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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#202061#6636. Longest Strictly Increasing Sequencearseny_y#AC ✓2ms3880kbC++23887b2023-10-05 18:57:212023-10-05 18:57:22

Judging History

你现在查看的是最新测评结果

  • [2023-10-05 18:57:22]
  • 评测
  • 测评结果:AC
  • 用时:2ms
  • 内存:3880kb
  • [2023-10-05 18:57:21]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;

#define int long long


void solve(){
    int n;
    cin >> n;
    vector<int> a(n);
    for(int i=0;i<n;++i){
        cin >> a[i];
    }
    bool fl = a[0] == 1;
    vector<int> ans = {1};
    for(int i=1;i<n;++i){
        if(a[i] - a[i-1] == 0 || a[i] - a[i-1] == 1){
            if(a[i] - a[i-1] == 0){
                ans.push_back(ans.back());
            } else{
                ans.push_back(ans.back() + 1);
            }
        } else{
            fl = false;
        }
    }
    if(fl){
        cout << "YES\n";
        for(auto i:ans){
            cout << i << ' ';
        }
    } else{
        cout << "NO";
    }
    cout << "\n";
}
int32_t main(){
    cin.tie(nullptr)->sync_with_stdio(false);
    int t;
    cin >> t;
    while(t--){
        solve();
    }
}

Details

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Test #1:

score: 100
Accepted
time: 0ms
memory: 3880kb

input:

2
6
1 2 3 2 5 7
2
1 2

output:

NO
YES
1 2 

result:

ok t=2 (2 test cases)

Test #2:

score: 0
Accepted
time: 2ms
memory: 3584kb

input:

3483
5
2 3 5 1 1
2
8 1
10
1 2 3 4 4 5 6 6 6 7
10
1 1 2 2 2 2 3 4 4 5
2
5 8
3
7 10 8
5
4 1 3 3 8
10
1 2 2 2 2 2 2 3 3 3
10
1 1 2 3 4 5 5 5 5 6
9
1 2 3 4 5 5 6 6 7
7
8 8 8 8 9 1 2
5
8 9 8 3 5
10
1 2 3 3 3 3 4 4 4 5
5
7 1 6 4 3
7
5 6 8 6 1 5 5
10
1 2 2 3 4 4 4 4 5 5
3
10 4 5
3
1 5 3
5
2 8 1 2 1
3
7 8 3...

output:

NO
NO
YES
1 2 3 4 4 5 6 6 6 7 
YES
1 1 2 2 2 2 3 4 4 5 
NO
NO
NO
YES
1 2 2 2 2 2 2 3 3 3 
YES
1 1 2 3 4 5 5 5 5 6 
YES
1 2 3 4 5 5 6 6 7 
NO
NO
YES
1 2 3 3 3 3 4 4 4 5 
NO
NO
YES
1 2 2 3 4 4 4 4 5 5 
NO
NO
NO
NO
NO
NO
YES
1 1 1 2 2 3 3 4 4 
NO
NO
NO
NO
NO
NO
NO
YES
1 2 3 3 3 4 4 4 5 5 
YES
1 1 2 2 2...

result:

ok t=3483 (3483 test cases)