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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#201708 | #5148. Tree Distance | luyiming123 | WA | 1899ms | 171260kb | C++14 | 5.1kb | 2023-10-05 16:20:02 | 2023-10-05 16:20:03 |
Judging History
answer
# include <bits/stdc++.h>
using namespace std;
using i64 = long long;
const int N = 2e5 + 5;
int n;
struct edge
{
int v, w;
};
struct node
{
int u, v; i64 w;
node() {}
node(int _u, int _v, i64 _w) : u(_u), v(_v), w(_w) {}
}Eg; int sizS = 0, mindelt = 1e9;
struct Query
{
int l, id;
};
vector <Query> Q[N];
bool compare(const struct node &x, const struct node &y)
{
return x.v < y.v;
}
vector <node> Pts;
vector <edge> g[N];
vector<pair<i64, int> > L, R;
bool del[N]; int siz[N];
void find_rt(int x, int fa)
{
siz[x] = 1;
for(auto I : g[x])
{
int v = I.v;
if(v == fa || del[v]) continue;
find_rt(v, x);
siz[x] += siz[v];
int dt = abs(siz[v] - (sizS - siz[v]));
if(dt < mindelt) mindelt = dt, Eg = {x, v, I.w};
}
return;
}
void dfs(int x, int fa, i64 DIST, vector <pair <i64,int> > &A)
{
A.push_back({DIST, x});
for(auto I : g[x])
{
int v = I.v;
if(v == fa || del[v]) continue;
dfs(v, x, DIST + 1ll * I.w, A);
}
return;
}
void solve(node Ed)
{
// printf("solve : (%d,%d,%lld)\n", Ed.u, Ed.v, Ed.w);
L.clear(), R.clear();
set <pair<int, i64> > St;
dfs(Ed.u, Ed.v, 0, L);
dfs(Ed.v, Ed.u, 0, R);
del[Ed.u] = del[Ed.v] = 1;
sort(L.begin(), L.end()), sort(R.begin(), R.end());
for(int i = 0, j = 0; i < (int)L.size(); i++)
{
while(j < (int)R.size() && R[j].first <= L[i].first) St.insert({R[j].second, R[j].first}), ++j;
auto it = St.upper_bound({L[i].second, 0});
if(it != St.end()) Pts.push_back({L[i].second, (*it).first, (*it).second + L[i].first + Ed.w});
if(it != St.begin())
{
--it;
Pts.push_back({(*it).first, L[i].second, (*it).second + L[i].first + Ed.w});
}
}
St.clear();
for(int i = 0, j = 0; i < (int)R.size(); i++)
{
while(j < (int)L.size() && L[j].first <= R[i].first) St.insert({L[j].second, L[j].first}), ++j;
auto it = St.upper_bound({R[i].second, 0});
if(it != St.end()) Pts.push_back({R[i].second, (*it).first, (*it).second + R[i].first + Ed.w});
if(it != St.begin())
{
--it;
Pts.push_back({(*it).first, R[i].second, (*it).second + R[i].first + Ed.w});
}
}
int lstR = (int)R.size();
Eg = {-1, -1, -1}, sizS = (int)L.size(), mindelt = 1e9;
if(sizS >= 2) find_rt(Ed.u, Ed.v), solve(Eg);
Eg = {-1, -1, -1}, sizS = lstR, mindelt = 1e9;
if(sizS >= 2) find_rt(Ed.v, Ed.u), solve(Eg);
return;
}
struct SgT
{
struct node
{
i64 Max, tag;
}T[N << 2];
void build(int root, int l, int r)
{
T[root].Max = 1e15, T[root].tag = -1;
if(l == r) return;
int mid = (l + r) >> 1;
build(root << 1, l, mid), build(root << 1 | 1, mid + 1, r);
return;
}
void pushup(int root)
{
T[root].Max = max(T[root << 1].Max, T[root << 1 | 1].Max);
return;
}
void pushdown(int root)
{
if(T[root].tag == -1) return;
i64 tag = T[root].tag; T[root].tag = -1;
T[root << 1].Max = tag;
T[root << 1].tag = tag;
T[root << 1 | 1].Max = tag;
T[root << 1 | 1].tag = tag;
return;
}
void update(int root, int l, int r, int s, int t, i64 d)
{
if(l <= s && t <= r)
{
T[root].Max = T[root].tag = d; return;
}
pushdown(root);
int mid = (s + t) >> 1;
if(l <= mid) update(root << 1, l, r, s, mid, d);
if(r > mid) update(root << 1 | 1, l, r, mid + 1, t, d);
pushup(root);
return;
}
int query(int root, int l, int r, i64 d) // the Max x that ax > d
{
// printf("root = %d, l = %d, r = %d, d = %lld\n", root, l, r, d);
if(l == r)
{
return T[root].Max <= d ? -1 : l;
}
pushdown(root);
int mid = (l + r) >> 1;
// printf("lfMax = %lld\n", T[root << 1].Max);
return T[root << 1].Max <= d ? query(root << 1 | 1, mid + 1, r, d) : query(root << 1, l, mid, d);
}
i64 query2(int root, int l, int r, int x)
{
if(l == r) return T[root].Max;
pushdown(root);
int mid = (l + r) >> 1;
return (x <= mid) ? query2(root << 1, l, mid, x) : query2(root << 1 | 1, mid + 1, r, x);
}
void modify(int l, i64 d)
{
// printf("modify : l = %d, d = %lld\n", l, d);
// [1, l] Max(d, ai)
int pos = query(1, 1, n, d);
// printf("pos = %d\n", pos);
if(pos == -1 || pos > l) return;
update(1, pos, l, 1, n, d);
// printf("update : %d, %d, %lld\n", pos, l, d);
return;
}
}T;
i64 Ans[N];
int main(void)
{
scanf("%d", &n);
for(int i = 1; i < n; i++)
{
int u, v, w; scanf("%d%d%d", &u, &v, &w);
g[u].push_back({v, w}), g[v].push_back({u, w});
}
Eg = {-1, -1, -1}, mindelt = 1e9, sizS = n; find_rt(1, 0); solve(Eg);
for(auto &I : Pts) if(I.u > I.v) swap(I.u, I.v);
sort(Pts.begin(), Pts.end(), compare);
// printf("DEBUG Pts\n");
// for(auto I : Pts)
// {
// printf("%d %d %lld\n", I.u, I.v, I.w);
// }
int Test; scanf("%d", &Test);
for(int i = 1; i <= Test; i++)
{
int l, r; scanf("%d%d", &l, &r);
if(l != r) Q[r].push_back({l, i});
else Ans[i] = -1;
}
T.build(1, 1, n);
for(int r = 1, j = 0; r <= n; r++)
{
// printf("r = %d\n", r);
while(j < (int)Pts.size() && Pts[j].v == r) T.modify(Pts[j].u, Pts[j].w), ++j;
for(auto I : Q[r])
{
Ans[I.id] = T.query2(1, 1, n, I.l);
}
}
for(int i = 1; i <= Test; i++) printf("%lld\n", Ans[i]);
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 3ms
memory: 15976kb
input:
5 1 2 5 1 3 3 1 4 4 3 5 2 5 1 1 1 4 2 4 3 4 2 5
output:
-1 3 7 7 2
result:
ok 5 number(s): "-1 3 7 7 2"
Test #2:
score: -100
Wrong Answer
time: 1899ms
memory: 171260kb
input:
199999 31581 23211 322548833 176307 196803 690953895 34430 82902 340232856 36716 77480 466375266 7512 88480 197594480 95680 61864 679567992 19572 14126 599247796 188006 110716 817477802 160165 184035 722372640 23173 188594 490365246 54801 56250 304741654 10103 45884 643490340 127469 154479 214399361...
output:
155607258 1178569098929 5340800 5340800 5340800 576093 4366 576093 1042121690 55721881562 4366 339719 576093 576093 5340800 576093 174753344 576093 75851476 5340800 5340800 108182 5340800 527345697 576093 969964 8367049186 98193163 4366 4366 576093 4366 4366 576093 5340800 576093 5340800 4366 -1 -1 ...
result:
wrong answer 1st numbers differ - expected: '29573323', found: '155607258'