#include<cstdio>
#include<algorithm>
#include<cmath>
#include<cstring>
#include<cctype>

#define y0 _y0
#define y1 _y1

using namespace std;

inline int read(){
	int x=0,f=0; char c=getchar();
	while(!isdigit(c)) f|=c=='-',c=getchar();
	while(isdigit(c)) x=x*10+(c^'0'),c=getchar();
	return f?-x:x;
}

const int maxn=100010;
const double eps=1e-8;
const double pi=acos(-1);

int cir[maxn];
struct Point{
	double x,y;
	bool operator<(const Point &p)const{
		return atan2(y,x)<atan2(p.y,p.x);
	}
};
typedef Point Line;


inline double dot(Point p,Point q){ return p.x*q.x+p.y*q.y; }
inline double len(Point p){ return sqrt(dot(p,p)); }

inline double cross(Point p,Point q){ return p.x*q.y-p.y*q.x; }

Line line[maxn];

int R,F,N;

Line get1_line(double x,double y){
	Line res=(Line){x,y};
	int l=1,r=F;
	while(l<r){
		int mid=l+r+1>>1;
		if(res<line[mid]) r=mid-1;
		else l=mid;
	}
	if(l==1&&res<line[l]) return line[F];
	return line[l];
}

Line get2_line(double x,double y){
	Line res=(Line){x,y};
	int l=1,r=F;
	while(l<r){
		int mid=l+r+1>>1;
		if(res<line[mid]) r=mid-1;
		else l=mid;
	}
	if(l<F) return line[l+1];
	if(line[F]<res) return line[1];
	return line[l];
}

inline double check(Line l,Point p){
	long double t=atan2(p.y,p.x)-atan2(l.y,l.x);
	if(t<0) t+=2*pi;
	if(t>=2*pi) t-=2*pi;
	if(t>pi) t=2*pi-t;
	
	double ll=len(p);
	
//	printf("ll = %lf\n",ll);
	
	int pp=lower_bound(cir+1,cir+R+1,ll)-cir,qq=0;
	if(pp==R+1) {
		pp=R,qq=1;
	} else {
		if(pp==1) qq=R;
		else qq=pp-1;
	}
	//if(pp<=R) qq=pp-1;
	//if(qq==0) qq=1;
	//if(pp==R+1) pp=R;
	
	
	//printf("%d %d\n",pp,qq);
	
	double d1=sqrt((ll*cos(t)-cir[pp])*(ll*cos(t)-cir[pp])+ll*ll*sin(t)*sin(t));
	double d2=sqrt((ll*cos(t)-cir[qq])*(ll*cos(t)-cir[qq])+ll*ll*sin(t)*sin(t));
	
	return min(d1,d2);
	
}

int main(){
	R=read(),F=read(),N=read();
	
	for(int i=1;i<=R;i++) cir[i]=read();
	sort(cir+1,cir+R+1);
	
	for(int i=1;i<=F;i++) line[i].x=read(),line[i].y=read();
	sort(line+1,line+F+1);
	
	while(N--){
		int x=read(),y=read();
		Point p={x,y};
		
		int tmp=lower_bound(line+1,line+F+1,p)-line;
		Line l1=line[min(tmp,F)],l2=line[max(tmp-1,1)];
//		Line l1=get1_line(x,y),l2=get2_line(x,y);
		
		printf("%.12lf\n",min(check(l1,p),min(min(check(line[F],p),check(line[1],p)),check(l2,p))));
		
	}
}
/*
3 7 5
2
4
7
8 4
2 8
-1 5
-7 2
-4 -4
1 -8
6 -3
3 -1
8 1
2 6
-5 2
-1 -1
*/