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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#190161#6851. Cyclically IsomorphicmasterhuangWA 18ms35000kbC++201.0kb2023-09-28 13:56:592023-09-28 13:56:59

Judging History

你现在查看的是最新测评结果

  • [2023-09-28 13:56:59]
  • 评测
  • 测评结果:WA
  • 用时:18ms
  • 内存:35000kb
  • [2023-09-28 13:56:59]
  • 提交

answer

#include<bits/stdc++.h>
#define LL long long
#define fr(x) freopen(#x".in","r",stdin);freopen(#x".out","w",stdout);
using namespace std;
inline string rds()
{
	string x="";char ch=getchar();
	while(ch<'a'||ch>'z') ch=getchar();
	while(ch>='a'&&ch<='z') x+=ch,ch=getchar();
	return x;
}
inline int rd()
{
	int x=0;char ch=getchar();
	while(ch<'0'||ch>'9') ch=getchar();
	while(ch>='0'&&ch<='9') x=x*10+ch-'0',ch=getchar();
	return x;
}
const int N=1e6+5,mod=998244353;
int T,n,m,q,pw[N],a[N];string c[N];
inline int md(int x){return x>=mod?x-mod:x;}
int main()
{
	T=rd();
	while(T--)
	{
		n=rd(),m=rd();for(int i=1;i<=n;i++) c[i]=rds();q=rd();
		for(int i=pw[0]=1;i<=m;i++) pw[i]=28ll*pw[i-1]%mod;
		for(int i=1;i<=n;i++)
		{
			int S=0;
			for(int j=0;j<m;j++) S=(S+1ll*pw[m-1-j]*(c[i][j]-'a'+1))%mod;a[i]=S;
			for(int j=0;j<m-1;j++) S=md((S-1ll*pw[m-1]*(c[i][j]-'a'+1))%mod+mod),
			a[i]=min((LL)a[i],(28ll*S+(c[i][j]-'a'+1))%mod);
		}
		while(q--) puts((a[rd()]==a[rd()])?"Yes":"No");	
	}
	return 0;
}

详细

Test #1:

score: 0
Wrong Answer
time: 18ms
memory: 35000kb

input:

5
10 10000
afcadffafeeebdfedfdafecfdbeecbcadfedcffaedecbacffedeccacfcbfbbdbcefbdefefebcbeacfbaafddbabcbfaeddaaefebbddafaaaaaedcbbdaafaffcbeeebfbbeedebabfbdbaceabfcccfedbdeafccbaffdeadbefbfeadbbedeeabbaafebaceeaeedbaddfecdefaabdbcfadadaebbdeedcfeeabbbdbcefdadbeecafcabbddddbcacadbbcddeddbbeecbdadefbaa...

output:

No
No
No
Yes
Yes
No
No
No
Yes
No
No
No
No
No
No
No
No
No
No
No
No
No
Yes
No
No
No
No
No
No
No
No
No
No
Yes
No
No
No
Yes
No
No
No
No
No
No
No
No
Yes
No
Yes
No
No
No
No
No
Yes
No
No
No
No
No
No
No
No
No
Yes
No
No
Yes
No
No
No
No
No
No
No
No
No
No
No
Yes
No
Yes
No
Yes
No
No
No
No
No
No
No
No
Yes
Yes
Ye...

result:

wrong answer 100005th lines differ - expected: 'Yes', found: 'No'