] = 0;
            if ((i + j) % 2 && cnt) {
                --cnt;
                a[i][j] = 1;
            }
        }
    }
    max = 0;
    for (int i = 0; i < n; ++i) {
        for (int j = 0; j < n; ++j) {
            max += (j + 1 != n && a[i][j] != a[i][j + 1]) + (i + 1 != n && a[i][j] != a[i + 1][j]);
        }
    }
    return max >= k;
}

int main() {
    std::cin.tie(nullptr)->ios_base::sync_with_stdio(false);
    int t;
    std::cin >> t;
    while (t--) {
        max = 0;
        std::cin >> n >> k;
        int hex = 0;
        for (int i = 0; i < n; ++i) {
            for (int j = 0; j < n; ++j) {
                a[i][j] = 0;
                if (max < k && (i + j) % 2) {
                    a[i][j] = 1;
                }
                hex += i != n - 1;
                hex += j != n - 1;
            }
        }
        int lo = -1, hi = n * n + 5;
        while (hi - lo > 1) {
            int mi = (lo + hi) / 2;
            if (heh(mi)) hi = mi;
            else lo = mi;
        }
        heh(hi);
//        std::cout << max << '\n';
        if (k > hex || k == hex - 1 || k == 1) {
            std::cout << "Impossible\n";
//            gen(0, 0);
        } else {
            std::cout << "Possible\n";
            assert(gen(0, 0));
        }
    }
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3684kb

input:

2
3 6
3 1

output:

Possible
RBR
BRR
RRR
Impossible

result:

ok correct! (2 test cases)

Test #2:

score: -100
Runtime Error

input:

4424
1 0
2 4
2 3
2 2
2 1
2 0
3 12
3 11
3 10
3 9
3 8
3 7
3 6
3 5
3 4
3 3
3 2
3 1
3 0
4 24
4 23
4 22
4 21
4 20
4 19
4 18
4 17
4 16
4 15
4 14
4 13
4 12
4 11
4 10
4 9
4 8
4 7
4 6
4 5
4 4
4 3
4 2
4 1
4 0
5 40
5 39
5 38
5 37
5 36
5 35
5 34
5 33
5 32
5 31
5 30
5 29
5 28
5 27
5 26
5 25
5 24
5 23
5 22
5 21
5...

output:


result: