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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#190000#4423. AMPPZ in the times of diseaseberarchegas#TL 0ms0kbC++208.2kb2023-09-28 05:07:402023-09-28 05:07:42

Judging History

你现在查看的是最新测评结果

  • [2023-09-28 05:07:42]
  • 评测
  • 测评结果:TL
  • 用时:0ms
  • 内存:0kb
  • [2023-09-28 05:07:40]
  • 提交

answer

#include <bits/stdc++.h>
#include <iostream>
// #define int long long
#define ld long double
#define fastio ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define pb push_back
#define mp(a,b) make_pair(a,b)
#define ms(v,x) memset(v,x,sizeof(v))
#define all(v) v.begin(),v.end()
#define ff first
#define ss second
#define rep(i, a, b) for(int i = a; i < (b); ++i)
#define per(i, a, b) for(int i = b-1; i>=a ; i--)
#define trav(a, x) for(auto& a : x)
#define allin(a , x) for(auto a : x)
#define Unique(v) sort(all(v)),v.erase(unique(all(v)),v.end());
#define sz(v) ((int)v.size())
using namespace std;
typedef vector<int> vi;
#define y1 abacaba
//#define left oooooopss
#define db(x) cerr << #x <<" == "<<x << endl;
#define db2(x,y) cerr<<#x <<" == "<<x<<", "<<#y<<" == "<<y<<endl;
#define db3(x,y,z) cerr << #x<<" == "<<x<<", "<<#y<<" == "<<y<<", "<<#z<<" == "<<z<<endl;
typedef long long ll;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
typedef vector<ll> vl;
// std::mt19937_64 rng64((int) std::chrono::steady_clock::now().time_since_epoch().count());
std::mt19937 rng(
  
//  (int) std::chrono::steady_clock::now().time_since_epoch().count()
   1239010
);
ll cdiv(ll a, ll b) { return a/b+((a^b)>0&&a%b); } // divide a by b rounded up
ll fdiv(ll a, ll b) { return a/b-((a^b)<0&&a%b); } // divide a by b rounded down
//inline ll mod(ll n, ll m ){ ll ret = n%m; if(ret < 0) ret += m; return ret; }
ll gcd(ll a, ll b){return (b == 0LL ? a : gcd(b, a%b));}
ll exp(ll b,ll e,ll m){
    b%=m;
    ll ans = 1;
    for (; e; b = b * b % m, e /= 2)
        if (e & 1) ans = ans * b % m;
    return ans;
}
// debug:
template<class T>void print_vector(vector<T> &v){
    rep(i,0,sz(v))cout<<v[i]<<" \n"[i==sz(v)-1];
}
void dbg_out() {cerr << endl; }
template<typename Head, typename ... Tail> void dbg_out(Head H,Tail... T){
    cerr << ' ' << H;
    dbg_out(T...);
}
#ifdef LOCAL
#define dbg(...) cerr << "(" << #__VA_ARGS__ << "):", dbg_out(__VA_ARGS__), cerr << endl
#else
#define dbg(...) 42
#endif
//

//BEGIN DELAUNAY


template <class T> int sgn(T x) { return (x > 0) - (x < 0); }
template<class T>
struct Point {
	typedef Point P;
	T x, y;
	explicit Point(T x=0, T y=0) : x(x), y(y) {}
	bool operator<(P p) const { return tie(x,y) < tie(p.x,p.y); }
	bool operator==(P p) const { return tie(x,y)==tie(p.x,p.y); }
	P operator+(P p) const { return P(x+p.x, y+p.y); }
	P operator-(P p) const { return P(x-p.x, y-p.y); }
	P operator*(T d) const { return P(x*d, y*d); }
	P operator/(T d) const { return P(x/d, y/d); }
	T dot(P p) const { return x*p.x + y*p.y; }
	T cross(P p) const { return x*p.y - y*p.x; }
	T cross(P a, P b) const { return (a-*this).cross(b-*this); }
	T dist2() const { return x*x + y*y; }
	double dist() const { return sqrt((double)dist2()); }
	// angle to x-axis in interval [-pi, pi]
	double angle() const { return atan2(y, x); }
	P unit() const { return *this/dist(); } // makes dist()=1
	P perp() const { return P(-y, x); } // rotates +90 degrees
	P normal() const { return perp().unit(); }
	// returns point rotated 'a' radians ccw around the origin
	P rotate(double a) const {
		return P(x*cos(a)-y*sin(a),x*sin(a)+y*cos(a)); }
	friend ostream& operator<<(ostream& os, P p) {
		return os << "(" << p.x << "," << p.y << ")"; }
};

typedef Point<ll> P;
typedef struct Quad* Q;
typedef __int128_t lll; // (can be ll if coords are < 2e4)
P arb(LLONG_MAX,LLONG_MAX); // not equal to any other point

struct Quad {
	Q rot, o; P p = arb; bool mark;
	P& F() { return r()->p; }
	Q& r() { return rot->rot; }
	Q prev() { return rot->o->rot; }
	Q next() { return r()->prev(); }
} *H;

bool circ(P p, P a, P b, P c) { // is p in the circumcircle?
	lll p2 = p.dist2(), A = a.dist2()-p2,
	    B = b.dist2()-p2, C = c.dist2()-p2;
	return p.cross(a,b)*C + p.cross(b,c)*A + p.cross(c,a)*B > 0;
}
Q makeEdge(P orig, P dest) {
	Q r = H ? H : new Quad{new Quad{new Quad{new Quad{0}}}};
	H = r->o; r->r()->r() = r;
	rep(i,0,4) r = r->rot, r->p = arb, r->o = i & 1 ? r : r->r();
	r->p = orig; r->F() = dest;
	return r;
}
void splice(Q a, Q b) {
	swap(a->o->rot->o, b->o->rot->o); swap(a->o, b->o);
}
Q connect(Q a, Q b) {
	Q q = makeEdge(a->F(), b->p);
	splice(q, a->next());
	splice(q->r(), b);
	return q;
}

pair<Q,Q> rec(const vector<P>& s) {
	if (sz(s) <= 3) {
		Q a = makeEdge(s[0], s[1]), b = makeEdge(s[1], s.back());
		if (sz(s) == 2) return { a, a->r() };
		splice(a->r(), b);
		auto side = s[0].cross(s[1], s[2]);
		Q c = side ? connect(b, a) : 0;
		return {side < 0 ? c->r() : a, side < 0 ? c : b->r() };
	}

#define H(e) e->F(), e->p
#define valid(e) (e->F().cross(H(base)) > 0)
	Q A, B, ra, rb;
	int half = sz(s) / 2;
	tie(ra, A) = rec({all(s) - half});
	tie(B, rb) = rec({sz(s) - half + all(s)});
	while ((B->p.cross(H(A)) < 0 && (A = A->next())) ||
	       (A->p.cross(H(B)) > 0 && (B = B->r()->o)));
	Q base = connect(B->r(), A);
	if (A->p == ra->p) ra = base->r();
	if (B->p == rb->p) rb = base;

#define DEL(e, init, dir) Q e = init->dir; if (valid(e)) \
		while (circ(e->dir->F(), H(base), e->F())) { \
			Q t = e->dir; \
			splice(e, e->prev()); \
			splice(e->r(), e->r()->prev()); \
			e->o = H; H = e; e = t; \
		}
	for (;;) {
		DEL(LC, base->r(), o);  DEL(RC, base, prev());
		if (!valid(LC) && !valid(RC)) break;
		if (!valid(LC) || (valid(RC) && circ(H(RC), H(LC))))
			base = connect(RC, base->r());
		else
			base = connect(base->r(), LC->r());
	}
	return { ra, rb };
}

vector<P> triangulate(vector<P> pts) {
	sort(all(pts));  assert(unique(all(pts)) == pts.end());
	if (sz(pts) < 2) return {};
	Q e = rec(pts).first;
	vector<Q> q = {e};
	int qi = 0;
	while (e->o->F().cross(e->F(), e->p) < 0) e = e->o;
#define ADD { Q c = e; do { c->mark = 1; pts.push_back(c->p); \
	q.push_back(c->r()); c = c->next(); } while (c != e); }
	ADD; pts.clear();
	while (qi < sz(q)) if (!(e = q[qi++])->mark) ADD;
	return pts;
}

// END DELAUNAY

const int N = 1e6 + 10;
int a[N];
int pre[N][2];
int suf[N][2];

struct edge{
    int a, b;
    ll cost;
};

struct dsu{
	vi p , ps;
	dsu(int n){
		p = vi(n+1),ps = vi(n+1,1);
		rep(i,0,n+1) p[i] = i;
	}
	int find(int x){return p[x]==x?x:p[x]=find(p[x]);}
	bool join(int x , int y){
		x = find(x) , y = find(y);
		if(x == y) return 0;
		if(ps[x] > ps[y]) swap(x,y);
		p[x] = y, ps[y] += ps[x];
		return 1;
	}
};	

void solve(){
    int n , k;
    cin >> n >> k;
    map<pair<ll,ll> , int> id;
    vector<P> v;
    for(int i = 0 ; i < n; i ++){
        pair<ll,ll> a;
        cin >> a.first >> a.second;
        id[a] = i;
        v.push_back(P(a.first,a.second));
    }
    vector<P> triangles = triangulate(v);
    vector<edge> e;
    for(int i = 0 ; i < sz(triangles) ; i += 3){
        auto a = triangles[i%sz(triangles)] , b = triangles[(i+1)%sz(triangles)] , c = triangles[(i+2)%sz(triangles)];
        int id_a = id[{a.x , a.y}] , id_b = id[{b.x , b.y}] , id_c = id[{c.x , c.y}];
        e.push_back({id_a, id_b, (a - b).dist2()});
        e.push_back({id_b , id_c , (b-c).dist2()});
        e.push_back({id_a , id_c , (a-c).dist2()});
    }
    sort(all(v) , [&](P a , P b){
        return a.x < b.x;
    });
    if(sz(triangles) == 0){
        for(int i = 1 ; i < n; i ++){
            int id_a = id[{v[i-1].x , v[i-1].y}] , id_b = id[{v[i].x , v[i].y}];
            e.push_back({id_a, id_b , (v[i-1] - v[i]).dist2()});
        }
    }
    sort(all(e) , [&](edge a , edge b){
        return a.cost < b.cost;
    });

    dsu T(n);
    vector<edge> mst;
    for(auto [a,b,c] : e){
        if(T.join(a,b)){
            mst.push_back({a,b,c});
        }
    }
    while(k > 1){
        mst.pop_back();
        k--;
    }
    dsu TT(n);
    map<int,int> group;
    for(auto [a,b,c] : mst){
        TT.join(a,b);
    }
    int xp = 0;
    for(int i = 0 ; i < n; i ++){
        if(!group.count(TT.find(i)))
            group[TT.find(i)] = ++xp;
        cout << group[TT.find(i)] << " ";
    }
    cout << endl;
}

int32_t main(){
    fastio;
    int t;
    cout << "ASHDNBAIUSFIUAS" << endl;
    cin >> t;
    while(t--){
        solve();
    }

    // math -> gcd it all
    // Did you swap N,M? N=1?
}

详细

Test #1:

score: 0
Time Limit Exceeded

input:

100
100000 20
270505 510725
245104 76414
131477 992924
781607 895592
562469 622976
564354 637966
980036 112090
522903 687218
113871 977855
6615 123673
13847 347618
657794 165707
420561 183995
11367 136391
507836 694877
985069 105115
774110 486921
14319 338715
774937 118145
981468 99089
803866 491315...

output:

ASHDNBAIUSFIUAS
1 2 3 4 5 5 6 7 3 8 9 10 11 8 7 6 12 9 13 6 12 10 14 4 15 1 11 16 14 5 2 10 17 15 16 4 13 11 4 17 17 9 2 1 5 14 1 18 12 18 14 18 10 14 14 19 8 1 8 14 14 13 19 9 4 11 13 16 15 13 17 10 16 15 8 10 13 12 19 20 4 6 3 12 3 9 11 15 18 12 2 5 5 14 14 4 12 15 6 14 12 1 8 1 8 14 8 11 13 12 15...

result: