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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#199082 | #5148. Tree Distance | qzez | TL | 0ms | 23588kb | C++14 | 2.3kb | 2023-10-03 20:54:32 | 2023-10-04 17:11:54 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
using ll=long long;
template<typename T>
ostream& operator << (ostream &out,const vector<T>&x){
if(x.empty())return out<<"[]";
out<<'['<<x[0];
for(int len=x.size(),i=1;i<len;i++)out<<','<<x[i];
return out<<']';
}
template<typename T>
vector<T> ary(const T *a,int l,int r){
return vector<T>{a+l,a+1+r};
}
template<typename T>
void debug(T x){
cerr<<x<<'\n';
}
template<typename T,typename ...S>
void debug(T x,S ...y){
cerr<<x<<' ',debug(y...);
}
const int N=2e5+10,M=1e6+10;
const ll INF=1e18;
int n,m;
vector<pair<int,int> >to[N];
#define v e.first
#define w e.second
int cnt,rt,siz[N],mx[N],vis[N];
void dfs1(int u,int fa=0){
cnt++;
for(auto e:to[u])if(v^fa&&!vis[v]){
dfs1(v,u);
}
}
void dfs2(int u,int fa=0){
siz[u]=1,mx[u]=0;
for(auto e:to[u])if(v^fa&&!vis[v]){
dfs2(v,u);
siz[u]+=siz[v];
mx[u]=max(mx[u],siz[v]);
}
mx[u]=max(mx[u],m-siz[u]);
if(mx[u]<mx[rt])rt=u;
}
vector<pair<int,ll> >d;
void dfs3(int u,int fa=0,ll dis=0){
d.push_back({u,dis});
for(auto e:to[u])if(v^fa)dfs3(v,u,dis+w);
}
int top,stk[N];
vector<pair<int,ll> >o[N];
vector<pair<int,int> >q[N];
ll ans[M];
void update(int x,int y,ll z){
if(x>y)swap(x,y);
o[x].push_back({y,z});
}
void insert(){
top=0;
for(int len=d.size(),i=0;i<len;i++){
for(;top;top--){
update(d[stk[top]].first,d[i].first,d[stk[top]].second+d[i].second);
if(d[stk[top]].second<=d[i].second)break;
}
stk[++top]=i;
}
}
void solve(int u){
cnt=rt=0,dfs1(u),dfs2(u),vis[u=rt]=1;
d.clear(),dfs3(u);
sort(d.begin(),d.end());
insert();
reverse(d.begin(),d.end());
insert();
for(auto e:to[u])if(!vis[v])solve(v);
}
#undef v
#undef w
ll c[N];
void add(int x,ll y){
for(;x<=n&&c[x]>y;x+=x&-x)c[x]=y;
}
ll get(int x,ll y=INF){
for(;x;x^=x&-x)y=min(y,c[x]);
return y;
}
int main(){
scanf("%d",&n);
for(int u,v,w,i=1;i<n;i++){
scanf("%d%d%d",&u,&v,&w);
to[u].push_back({v,w}),to[v].push_back({u,w});
}
mx[0]=n+1,solve(1);
scanf("%d",&m);
for(int i=1,l,r;i<=m;i++){
scanf("%d%d",&l,&r);
q[l].push_back({r,i});
}
fill(c+1,c+1+n,INF);
for(int i=n;i>=1;i--){
for(auto ot:o[i])add(ot.first,ot.second);
for(auto qt:q[i])ans[qt.second]=get(qt.first);
}
for(int i=1;i<=m;i++)printf("%lld\n",ans[i]<INF?ans[i]:-1);
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 23588kb
input:
5 1 2 5 1 3 3 1 4 4 3 5 2 5 1 1 1 4 2 4 3 4 2 5
output:
-1 3 7 7 2
result:
ok 5 number(s): "-1 3 7 7 2"
Test #2:
score: -100
Time Limit Exceeded
input:
199999 31581 23211 322548833 176307 196803 690953895 34430 82902 340232856 36716 77480 466375266 7512 88480 197594480 95680 61864 679567992 19572 14126 599247796 188006 110716 817477802 160165 184035 722372640 23173 188594 490365246 54801 56250 304741654 10103 45884 643490340 127469 154479 214399361...