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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#188334#5148. Tree DistancezhouhuanyiWA 394ms79704kbC++142.9kb2023-09-25 19:07:562023-09-29 19:17:53

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  • [2023-09-29 19:17:53]
  • 管理员手动重测该提交记录
  • 测评结果:WA
  • 用时:394ms
  • 内存:79704kb
  • [2023-09-25 19:07:56]
  • 提交

answer

#include<iostream>
#include<cstdio>
#include<vector>
#include<algorithm>
#define N 200000
using namespace std;
const int inf=(int)(1e9);
const long long INF=(long long)(1e18);
int read()
{
	char c=0;
	int sum=0;
	while (c<'0'||c>'9') c=getchar();
	while ('0'<=c&&c<='9') sum=sum*10+c-'0',c=getchar();
	return sum;
}
struct reads
{
	int num;
	long long data;
	bool operator < (const reads &t)const
	{
		return num<t.num;	
	}
};
reads tong[N+1];
int n,q,rt,leng,length,smz,sz[N+1],szt[N+1],maxp[N+1],dque[N+1],top;
long long dis[N+1],ans[N+1],c[N+1];
vector<reads>E[N+1];
vector<reads>p[N+1];
vector<reads>v[N+1];
bool used[N+1],vis[N+1];
void add(int x,int y,int z)
{
	E[x].push_back((reads){y,z}),E[y].push_back((reads){x,z});
	return;
}
void get_rt(int x)
{
	vis[x]=sz[x]=1,maxp[x]=0;
	for (int i=0;i<E[x].size();++i)
		if (!used[E[x][i].num]&&!vis[E[x][i].num])
			get_rt(E[x][i].num),sz[x]+=sz[E[x][i].num],maxp[x]=max(maxp[x],sz[E[x][i].num]);
	maxp[x]=max(maxp[x],smz-sz[x]);
	if (maxp[x]<maxp[rt]) rt=x;
	vis[x]=0;
	return;
}
void dfs(int x)
{
	vis[x]=szt[x]=1,tong[++length]=(reads){x,dis[x]};
	for (int i=0;i<E[x].size();++i)
		if (!used[E[x][i].num]&&!vis[E[x][i].num])
			dis[E[x][i].num]=dis[x]+E[x][i].data,dfs(E[x][i].num),szt[x]+=szt[E[x][i].num];	
	return;
}
void solve(int x)
{
	used[x]=1,dis[x]=0,tong[length=1]=(reads){x,0};
	for (int i=0;i<E[x].size();++i)
		if (!used[E[x][i].num])
			dis[E[x][i].num]=E[x][i].data,dfs(E[x][i].num);
	sort(tong+1,tong+length+1),top=0;
	for (int i=1;i<=length;++i)
	{
		while (top&&tong[dque[top]].data>=tong[i].data) top--;
		if (top) p[tong[i].num].push_back((reads){tong[dque[top]].num,tong[dque[top]].data+tong[i].data});
		dque[++top]=i;
	}
	top=0;
	for (int i=length;i>=1;--i)
	{
		while (top&&tong[dque[top]].data>tong[i].data) top--;
		if (top) p[tong[dque[top]].num].push_back((reads){tong[i].num,tong[i].data+tong[dque[top]].data});
		dque[++top]=i;
	}
	for (int i=0;i<E[x].size();++i)
		if (!used[E[x][i].num])
			smz=szt[E[x][i].num],rt=0,get_rt(E[x][i].num),solve(rt);
	return;
}
int lowbit(int x)
{
	return x&(-x);
}
void add(int x,long long d)
{
	for (;x<=n;x+=lowbit(x)) c[x]=min(c[x],d);
	return;
}
long long query(int x)
{
	long long res=INF;
	for (;x>=1;x-=lowbit(x)) res=min(res,c[x]);
	return res;
}
int main()
{
	int x,y,z,l,r;
	n=read(),maxp[0]=inf;
	for (int i=1;i<=n;++i) c[i]=INF;
	for (int i=1;i<=n-1;++i) x=read(),y=read(),z=read(),add(x,y,z);
	q=read();
	for (int i=1;i<=q;++i)
	{
		l=read(),r=read();
		if (l==r) ans[i]=-1;
		else v[r].push_back((reads){l,i});
	}
	smz=n,get_rt(1),solve(rt);
	for (int i=1;i<=n;++i)
	{
		for (int j=0;j<p[i].size();++j) add(n-p[i][j].num+1,p[i][j].data);
		for (int j=0;j<v[i].size();++j) ans[v[i][j].data]=query(n-v[i][j].num+1);
	}
	for (int i=1;i<=q;++i) printf("%lld\n",ans[i]);
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 25896kb

input:

5
1 2 5
1 3 3
1 4 4
3 5 2
5
1 1
1 4
2 4
3 4
2 5

output:

-1
3
7
7
2

result:

ok 5 number(s): "-1 3 7 7 2"

Test #2:

score: -100
Wrong Answer
time: 394ms
memory: 79704kb

input:

199999
31581 23211 322548833
176307 196803 690953895
34430 82902 340232856
36716 77480 466375266
7512 88480 197594480
95680 61864 679567992
19572 14126 599247796
188006 110716 817477802
160165 184035 722372640
23173 188594 490365246
54801 56250 304741654
10103 45884 643490340
127469 154479 214399361...

output:


result:

wrong answer Answer contains longer sequence [length = 999999], but output contains 0 elements