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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#201317#5152. Circular Caramel CookieSolitaryDream#WA 1ms3948kbC++20814b2023-10-05 13:42:112023-10-05 13:42:12

Judging History

你现在查看的是最新测评结果

  • [2023-10-05 13:42:12]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:3948kb
  • [2023-10-05 13:42:11]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;

#define int long long

int s;

double mysqr(double x)
{
    if(x<0)
        return 0;
    return sqrt(x);
}

int chk(double R)
{
    int ret=0;
    for(int i=1;i<=R;i++)
    {
        
        int X=i+1>R?1:ceil(mysqr(R*R-(i+1)*(i+1))+1e-9);
        while(X-1>=1&&(X-1)*(X-1)>R*R-(i+1)*(i+1))
            X--;
        int Y=floor(mysqr(R*R-i*i));
        while((Y+1)*(Y+1)<=R*R-i*i)
            Y++;
        ret+=(Y-X+1)*i;
    }
    return ret;
}

signed main()
{
    scanf("%lld",&s);
    double l=0,r=1e5;
    // cout<<chk(2.2360679775)<<endl;
    while((r-l)/max(1.,r)>1e-9)
    {
        double mid=(l+r)/2;
        if(chk(mid)*4>=s)
            r=mid;
        else
            l=mid;
    }
    printf("%.10lf\n",r);
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 3948kb

input:

11

output:

2.2360679779

result:

ok found '2.2360680', expected '2.2360680', error '0.0000000'

Test #2:

score: 0
Accepted
time: 1ms
memory: 3876kb

input:

59

output:

5.0000000016

result:

ok found '5.0000000', expected '5.0000000', error '0.0000000'

Test #3:

score: 0
Accepted
time: 1ms
memory: 3920kb

input:

1

output:

1.4142135626

result:

ok found '1.4142136', expected '1.4142136', error '0.0000000'

Test #4:

score: 0
Accepted
time: 1ms
memory: 3868kb

input:

2

output:

1.4142135626

result:

ok found '1.4142136', expected '1.4142136', error '0.0000000'

Test #5:

score: 0
Accepted
time: 1ms
memory: 3872kb

input:

3

output:

1.4142135626

result:

ok found '1.4142136', expected '1.4142136', error '0.0000000'

Test #6:

score: -100
Wrong Answer
time: 1ms
memory: 3888kb

input:

4

output:

1.4142135626

result:

wrong answer 1st numbers differ - expected: '2.2360680', found: '1.4142136', error = '0.3675445'