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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#200171#7523. Partially Free MealOccDreamerTL 0ms15720kbC++143.2kb2023-10-04 15:38:052023-10-04 15:38:06

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你现在查看的是最新测评结果

  • [2023-10-04 15:38:06]
  • 评测
  • 测评结果:TL
  • 用时:0ms
  • 内存:15720kb
  • [2023-10-04 15:38:05]
  • 提交

answer

//code by Emissary
#include<bits/stdc++.h>

#define fi first
#define se second
#define vc vector
#define db double
#define ll long long
#define mk make_pair
#define pb push_back
#define PI pair<int,int>
#define ull unsigned long long
#define err cerr << "   -_-   " << endl
#define debug cerr << " ------------------- " << endl

#define input(x) freopen(#x".in","r",stdin)
#define output(x) freopen(#x".out","w",stdout)

#define NO puts("No")
#define YES puts("Yes")

#define int long long

using namespace std;

namespace IO{
	inline int read(){
		int X=0, W=0; char ch=getchar();
		while(!isdigit(ch)) W|=ch=='-', ch=getchar();
		while(isdigit(ch)) X=(X<<1)+(X<<3)+(ch^48), ch=getchar();
		return W?-X:X;
	}
	inline void write(ll x){
		if(x<0) x=-x, putchar('-');
		if(x>9) write(x/10);
		putchar(x%10+'0');
	}
	inline void sprint(ll x){write(x), putchar(32);}
	inline void eprint(ll x){write(x), putchar(10);}
}using namespace IO;

const int inf = 2e9;
const int MAXN = 2e5+5;

ll res[MAXN], ans, sum[MAXN*40];

int tot, Pos[MAXN];
int n, le[MAXN], ri[MAXN];
int root[MAXN], lc[MAXN*40], rc[MAXN*40], tree[MAXN*40];

bool mark[MAXN];

struct IT{
	int x, y;
	inline bool friend operator < (const IT &x, const IT &y){
		return x.y==y.y?x.x<y.x:x.y<y.y;
	}
}a[MAXN];

inline void build(int &now, int pre, int l, int r, int pos){
	now=++tot; lc[now]=lc[pre]; rc[now]=rc[pre];
	tree[now]=tree[pre]+1; sum[now]=sum[pre]+pos;
	if(l==r) return ;
	int mid=(l+r)>>1;
	if(pos<=mid) build(lc[now],lc[pre],l,mid,pos);
	else build(rc[now],rc[pre],mid+1,r,pos);
	return ;
}

int rk, ing[MAXN];

inline void ask(int now, int l, int r){
	if(tree[now]<=rk){
		rk-=tree[now];
		ans+=sum[now];
		return ;
	}
	if(l==r){
		if(rk>=tree[now]) rk-=tree[now], ans+=1ll*tree[now]*l;
		else ans+=1ll*rk*l, rk=0;
		return ;
	}
	if(rk==0) return ;
	int mid=(l+r)>>1;
	ask(lc[now],l,mid); ask(rc[now],mid+1,r);
	return ;
}

inline int Qsum(int now, int l, int r, int L, int R){
	if(L<=l && r<=R) return tree[now];
	int mid=(l+r)>>1, res=0;
	if(L<=mid) res+=Qsum(lc[now],l,mid,L,R);
	if(R>mid) res+=Qsum(rc[now],mid+1,r,L,R);
	return res;
}

int stk[MAXN], topf;

signed main(){
	n=read(); set<int> S;
	for(int i=1;i<=n;++i) res[i]=1e18;
	for(int i=1;i<=n;++i) S.insert(i), a[i].x=read(), a[i].y=read();
	sort(a+1,a+1+n); ll g;
	for(int i=n;i>=1;--i){
		while(topf && a[stk[topf]].x+a[stk[topf]].y<a[i].x+a[i].y) --topf;
		stk[++topf]=i;
	}
	while(topf) mark[stk[topf]]=1, --topf;
	for(int i=1;i<=n;++i) g=min(a[i].x+a[i].y,g), build(root[i],root[i-1],1,inf,a[i].x);
	for(int i=1;i<=n;++i){
		int u=Qsum(root[i],1,inf,1,a[i].x+a[i].y-a[i-1].y);
		ri[i]=i; le[i]=u;
		for(int j=u;j<=min(53ll,i);++j){
			rk=j; ans=0; ask(root[i],1,inf); res[j]=min(res[j],ans+a[i].y);
			if(res[j]==ans+a[i].y) Pos[j]=i;
		}
		for(int j=1;j<u;++j) if(!ing[j]) ing[j]=i;
	}
	if(n<=3){
		for(int i=1;i<=n;++i) eprint(res[i]);
		return 0;
	}	
	for(int i=1;i<=n;++i) sprint(res[i]), sprint(Pos[i]), eprint(ing[i]);
	return 0;
}





































































详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 15720kb

input:

3
2 5
4 3
3 7

output:

7
11
16

result:

ok 3 lines

Test #2:

score: -100
Time Limit Exceeded

input:

200000
466436993 804989151
660995237 756645598
432103296 703610564
6889895 53276988
873617076 822481192
532911431 126844295
623111499 456772252
937464699 762157133
708503076 786039753
78556972 5436013
582960979 398984169
786333369 325119902
930705057 615928139
924915828 506145001
164984329 208212435...

output:


result: