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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#201708#5148. Tree Distanceluyiming123WA 1899ms171260kbC++145.1kb2023-10-05 16:20:022023-10-05 16:20:03

Judging History

你现在查看的是最新测评结果

  • [2023-10-05 16:20:03]
  • 评测
  • 测评结果:WA
  • 用时:1899ms
  • 内存:171260kb
  • [2023-10-05 16:20:02]
  • 提交

answer

# include <bits/stdc++.h>
using namespace std;
using i64 = long long;
const int N = 2e5 + 5; 
int n;
struct edge
{
	int v, w; 
};
struct node
{
	int u, v; i64 w; 
	node() {}
	node(int _u, int _v, i64 _w) : u(_u), v(_v), w(_w) {}
}Eg; int sizS = 0, mindelt = 1e9;
struct Query
{
	int l, id;
};
vector <Query> Q[N];
bool compare(const struct node &x, const struct node &y)
{
	return x.v < y.v;
}
vector <node> Pts;
vector <edge> g[N]; 
vector<pair<i64, int> > L, R; 
bool del[N]; int siz[N];

void find_rt(int x, int fa)
{
	siz[x] = 1;
	for(auto I : g[x])
	{
		int v = I.v; 
		if(v == fa || del[v]) continue;
		find_rt(v, x); 
		siz[x] += siz[v];
		int dt = abs(siz[v] - (sizS - siz[v]));
		if(dt < mindelt) mindelt = dt, Eg = {x, v, I.w};
	}
	return;
}

void dfs(int x, int fa, i64 DIST, vector <pair <i64,int> > &A)
{
	A.push_back({DIST, x});
	for(auto I : g[x])
	{
		int v = I.v; 
		if(v == fa || del[v]) continue;
		dfs(v, x, DIST + 1ll * I.w, A);
	}
	return;
}
void solve(node Ed)
{
	// printf("solve : (%d,%d,%lld)\n", Ed.u, Ed.v, Ed.w);
	L.clear(), R.clear();
	set <pair<int, i64> > St;
	dfs(Ed.u, Ed.v, 0, L);
	dfs(Ed.v, Ed.u, 0, R);

	del[Ed.u] = del[Ed.v] = 1;
	sort(L.begin(), L.end()), sort(R.begin(), R.end());
	for(int i = 0, j = 0; i < (int)L.size(); i++)
	{
		while(j < (int)R.size() && R[j].first <= L[i].first) St.insert({R[j].second, R[j].first}), ++j;
		auto it = St.upper_bound({L[i].second, 0}); 
		if(it != St.end()) Pts.push_back({L[i].second, (*it).first, (*it).second + L[i].first + Ed.w});
		if(it != St.begin())
		{
			--it;
			Pts.push_back({(*it).first, L[i].second, (*it).second + L[i].first + Ed.w});
		}
	}
	St.clear();
	for(int i = 0, j = 0; i < (int)R.size(); i++)
	{
		while(j < (int)L.size() && L[j].first <= R[i].first) St.insert({L[j].second, L[j].first}), ++j; 
		auto it = St.upper_bound({R[i].second, 0});
		if(it != St.end()) Pts.push_back({R[i].second, (*it).first, (*it).second + R[i].first + Ed.w});
		if(it != St.begin())
		{
			--it;
			Pts.push_back({(*it).first, R[i].second, (*it).second + R[i].first + Ed.w});
		}
	}
	int lstR = (int)R.size(); 
	Eg = {-1, -1, -1}, sizS = (int)L.size(), mindelt = 1e9; 
	if(sizS >= 2) find_rt(Ed.u, Ed.v), solve(Eg); 
	Eg = {-1, -1, -1}, sizS = lstR, mindelt = 1e9; 
	if(sizS >= 2) find_rt(Ed.v, Ed.u), solve(Eg); 
	return;
}

struct SgT
{
	struct node
	{
		i64 Max, tag; 
	}T[N << 2];
	void build(int root, int l, int r)
	{
		T[root].Max = 1e15, T[root].tag = -1;
		if(l == r) return;
		int mid = (l + r) >> 1;
		build(root << 1, l, mid), build(root << 1 | 1, mid + 1, r);
		return;
	}
	void pushup(int root)
	{
		T[root].Max = max(T[root << 1].Max, T[root << 1 | 1].Max);
		return;
	}
	void pushdown(int root)
	{
		if(T[root].tag == -1) return; 
		i64 tag = T[root].tag; T[root].tag = -1;
		T[root << 1].Max = tag;
		T[root << 1].tag = tag;
		T[root << 1 | 1].Max = tag;
		T[root << 1 | 1].tag = tag;
		return;
	}
	void update(int root, int l, int r, int s, int t, i64 d)
	{
		if(l <= s && t <= r)
		{
			T[root].Max = T[root].tag = d; return;
		}
		pushdown(root);
		int mid = (s + t) >> 1;
		if(l <= mid) update(root << 1, l, r, s, mid, d);
		if(r > mid) update(root << 1 | 1, l, r, mid + 1, t, d); 
		pushup(root);
		return;
	}
	int query(int root, int l, int r, i64 d) // the Max x that ax > d
	{
		// printf("root = %d, l = %d, r = %d, d = %lld\n", root, l, r, d);
		if(l == r) 
		{
			return T[root].Max <= d ? -1 : l;
		}
		pushdown(root);
		int mid = (l + r) >> 1;
		// printf("lfMax = %lld\n", T[root << 1].Max);
		return T[root << 1].Max <= d ? query(root << 1 | 1, mid + 1, r, d) : query(root << 1, l, mid, d);
	}
	i64 query2(int root, int l, int r, int x)
	{
		if(l == r) return T[root].Max;
		pushdown(root);
		int mid = (l + r) >> 1;
		return (x <= mid) ? query2(root << 1, l, mid, x) : query2(root << 1 | 1, mid + 1, r, x);
	}
	void modify(int l, i64 d)
	{
		// printf("modify : l = %d, d = %lld\n", l, d);
		// [1, l] Max(d, ai)
		int pos = query(1, 1, n, d); 
		// printf("pos = %d\n", pos);
		if(pos == -1 || pos > l) return;
		update(1, pos, l, 1, n, d);
		// printf("update : %d, %d, %lld\n", pos, l, d);
		return;
	}
}T;
i64 Ans[N];
int main(void)
{
	scanf("%d", &n);
	for(int i = 1; i < n; i++)
	{
		int u, v, w; scanf("%d%d%d", &u, &v, &w);
		g[u].push_back({v, w}), g[v].push_back({u, w}); 
	}
	Eg = {-1, -1, -1}, mindelt = 1e9, sizS = n; find_rt(1, 0); solve(Eg); 
	for(auto &I : Pts) if(I.u > I.v) swap(I.u, I.v);
	sort(Pts.begin(), Pts.end(), compare);
	// printf("DEBUG Pts\n");
	// for(auto I : Pts) 
	// {
	// 	printf("%d %d %lld\n", I.u, I.v, I.w);
	// }
	int Test; scanf("%d", &Test);
	for(int i = 1; i <= Test; i++)
	{
		int l, r; scanf("%d%d", &l, &r); 
		if(l != r) Q[r].push_back({l, i});
		else Ans[i] = -1;
	}
	T.build(1, 1, n);
	for(int r = 1, j = 0; r <= n; r++)
	{
		// printf("r = %d\n", r);
		while(j < (int)Pts.size() && Pts[j].v == r) T.modify(Pts[j].u, Pts[j].w), ++j;
		for(auto I : Q[r]) 
		{
			Ans[I.id] = T.query2(1, 1, n, I.l);
		}
	}
	for(int i = 1; i <= Test; i++) printf("%lld\n", Ans[i]);
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 3ms
memory: 15976kb

input:

5
1 2 5
1 3 3
1 4 4
3 5 2
5
1 1
1 4
2 4
3 4
2 5

output:

-1
3
7
7
2

result:

ok 5 number(s): "-1 3 7 7 2"

Test #2:

score: -100
Wrong Answer
time: 1899ms
memory: 171260kb

input:

199999
31581 23211 322548833
176307 196803 690953895
34430 82902 340232856
36716 77480 466375266
7512 88480 197594480
95680 61864 679567992
19572 14126 599247796
188006 110716 817477802
160165 184035 722372640
23173 188594 490365246
54801 56250 304741654
10103 45884 643490340
127469 154479 214399361...

output:

155607258
1178569098929
5340800
5340800
5340800
576093
4366
576093
1042121690
55721881562
4366
339719
576093
576093
5340800
576093
174753344
576093
75851476
5340800
5340800
108182
5340800
527345697
576093
969964
8367049186
98193163
4366
4366
576093
4366
4366
576093
5340800
576093
5340800
4366
-1
-1
...

result:

wrong answer 1st numbers differ - expected: '29573323', found: '155607258'