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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#196114 | #2838. 2D Geometry | CSU2023# | WA | 1ms | 10036kb | C++14 | 1.2kb | 2023-10-01 12:39:48 | 2023-10-01 12:39:48 |
Judging History
answer
#include <bits/stdc++.h>
#define LL long long
const int N = 2e5 + 3;
struct point{
LL x,y;
void read(){
LL a,b;
scanf("%lld%lld",&a,&b);
x = a,y = b;
}
point(LL x = 0,LL y = 0) : x(x),y(y){}
point operator+(const point &r)const{return point(x + r.x,y + r.y);}
point operator-(const point &r)const{return point(x - r.x,y - r.y);}
LL operator*(const point&r){return x * r.y - y * r.x;}
}p[N],s[N];
int n,top;
int main()
{
// freopen("a.txt","r",stdin);
while(scanf("%d",&n) != EOF){
top = 0;
for(int i = 1;i <= n;++i){
p[i].read();
if(top >= 2 && (s[top - 1] - s[top - 2]) * (p[i] - s[top - 1]) != 0){
top -= 2;
}
else s[++top] = p[i];
// printf("GG");
}
// printf("top:%d\n",top);
if(top < 3) printf("%d\n",top);
else{
int sum = 0;
for(int i = 1;i <= n;++i){
if(((s[1] - s[2]) * (s[1] - p[i])) == 0) sum++;
}
printf("%d\n",std::max(0,n - (n - sum) * 3));
}
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 10036kb
input:
3 0 0 0 1 0 2 3 0 0 0 1 1 0 6 0 0 0 1 0 2 0 3 1 1 1 2
output:
3 0 0
result:
ok 3 lines
Test #2:
score: -100
Wrong Answer
time: 0ms
memory: 10000kb
input:
1 0 0 2 0 0 1 1 3 0 0 0 1 0 2 3 0 0 0 1 1 0 4 3 0 0 2 3 3 3 1 4 2 3 1 1 0 3 0 2 4 0 0 0 3 0 2 0 1 5 8 6 9 2 2 3 7 4 1 5 5 2 2 4 2 6 2 7 2 0 4 5 3 7 5 4 4 4 9 4 9 9 5 5 4 5 9 5 5 4 3 1 0 5 3 2 1 2 7 2 6 2 5 2 6 7 2 7 9 0 3 8 8 4 4 3 8 6 2 8 2 5 3 5 3 8 2 0 0 2 6 2 3 8 4 2 9 2 2 2 6 4 9 6 2 1 7 6 6 5 ...
output:
1 2 3 0 1 1 4 2 2 2 2 2 0 0 0 0 0 0 0 3 0 6
result:
wrong answer 12th lines differ - expected: '5', found: '2'