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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#188872#4886. Best SunDualqwqWA 163ms5848kbC++236.2kb2023-09-26 15:43:022023-09-26 15:43:02

Judging History

你现在查看的是最新测评结果

  • [2023-09-26 15:43:02]
  • 评测
  • 测评结果:WA
  • 用时:163ms
  • 内存:5848kb
  • [2023-09-26 15:43:02]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
const int N = 3e2 + 5;
typedef long long i64;
typedef double db;
typedef pair<int,int> pii;
#define FI first
#define SE second
const db eps = 1e-9,PI = acos(-1.0);
mt19937 Rnd(114514);
struct Vec {
	int x,y;
	Vec(){}
	Vec(const int _x,const int _y):x(_x),y(_y){}
	Vec operator + (const Vec &rhs) const { return Vec(x + rhs.x,y + rhs.y);}
	Vec operator - (const Vec &rhs) const { return Vec(x - rhs.x,y - rhs.y);}
	i64 operator * (const Vec &rhs) const { return 1ll * x * rhs.y - 1ll * y * rhs.x;}
};
Vec O(0,0);
bool Cmp(const Vec &x,const Vec &y) { return (x.y == y.y) ? (x.x < y.x) : (x.y < y.y);}
i64 Dot(const Vec &A,const Vec &B) { return 1ll * A.x * B.x + 1ll * A.y * B.y;}
db Distance(const Vec &A,const Vec &B) { return sqrt(Dot(A - B,A - B));}
db Angle(const Vec &A) { 
	db tmp = atan2(A.y,A.x);
	// if(tmp < -eps) return tmp + PI * 2;
	// else 
	return tmp;
}
db Area(const Vec &A,const Vec &B,const Vec &C) { return 0.5 * fabs(A * B + B * C + C * A);}
bool Equal(const db &A,const db &B) { return fabs(A - B) < eps;}
db Angle(const Vec &A,const Vec &B,const Vec &C) { // jiao ABC
	return Angle(A - B) - Angle(C - B);
}
bool InSegment(const Vec &A,const Vec &B,const Vec &p) { return Equal(Distance(A,p) + Distance(p,B),Distance(A,B));}
bool InTriangle(const Vec &A,const Vec &B,const Vec &C,const Vec &p) {
	return Equal(Area(A,B,p) + Area(B,C,p) + Area(C,A,p),Area(A,B,C));
}
Vec Rotate(const Vec &A) { return Vec(-A.y,A.x);}
int sgn(const Vec &A) { return A.y > 0 || A.y == 0 && A.x > 0;}
Vec p[N];
int n;
int V[N][N],VL[N][N]; 
db sum[N][N];
bool NeedAdd(const Vec &A,const Vec &B,const Vec &p) {
	if(!InTriangle(O,A,B,p)) return 0;
	if(InSegment(O,A,p)) return 0;
	return 1;
}
inline bool CheckTriangle(int i,int j,int k) {
	
	if(InSegment(p[i],p[j],p[k])) return VL[i][j] <= 1;
	if(InSegment(p[i],p[k],p[j])) return VL[i][k] <= 1;
	if(InSegment(p[j],p[k],p[i])) return VL[j][k] <= 1;
	if(VL[i][j] || VL[j][k] || VL[i][k]) return false;
	// if(i == 1 && j == 1 && k == 4) puts("done");
	int num = 0;
	int v1 = V[i][j] - NeedAdd(p[i],p[j],p[k]);
	int v2 = V[j][k] - NeedAdd(p[j],p[k],p[i]);
	int v3 = V[k][i] - NeedAdd(p[k],p[i],p[j]);
	if(p[i] * p[j] > 0) num += v1; else if(p[i] * p[j] < 0) num -= v1;
	if(p[j] * p[k] > 0) num += v2; else if(p[j] * p[k] < 0) num -= v2;
	if(p[k] * p[i] > 0) num += v3; else if(p[k] * p[i] < 0) num -= v3;
	// int brt = 0;
	// for(int t = 1;t <= n;t++)
	// 	if(i != t && j != t && k != t && InTriangle(p[i],p[j],p[k],p[t])) ++brt;
	// if(abs(num) != brt) {
	// 	printf("%d %d %d\n",i,j,k);
	// 	printf("p[%d]:%d,%d\n",i,p[i].x,p[i].y);
	// 	printf("p[%d]:%d,%d\n",j,p[j].x,p[j].y);
	// 	printf("p[%d]:%d,%d\n",k,p[k].x,p[k].y);
	// 	printf("%d %d %d\n",v1,v2,v3);
	// 	exit(0);
	// }
	// // assert(num % 2 == 0);
	// assert(abs(num) == brt);
	return num == 0;
}

struct Line {
	int s,t,type;
	Vec v;
	Line(){}
	Line(const int _s,const int _t,const int _type,const Vec _v):
		s(_s),t(_t),type(_type),v(_v){}
	bool operator < (const Line &rhs) const { 
		// return Angle(v) < Angle(rhs.v);
		int t1 = sgn(this->v),t2 = sgn(rhs.v);
		if(t1 != t2) return t1 > t2;
		i64 val = this->v * rhs.v;
		// db val = Angle(this->v) - Angle(rhs.v);
		if(val) return val > 0;
		else return type < rhs.type;
	}
};
Line L[N * N];
int tot;
inline void Init() {
	cin >> n;
	for(int i = 1;i <= n;i++) cin >> p[i].x >> p[i].y;
	sort(p + 1,p + n + 1,Cmp);
	for(int i = 1;i <= n;i++) 
		for(int j = 1;j <= n;j++)
			for(int k = 1;k <= n;k++) {
				if(k == i || k == j) continue;	
				if(!InTriangle(p[i],O,p[j],p[k])) continue;

				// if(InSegment(O,p[i],p[k]) || (!InSegment(O,p[j],p[k]) && !InSegment(O,p[i],p[k])))
				// // if(InSegment(p[i],p[j],p[k]) || (!InSegment(O,p[i],p[k]) && !InSegment(O,p[j],p[k])))
				if(NeedAdd(p[i],p[j],p[k]))
					++V[i][j];
				if(InSegment(p[i],p[j],p[k])) ++VL[i][j];
			}
	// printf("V,VL[1,2]:%d,%d\n",V[1][2],VL[1][2]);
	// printf("V,VL[3,1]:%d,%d\n",V[3][1],VL[3][1]);
	// printf("V,VL[2,3]:%d,%d\n",V[2][3],VL[2][3]);
	for(int i = 1;i <= n;i++)
		for(int j = 1;j <= n;j++)
			for(int k = 1;k <= n;k++) {
				if(k == i || k == j) continue;
				if((p[k] - p[i]) * (p[j] - p[i]) <= 0) continue;
				if(Dot(p[j] - p[i],p[k] - p[i]) >= 0 && Dot(p[i] - p[j],p[k] - p[j]) > 0)
					sum[i][j] += min(Distance(p[k],p[i]),Distance(p[k],p[j]));
			}
	for(int i = 1;i <= n;i++)
		for(int j = 1;j <= n;j++) {
			if(i == j) continue;
			sum[i][j] += Distance(p[i],p[j]);
			L[++tot] = Line(i,j,0,p[j] - p[i]);
			L[++tot] = Line(i,j,1,Rotate(p[j] - p[i]));
		}
	// printf("Angle(1,2):%.6lf\n",Angle(p[2] - p[1]));
	// printf("Angle(1,3):%.6lf\n",Angle(p[3] - p[1]));
	// printf("Angle(2,1):%.6lf\n",Angle(p[1] - p[2]));
	// printf("Angle(2,3):%.6lf\n",Angle(p[3] - p[2]));
	// printf("Angle(3,1):%.6lf\n",Angle(p[1] - p[3]));
	// printf("Angle(3,2):%.6lf\n",Angle(p[2] - p[3]));

	sort(L + 1,L + tot + 1);
}

db dp[N];
inline bool Check(int st,db mid) {
	for(int i = 1;i <= n;i++) dp[i] = -1e15;
	dp[st] = -eps;
	// printf("Check:%d\n",st);
	for(int i = 1;i <= tot;i++) {
		int s = L[i].s,t = L[i].t,tp = L[i].type;
		// printf("L:%d,%d,%d\n",s,t,tp);
		// printf("CheckTriangle[%d,%d,%d]:%d\n",st,s,t,CheckTriangle(st,s,t));
		if(tp == 1) {
			if(s >= st) dp[s] -= mid * Distance(p[s],p[t]);
		} else 
			if(s >= st && t >= st && CheckTriangle(st,s,t))
				dp[t] = max(dp[t],dp[s] + Area(p[st],p[s],p[t]) - mid * sum[s][t]); 
	}
	// for(int i = 1;i <= n;i++) printf("dp[%d]=%.12lf\n",i,dp[i]);
	return dp[st] > eps;
}
inline void Clr(int n) {
	for(int i = 1;i <= n;i++) for(int j = 1;j <= n;j++) V[i][j] = VL[i][j] = sum[i][j] = 0;
	tot = 0;
}
inline void work() {
	Clr(n);
	Init();
	static int perm[N];
	for(int i = 1;i <= n;i++) perm[i] = i;
	shuffle(perm + 1,perm + n + 1,Rnd);
	db ans = 0;
	// printf("Check:%d\n",Check(1,0));
	for(int i = 1;i <= n;i++) 
		if(Check(perm[i],ans)) {
			db lef = ans,rig = 1e6;
			for(int _ = 1;_ <= 60;_++) {
				db mid = (lef + rig) / 2;
				if(Check(perm[i],mid)) lef = mid;
				else rig = mid;
			}
			ans = lef;
		}
	printf("%.10lf\n",ans);
}
int main() {
	int T;
	cin >> T;
	while(T--) work();
	return 0;
}
/*
1
4
0 -5
5 -5
0 -2
-3 2
*/

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 3824kb

input:

4
3
-1 -1
1 -1
0 1
4
0 0
10 0
0 10
8 1
5
2 0
-2 0
1 1
-1 1
0 3
8
4 4
-4 4
4 -4
-4 -4
5 6
-6 5
-5 -6
6 -5

output:

0.3090169941
1.2368614276
0.2711375413
1.5631002094

result:

ok 4 numbers

Test #2:

score: 0
Accepted
time: 94ms
memory: 3800kb

input:

10000
3
702262 828158
-350821 -420883
-466450 13507
3
28647 -193498
126436 -864937
-287798 738936
3
270358 -269567
745815 -485408
834083 677952
3
-2036 -403634
742978 -263774
975937 -609237
3
584248 -472620
482016 -356760
284902 903881
3
-292004 504925
-935756 373793
-781101 -434659
3
-858513 684433...

output:

85789.0873983536
18268.5193616721
102489.9883902622
66685.7544280802
18674.6579374143
106468.9651319721
14427.0246510711
29966.2453025429
143547.7510835874
13097.1756881261
162410.1683169808
72070.9324178747
29369.9926278869
52867.2944311017
90314.3083467567
99775.9271965681
144449.7053083692
64406....

result:

ok 10000 numbers

Test #3:

score: 0
Accepted
time: 100ms
memory: 3616kb

input:

10000
3
2 2
2 -2
-5 -5
3
-3 5
5 -4
2 -2
3
-4 1
2 -2
-4 4
3
1 -4
2 1
-4 1
3
2 1
-1 1
-3 3
3
4 5
3 -1
-3 -3
3
1 5
5 0
5 -1
3
2 -3
-5 -3
5 3
3
-4 4
0 -5
5 4
3
2 -3
5 0
2 -5
3
-2 -3
5 -3
5 4
3
-1 4
4 4
4 3
3
5 3
-1 4
2 -1
3
2 -3
4 3
-4 3
3
0 4
-2 -2
-1 -3
3
-2 0
-4 -2
4 2
3
-3 -1
3 1
1 -3
3
2 -5
2 3
-4 ...

output:

0.6507007010
0.2268090702
0.4946825661
0.8255326311
0.2675324745
0.7379284563
0.1368529466
0.8277457955
1.3896281203
0.2484761663
1.0251262658
0.2252451214
0.7981688504
1.0521776337
0.2700907566
0.2210280034
0.6549291473
1.0657925458
0.1207361881
0.1727212123
0.4458825284
0.2484761663
0.1224985769
0...

result:

ok 10000 numbers

Test #4:

score: 0
Accepted
time: 154ms
memory: 3904kb

input:

5625
4
-405394 -381883
602267 -335687
-620806 984110
271283 531233
4
196903 -993060
290851 358123
-890076 -717709
-681138 209884
4
-849589 607722
-21517 -586295
208561 -220953
924518 622983
4
-832186 456270
289934 43656
636006 339718
188963 113907
4
-305762 -872205
-520125 368722
-774548 984204
4245...

output:

232625.0042744304
268175.8269859639
159589.3236305173
60440.7530425985
133893.1234363519
63201.9907486268
167697.6634061348
129470.0132843163
126903.8540728102
106643.9712630971
131692.3112279047
100421.0550162125
148490.2748179024
68842.2423098231
241376.1911161292
303904.5464356643
77462.333614780...

result:

ok 5625 numbers

Test #5:

score: -100
Wrong Answer
time: 163ms
memory: 5848kb

input:

5625
4
-2 -1
4 -5
-2 -4
-4 -4
4
-1 -5
4 4
2 -5
-5 1
4
-3 -4
-3 -1
-5 -1
4 -2
4
-2 4
-4 1
-1 -1
5 -4
4
-3 -5
-1 4
5 -1
3 5
4
-4 -2
1 4
-1 1
3 4
4
-5 3
-3 3
5 -4
-1 4
4
1 2
2 -5
1 0
0 -3
4
-5 -4
2 -3
5 3
-3 2
4
2 -2
-4 3
1 -4
-5 -5
4
-3 5
-2 4
1 3
1 -4
4
0 -5
5 -5
0 -2
-3 2
4
0 5
-1 -4
-2 0
4 -1
4
4 -...

output:

0.4919682067
1.6080239363
0.6764635634
0.8146821264
1.5727954032
0.2020448015
0.4423673057
0.3055832122
1.5089069099
1.3227875237
0.5218559491
0.3982804502
1.2194946257
1.1774912552
1.3951026929
1.0737731259
0.7540897904
0.6075591083
1.4373192211
0.9671123463
0.9534878419
1.4836242816
1.2273730216
0...

result:

wrong answer 60th numbers differ - expected: '0.6232773', found: '0.4397193', error = '0.1835580'