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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#200785#4477. Pandaemonium Asphodelos: The First Circle (Savage)yiyiyiAC ✓572ms26632kbC++176.0kb2023-10-04 19:58:212023-10-04 19:58:21

Judging History

你现在查看的是最新测评结果

  • [2023-10-04 19:58:21]
  • 评测
  • 测评结果:AC
  • 用时:572ms
  • 内存:26632kb
  • [2023-10-04 19:58:21]
  • 提交

answer

#include<bits/stdc++.h>
#define ll long long
#define rep(i,s,t) for(int i=(s);i<=(t);i++)
#define rev_rep(i,s,t) for(int i=(s);i>=(t);i--)
using namespace std;
int ci(){
	int x; scanf("%d",&x); return x;
}

enum{N=200023};

/*
struct dt{ ll sum; };
dt NIL = (dt){0};
dt operator+(const dt&a,const dt&b){
	return (dt){a.sum+b.sum};
}
class SEG{
private:
	struct node{
		node*c[2];
		dt x,tag;
		#define lch c[0]
		#define rch c[1]
		void update(){
			x = lch->x + rch->x;
		}
	}d[N*42];
	int tot_d;
	void func(dt& x, int l, int r, dt k){
		x.sum += (r-l+1)*k.sum;
	}
	void downdate(node*e, int l,int r){
		int mid = (l+r)/2;
		if( e->lch==d ) e->lch = &(d[++tot_d]=*d);
		if( e->rch==d ) e->rch = &(d[++tot_d]=*d);
		func(e->lch->x, l,mid, e->tag);
		func(e->lch->tag, 1,1, e->tag);
		func(e->rch->x, mid+1,r, e->tag);
		func(e->rch->tag, 1,1, e->tag);
		e->tag = NIL;
	}
	void add(node*&e,int l,int r,int ql,int qr,dt x){
		if( e==d ) e = &(d[++tot_d]=*d);
		if( ql<=l && r<=qr ) return func(e->x, l,r, x), func(e->tag,1,1,x), void();
		downdate(e,l,r);
		int mid = (l+r)/2;
		( ql<=mid ? add(e->lch, l,mid ,ql,qr,x) : void());
		( mid< qr ? add(e->rch,mid+1,r,ql,qr,x) : void());
		e->update();
	}
	dt query(node*e,int l,int r,int ql,int qr){
		if( e==d ) return NIL;
		if( ql<=l && r<=qr ) return e->x;
		int mid = (l+r)/2;
		downdate(e,l,r);
		return ( ql<=mid ? query(e->lch, l,mid ,ql,qr) : NIL)
			  +( mid< qr ? query(e->rch,mid+1,r,ql,qr) : NIL);
	}
	int n;
	node*ver[5];
public:
	void init(int tot_ver,int n0){
		*d = (node){d,d,NIL,NIL};
		tot_d = 0;
		n = n0;
		fill(ver,ver+tot_ver+1,(node*)d);
	}
	void add(int x,int l,int r,dt y){
		add(ver[x],1,n,l,r,y);
	}
	dt query(int x,int l,int r){
		return query(ver[x],1,n,l,r);
	}
}seg;
*/

struct dt{ ll sum; };
dt NIL = (dt){0};
dt operator+(const dt&a,const dt&b){
	return (dt){a.sum+b.sum};
}
class SEG{
private:
	struct node{
		node*c[2];
		dt x;
		#define lch c[0]
		#define rch c[1]
		void update(){
			x = lch->x + rch->x;
		}
	}d[N*45];
	int tot_d;
	void add(node*&e,int l,int r,int ql,int qr,dt x){
		if( e==d ) e = &(d[++tot_d]=*d);
		if( ql<=l && r<=qr ) return e->x = e->x+x, void();
		int mid = (l+r)/2;
		( ql<=mid ? add(e->lch, l,mid ,ql,qr,x) : void());
		( mid< qr ? add(e->rch,mid+1,r,ql,qr,x) : void());
		e->update();
	}
	dt query(node*e,int l,int r,int ql,int qr){
		if( e==d ) return NIL;
		if( ql<=l && r<=qr ) return e->x;
		int mid = (l+r)/2;
		return ( ql<=mid ? query(e->lch, l,mid ,ql,qr) : NIL)
			  +( mid< qr ? query(e->rch,mid+1,r,ql,qr) : NIL);
	}
	node*ver[5];
	int n;
public:
	void init(int tot_ver,int n0){
		*d = (node){d,d,NIL};
		tot_d = 0;
		n = n0;
		fill(ver,ver+tot_ver+1,(node*)d);
	}
	void add(int x,int p,dt y){
		if( p>n ) return;
		if( p<1 ) return;
		add(ver[x],1,n,p,p,y);
	}
	dt query(int x,int l,int r){
		return query(ver[x],1,n,l,r);
	}
}seg;

ll c[N];

#define qwq first
#define awa second
using range = pair<int,int>;
using CH = map<range,int>;
class chtholly{
private:
	CH m;
	CH::iterator split(int p){
		CH::iterator it = m.lower_bound(range(p,0));
		if( it->qwq.qwq==p ) return it;
		it--;
		int l = it->qwq.qwq, r = it->qwq.awa, x=it->awa;
		m.erase(it);
		m[range(l,p-1)] = x;
		m[range(p,r)] = x;
		return m.find(range(p,r));
	}
public:
	void init(int n){
		m.clear();
		m[range(0,0)] = -1;
		m[range(1,n)] = 1;
		m[range(n+1,n)] = -1;
	}
	void assign(int l0,int r0, int x0){
		//printf("line %d: [%d %d] %d\n", __LINE__, l,r,x);
		CH::iterator R = split(r0+1), L = split(l0);
		for(auto it=L; it!=R; it++){
			int l = it->qwq.qwq, r = it->qwq.awa, x=it->awa;
		//printf("line %d: add %d %d %d\n", __LINE__, l,r,c[x]);
			seg.add(1,l,(dt){c[x]});
			seg.add(1,r+1,(dt){-c[x]});
		}
		m.erase(L,R);
		//printf("line %d:\n", __LINE__);
		m[range(l0,r0)] = x0;
	}
	void expand(int x, int y){
		CH::iterator it = m.lower_bound(range(x,0));
		if( it->qwq.qwq==x ) ;
		else it--;
		int colx = it->awa;

		it = m.lower_bound(range(y,0));
		if( it->qwq.qwq==y ) ;
		else it--;
		int col = it->awa;
		//printf("line %d:  col %d %d\n", __LINE__, col, colx);

		auto L = it;
		while( L->awa == col ) L--;
		L++;
		int l0 = L->qwq.qwq, r0 = it->qwq.qwq-1;
		//printf("line %d: %d %d %d\n", __LINE__, l,r,colx);
		for(it=L; it->awa==col; it++){
			int l = it->qwq.qwq, r = it->qwq.awa;
		//printf("line %d: lr %d %d %d  + %lld\n", __LINE__, l,r,x, c[col]-c[colx]);
			seg.add(1,l,(dt){c[col]-c[colx]});
			seg.add(1,r+1,(dt){-c[col]+c[colx]});
		}
		l0 = L->qwq.qwq, r0 = it->qwq.qwq-1;
		//printf("line %d: %d %d %d\n", __LINE__, l,r,colx);
		m.erase(L,it);
		m[range(l0,r0)] = colx;
	}
	int query(int x){
		auto it = m.lower_bound(range(x,0));
		if( it->qwq.qwq==x ) ;
		else it--;
		return it->awa;
	}
}ch;
#undef qwq
#undef awa

signed main(){
		//printf("line %d: %lld\n", __LINE__, sizeof seg);
	int T = ci();
	while( T-- ){
		int n = ci();
		int q = ci();
		ch.init(n);
		seg.init(2,n);
		int tot = 1;
		c[1] = 0;
		int last = 0;
		while( q-- ){
			int opt = ci();
		//printf("line %d: opt %d\n", __LINE__, opt);
			if( opt==1 ){
				int x = ci(), d = ci();
				x = ((x-1)^last)%n+1;
				d = ((d-1)^last)%((n-1)/2)+1;
				int l = max(1,x-d), r = l+2*d;
				if (r > n) l = n - 2 * d, r = n;
				c[++tot] = 0;
				ch.assign(l,r, tot);
			}else if( opt==2 ){
				int x = ci(), y = ci();
				x = ((x-1)^last)%n+1;
				y = ((y-1)^last)%n+1;
				ch.expand(x,y);
			}else if( opt==3 ){
				int x = ci(), v = ci();
				x = ((x-1)^last)%n+1;
				c[ch.query(x)] += v;
	//	printf("line %d:\n", __LINE__);
	//rep(i,1,tot) printf("%lld ", c[i]); puts("");
			}else if( opt==4 ){
				int x = ci();
				x = ((x-1)^last)%n+1;
		//printf("line %d: 4 %d\n", __LINE__, x);
				ll ans = seg.query(1,1,x).sum + c[ch.query(x)];
		//printf("line %d: %lld %lld\n", __LINE__, seg.query(1,x,x).sum , c[ch.query(x)]);
				printf("%lld\n", ans);
				last=ans&1073741823;
			}
		}
	}
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 572ms
memory: 26632kb

input:

16
16 12
3 10 16
4 2
1 1 6
1 5 6
1 9 7
1 15 7
2 2 10
2 2 13
3 1 16
4 16
4 9
4 4
100 10
3 52 336470888
2 46 95
4 98
3 3 971207868
2 6 18
2 27 38
3 68 717268783
4 69
4 30
2 2 54
100000000 100
3 23264237 374288891
1 51244358 31960832
3 66089174 543529670
3 19728747 580543238
3 68188689 490702144
1 3862...

output:

16
32
32
16
336470888
2024947539
2024947539
1989063943
1989063943
3947292200
2332517148
3947292200
2332517148
2332517148
2173902728
3154913316
3154913316
7792501902
5025837134
5196716262
7081781397
5196716262
6177726850
7031735014
7081781397
7081781397
7589349584
10153736164
9944646904
12358787010
9...

result:

ok 166382 lines