#include<bits/stdc++.h>
#define rep(i, l, r) for(int i = (l); i <= (r); i ++)
#define per(i, r, l) for(int i = (r); i >= (l); i --)
#define trv(i, u, v) for(int i = head[u], v = e[i].to; i; v = e[i = e[i].nxt].to)
#define fi first
#define se second
#define all(s) s.begin(), s.end()
#define sz(s) (int)(s.size())
#define lb(s) ((s) & -(s))
#define pb push_back
using namespace std;

typedef long long ll;
typedef pair<int, int> P;
mt19937_64 hua(time(0));
template<typename T> inline bool chkmx(T &x, T y) {return x < y ? x = y, 1 : 0;}
template<typename T> inline bool chkmn(T &x, T y) {return y < x ? x = y, 1 : 0;}
template<int T> using A = array<int, T>;

inline int read() {
	int x = 0, f = 1; char c = getchar();
	for(; !isdigit(c); c = getchar()) if(c == '-')  f = 0;
	for(; isdigit(c); c = getchar()) x = x * 10 + c - '0';
	return f ? x : -x;
}
const int maxn = 1000;
int n, m, f[maxn + 5][2], g[maxn + 5], h[maxn + 5], vis[maxn + 5][2];
char s[maxn + 5][maxn + 5];
inline int nxt(int x) {return x == m ? 1 : x + 1;}
inline int prv(int x) {return x == 1 ? m : x - 1;}
inline int mex(int a, int b) {return !a || !b ? 1 + (a == 1 || b == 1) : 0;}
struct PP {
	int p[3];
	inline int& operator [] (int x) {return p[x];}
	friend PP operator + (PP a, PP b) {
		PP c;
		rep(i, 0, 2) c[i] = b[a[i]];
		return c;
	}
	void debug() {cout << p[0] << ' ' << p[1] << ' ' << p[2] << '\n';}
}mt[maxn + 5], pre[maxn + 5][2], suf[maxn + 5][2], null;
int main() {
 	//freopen("in.txt", "r", stdin);
	rep(i, 0, 2) null[i] = i;
	n = read(), m = read();
	rep(i, 1, n) cin >> s[i] + 1;
	int ans = 0;
	rep(i, 1, m) h[i] = 2;
	per(i, n, 1) {
		rep(j, 1, m) g[j] = h[j];
		if(count(s[i] + 1, s[i] + m + 1, '#') == 0) {
			if(m == 1) {
				h[1] = s[i][1] == '#' ? 2 : g[1];
				continue;
			}
			rep(j, 1, m) {
				rep(c, 0, 2) mt[j][c] = mex(c, g[j]);
			}
			pre[0][0] = pre[0][1] = suf[m + 1][0] = suf[m + 1][1] = null;
			rep(j, 1, m) {
				pre[j][0] = pre[j - 1][0] + mt[j];
				pre[j][1] = mt[j] + pre[j - 1][1];
			}
			per(j, m, 1) {
				suf[j][0] = suf[j + 1][0] + mt[j];
				suf[j][1] = mt[j] + suf[j + 1][1];
			}
			rep(j, 1, m) {
				h[j] = mex((suf[j + 1][1] + pre[j - 1][0])[2], (pre[j - 1][1] + suf[j + 1][0])[2]);
			}
		}
		else {
			rep(j, 1, m) vis[j][0] = vis[j][1] = 0;
			function<int(int)> opt[2] = {prv, nxt};
			function<int(int, int)> dfs = [&] (int u, int flg) {
				if(s[i][u] == '#') return 2;
				if(vis[u][flg]) return f[u][flg]; 
				vis[u][flg] = 1;
				f[u][flg] = mex(dfs(opt[flg](u), flg), g[u]);
				return f[u][flg];
			};
			rep(j, 1, m) {
				h[j] = (s[i][j] == '#' ? 2 : mex(dfs(prv(j), 0), dfs(nxt(j), 1)));
			}
		}
		rep(j, 1, m) if(s[i][j] == 'B') ans ^= h[j];
		//rep(j, 1, m) cout << h[j] << " \n"[j == m];
	}
	puts(ans ? "Alice" : "Bob");
	return 0;
}