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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#189961#4432. Jungle Trailberarchegas#WA 633ms298092kbC++204.5kb2023-09-28 02:58:072023-09-28 02:58:08

Judging History

你现在查看的是最新测评结果

  • [2023-09-28 02:58:08]
  • 评测
  • 测评结果:WA
  • 用时:633ms
  • 内存:298092kb
  • [2023-09-28 02:58:07]
  • 提交

answer

#include <bits/stdc++.h>
#include <iostream>
// #define int long long
#define ld long double
#define endl "\n"
#define fastio ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define pb push_back
#define mp(a,b) make_pair(a,b)
#define ms(v,x) memset(v,x,sizeof(v))
#define all(v) v.begin(),v.end()
#define ff first
#define ss second
#define rep(i, a, b) for(int i = a; i < (b); ++i)
#define per(i, a, b) for(int i = b-1; i>=a ; i--)
#define trav(a, x) for(auto& a : x)
#define allin(a , x) for(auto a : x)
#define Unique(v) sort(all(v)),v.erase(unique(all(v)),v.end());
#define sz(v) ((int)v.size())
using namespace std;
typedef vector<int> vi;
#define y1 abacaba
//#define left oooooopss
#define db(x) cerr << #x <<" == "<<x << endl;
#define db2(x,y) cerr<<#x <<" == "<<x<<", "<<#y<<" == "<<y<<endl;
#define db3(x,y,z) cerr << #x<<" == "<<x<<", "<<#y<<" == "<<y<<", "<<#z<<" == "<<z<<endl;
typedef long long ll;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
typedef vector<ll> vl;
// std::mt19937_64 rng64((int) std::chrono::steady_clock::now().time_since_epoch().count());
std::mt19937 rng(
  
//  (int) std::chrono::steady_clock::now().time_since_epoch().count()
   1239010
);
ll cdiv(ll a, ll b) { return a/b+((a^b)>0&&a%b); } // divide a by b rounded up
ll fdiv(ll a, ll b) { return a/b-((a^b)<0&&a%b); } // divide a by b rounded down
//inline ll mod(ll n, ll m ){ ll ret = n%m; if(ret < 0) ret += m; return ret; }
ll gcd(ll a, ll b){return (b == 0LL ? a : gcd(b, a%b));}
ll exp(ll b,ll e,ll m){
    b%=m;
    ll ans = 1;
    for (; e; b = b * b % m, e /= 2)
        if (e & 1) ans = ans * b % m;
    return ans;
}
// debug:
template<class T>void print_vector(vector<T> &v){
    rep(i,0,sz(v))cout<<v[i]<<" \n"[i==sz(v)-1];
}
void dbg_out() {cerr << endl; }
template<typename Head, typename ... Tail> void dbg_out(Head H,Tail... T){
    cerr << ' ' << H;
    dbg_out(T...);
}
#ifdef LOCAL
#define dbg(...) cerr << "(" << #__VA_ARGS__ << "):", dbg_out(__VA_ARGS__), cerr << endl
#else
#define dbg(...) 42
#endif
//

const int N = 2050;
string s[N];
bool can[N][N][2][2];
bool vis[N][N][2][2];

struct nx{
    int i , j , l , r;
} nxt[N][N][2][2];

int n, m;
bool A[N] , B[N];
bool dp(int i ,int j , int l , int r){
    if(i >= n || j >= m)
        return 0;
    if(s[i][j] == '#')
        return 0;
    if(vis[i][j][l][r])
        return can[i][j][l][r];
    vis[i][j][l][r] = true;
    char p = s[i][j];
    bool flipped = l ^ r;

    if((p == '@' && !flipped) || (p == 'O' && flipped)){
        if(!l){
        bool ff = dp(i,j,1,r);
        can[i][j][l][r] |= ff;
        if(ff)
            nxt[i][j][l][r] = {i,j,1,r};
        }
        if(!r){
            bool ff = dp(i,j,l,1);
            can[i][j][l][r] |= ff;
            if(ff)
                nxt[i][j][l][r] = {i,j,l,1};
        }   
    }
    else{
        bool a = dp(i+1,j,0,r);
        bool b = dp(i,j+1,l,0);
        if(a)
            can[i][j][l][r] = 1 , nxt[i][j][l][r] = {i+1,j,0,r};
        if(b)
            can[i][j][l][r] = 1 , nxt[i][j][l][r] = {i,j+1,l,0};
    }
    if(i == n - 1&& j == m - 1 && ((p == '@' && flipped) || (p== 'O' && !flipped))){
        can[i][j][l][r] = 1 , nxt[i][j][l][r] = {-1,-1,-1,-1};
    }
    return can[i][j][l][r];
}
string ans;
void recover(int i , int j , int l , int r){
    if(i == -1 )
        return;
    if(l)
        A[i] = true;
    if(r)
        B[j] = true;
    auto [ii, jj , ll, rr] = nxt[i][j][l][r];
    if(jj > j)
        ans.push_back('P');
    else if(ii > i)
        ans.push_back('D');
    recover(ii, jj , ll,  rr);
}

void solve(){
    cin >> n >> m;
    ans.clear();
    for(int i = 0 ; i < n; i ++){
        cin >> s[i];
        A[i] = 0;
        for(int j = 0 ; j < m ; j ++)
            for(int l = 0 ; l < 2; l ++)
                for(int r = 0 ; r < 2 ; r ++)
                    can[i][j][l][r] = vis[i][j][l][r] = B[j] = 0;
    }
    bool pt = dp(0,0,0,0);
    if(pt){
        cout << "TAK" << endl;
        recover(0,0,0,0);
        for(int i = 0 ; i < n; i ++)   
            cout << (A[i] ? 'T' : 'N');
        cout << endl;
        for(int i = 0 ; i < m ; i ++)
            cout << (B[i] ? 'T' : 'N');
        cout << endl;
        cout << ans << endl;
    }
    else{
        cout << "NIE" << endl;
    }
}

int32_t main(){
    fastio;
    int t;
    cin >> t;
    while(t--){
        solve();
    }

    // math -> gcd it all
    // Did you swap N,M? N=1?
}

詳細信息

Test #1:

score: 0
Wrong Answer
time: 633ms
memory: 298092kb

input:

486
4 5
..#..
@@O@@
##@#O
..@.@
2 2
OO
OO
2 2
@@
@@
2 2
@@
#@
2 2
@O
#@
2 2
@@
OO
2 2
O#
@O
2 2
@#
#@
2 2
@.
.@
2 2
@#
.O
2 2
OO
.O
10 10
@O@O#O@@@#
OO#@#@@#OO
#@#@#O##O@
OO##@@O#@O
O##@@#@O#@
OO@OO@@@O@
@O#@#@O#@O
@OOOOO@##.
O@OOO##O@@
OO@@OOOO#@
10 10
@@#OOO#O@@
#@@OO@@.O@
#.O@@O#@@O
OO@@#O@#O@
.#...

output:

TAK
NNTN
NTNTT
PDPPPDD
TAK
NN
NN
PD
TAK
NN
TT
PD
TAK
NN
TT
PD
TAK
NN
TT
PD
TAK
NT
TT
PD
TAK
NN
TN
DP
NIE
TAK
NN
TT
PD
TAK
NN
TN
DP
TAK
NN
NN
PD
NIE
TAK
NNNTTNNNNN
TTTNNTTNTT
PDPPPPPPPDDDDDPDDD
TAK
NNNTTNNNNN
NNTNTTNTTN
PPDDDPPDPDPPDDPDPD
TAK
NNNNTNNNNT
NNNTTNTTTT
PPDDPPPDPDPPDDPDDD
TAK
NNNNTNTNNT
NT...

result:

wrong answer you dead (test case 5)