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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#188570 | #7239. Triangle | ucup-team004 | WA | 1ms | 3968kb | C++20 | 1.2kb | 2023-09-26 01:28:24 | 2023-09-26 01:28:25 |
Judging History
answer
#include <bits/stdc++.h>
using i64 = long long;
constexpr int N = 1E5;
void solve() {
int n, c;
std::cin >> n >> c;
std::bitset<N + 1> a{}, b{};
for (int i = 0; i < n; i++) {
int x;
std::cin >> x;
a[x] = b[N - x] = 1;
}
double ans = -1;
for (int s = 2 * c, z = s; s >= 3; s--) {
while (z > 0 && (z >= s || !a[z])) {
z--;
}
if (2 * z >= s) {
a[z] = b[N - z] = 0;
auto v = a & (s < N ? b >> (N - s) : b << (s - N));
int x = v._Find_next(s - z - 1);
int y = s - x;
if (x < y && y < z) {
double p = 0.5 * (x + y + z);
double area = std::sqrt(p * (p - x) * (p - y) * (p - z));
if (ans < 0 || ans > area) {
ans = area;
}
}
a[z] = b[N - z] = 1;
}
}
std::cout << ans << "\n";
}
int main() {
std::ios::sync_with_stdio(false);
std::cin.tie(nullptr);
std::cout << std::fixed << std::setprecision(10);
int t;
std::cin >> t;
while (t--) {
solve();
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 3968kb
input:
4 3 3 1 2 3 4 4 1 2 3 4 3 11 5 7 11 6 11 5 7 8 9 10 11
output:
-1.0000000000 2.9047375097 12.9687123493 12.9687123493
result:
ok 4 numbers
Test #2:
score: -100
Wrong Answer
time: 1ms
memory: 3904kb
input:
20 5 20 15 20 11 17 18 5 20 12 18 13 20 15 5 20 12 10 14 18 16 5 20 18 16 15 11 14 5 20 18 12 11 20 14 5 20 20 15 10 16 12 5 20 12 10 15 13 17 5 20 18 15 13 20 12 5 20 16 18 20 10 14 5 20 11 15 16 13 18 5 20 11 13 16 14 17 5 20 20 14 11 13 16 5 20 16 11 15 13 18 5 20 11 15 13 20 14 5 20 16 10 13 20 ...
output:
81.3879597975 74.9061913329 56.5685424949 76.9801110677 56.7180526817 45.5960524607 58.9358761706 74.9061913329 64.9923072371 70.9929573972 71.4995629357 66.0000000000 70.9929573972 66.0000000000 31.9755766172 89.9777750336 56.1465715783 71.4995629357 42.4264068712 82.6498638837
result:
wrong answer 1st numbers differ - expected: '81.2599994', found: '81.3879598', error = '0.0015747'