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#186497#5407. 基础图论练习题NGC54570 0ms0kbC++175.0kb2023-09-23 23:51:072023-09-23 23:51:09

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你现在查看的是最新测评结果

  • [2023-09-23 23:51:09]
  • 评测
  • 测评结果:0
  • 用时:0ms
  • 内存:0kb
  • [2023-09-23 23:51:07]
  • 提交

answer

/* 陽炎は黄泉に待たむと。*/

#include <bits/stdc++.h>
using namespace std;

#define inl inline
constexpr int BUF = 1<<17;
char ibuf[BUF], obuf[BUF], *__st, *__ed, *__pt;
inl void buffer () { __st = ibuf,
	__ed = ibuf + fread (ibuf, 1, BUF, stdin); }
inl void flush () {
	fwrite (obuf, 1, __pt - obuf, stdout);
	__pt = obuf; }
inl char getc () {
	return __st == __ed && (buffer (),
		__st == __ed) ? EOF : *__st++; }
inl void putc (char c) {
	if (__pt == obuf + BUF) flush ();
	*__pt++ = c; }
template <typename T> inl bool read (T &x) {
	int f = 1; static char c = getc (); x = 0; 
	for (; ~c && !isdigit (c); c = getc ())
		if (c == '-') f = -1;
	if (c == EOF) return 0;
	for (; ~c && isdigit (c); c = getc ())
		x = (x<<1) + (x<<3) + (c^48);
	x *= f; return 1;
}
inl int read (char *s) {
	static char c = getc ();
	for (; ~c && isspace (c); c = getc ());
	if (c == EOF) return 0; int len = 0;
	for (; ~c && !isspace (c); c = getc ())
		*s++ = c, ++len; return *s = 0, len;
}
template <typename T, typename...Targs>
inl bool read (T &x, Targs&... args) {
	return read (x) && read (args...); }
template <typename T> inl void print (T x) {
	if (x < 0) x = -x, putc ('-');
	static int st[36], top = 0;
	do { st[top++] = x % 10, x /= 10; } while (x);
	while (top) putc (st[--top] ^ '0');
}
template <typename T> inl void print (T *s) {
	for (; *s; ++s) putc (*s); }
template <typename T>
inl void print (T x, char c) {
	print (x), putc (c); }
template <typename T, typename...Targs>
inl void print (T x, Targs...args) {
	print (x), putc (' '), print (args...); }
struct IO {
	IO () { __pt = obuf, __ed = __st = ibuf; }
	~IO () { flush (); }
} __io;
#define putchar putc
#define puts(s) (print (s, '\n'))
#define scanf(...) fprintf (stderr, "fread loaded.")
#define printf scanf

typedef long long ll;
typedef unsigned long long ull;
// typedef __int128 lll;
// typedef long double llf;
typedef pair <int, int> pint;
#define fst first
#define scd second
#define all(p) begin (p), end (p)
#define empb emplace_back

#ifdef SHIKEN
#define msg(args...) fprintf (stderr, args)
#else
#define msg(...) void ()
#endif

constexpr int N = 5005, G = N/4 + 2, P = 1e9 + 7;
int T, n; char s[G]; bool vis[N], ins[N], e[N][N];
short ind[N], tt[N], bel[N], siz[N], c;
int pow2c[N], pow2u[N]; ll ans;

template <short bel[], short siz[]>
int imple () {
	static short p[N];
	memset (tt, 0, n + 1<<1);
	for (int x = 0; x < n; ++x)
		++tt[ind[x]];
	for (int d = 1; d <= n; ++d)
		tt[d] += tt[d - 1];
	for (int x = 0; x < n; ++x)
		p[tt[ind[x]]--] = x;
	int c = 0;
	for (int i = 0, j = 1, sum = 0; j <= n; sum = 0, i = j, ++j) {
		bel[p[j]] = ++c;
		auto &s = siz[c] = 1;
		while (sum += ind[p[j]], sum != ((j - i) * (j + i - 1)>>1))
			bel[p[++j]] = c, ++s;
	}
	return c;
}

inl void calc (const int x, const int y) {
	static short bel[N], siz[N];
	const bool jun = e[x][y];
	if (jun) ++ind[x], --ind[y];
	else ++ind[y], --ind[x];
	const int _c = imple <bel, siz> ();
	if (!jun) ++ind[x], --ind[y];
	else ++ind[y], --ind[x];
	ans += (ll) pow2c[max (x, y)] * pow2u[min (x, y)] % P * (_c - c);
}
bool route (int x, const int b, int u[], int &uc) {
	u[uc++] = x; ins[x] = 1;
	for (int y = 0; y < n; ++y)
		if (bel[y] == b && e[x][y] && vis[y])
			return calc (x, y), 1;
	for (int y = 0; y < n; ++y)
		if (bel[y] == b && e[x][y] && !ins[y] && route (x, b, u, uc))
			return calc (x, y), 1;
	for (int y = 0; y < n; ++y)
		if (bel[y] == b && e[x][y] && ins[y])
			return calc (x, y), 0;
	return 0;
}
inl void sousaku (const int id) {
	static int u[N], uc, pt;
	uc = pt = 0; int rt = 0;
	while (bel[rt] != id) ++rt;
	vis[rt] = 1; u[uc++] = rt;
	while (pt < uc) {
		const int x = u[pt]; bool on = 0;
		for (int y = 0; y < n; ++y) {
			if (bel[y] != id || vis[y] || !e[x][y]) continue;
			on = 1; int _uc = uc;
			calc (x, y);
			route (y, id, u, uc);
			while (_uc < uc) vis[u[_uc++]] = 1;
		}
		if (!on) ++pt;
	}
}

int main () {
	/*  */
pow2c[0] = pow2u[0] = 1;
for (int i = 1; i < N; ++i)
	pow2u[i] = (pow2u[i - 1]<<1) % P,
	pow2c[i] = pow2c[i - 1] * (ll) pow2u[i - 1] % P;

read (T);
while (T--) {
	read (n); ans = 0;
	memset (ind, 0, n + 1<<1);
	memset (vis, 0, n + 1);
	memset (ins, 0, n + 1);
	for (int x = 1; x < n; ++x) {
		read (s);
		for (int i = 0; (i<<2) <= x; ++i) {
			char &c = s[i];
			c = c >= 'A' ? c - 'A' + 10 : c - '0';
		}
		e[x][x] = 0;
		for (int y = 0; y < x; ++y) {
			const bool jun = (s[y>>2]>>(y & 3)) & 1;
			e[x][y] = jun, e[y][x] = !jun;
			ind[y] += jun, ind[x] += !jun;
			ans += (ll) pow2c[x] * pow2u[y] % P;
		}
	}
	c = imple <bel, siz> ();
	(ans %= P) *= c;
	for (int b = 0; b < c; ++b) sousaku (b);
	for (int x = 0; x < n; ++x)
		for (int y = 0; y < x; ++y) {
			const int b1 = bel[x], b2 = bel[y], dt = abs (b1 - b2);
			if (b1 == b2) continue;
			if (dt == 1 && siz[b2] == 1 && siz[b1] == 1);
			else ans -= (ll) pow2c[x] * pow2u[y] % P * dt;
		}
	print ((ans % P + P) % P); putc ('\n');
}

	return 0;
}

详细

Subtask #1:

score: 0
Runtime Error

Test #1:

score: 0
Runtime Error

input:

10000
100
1
2
2
8
C0
F0
27
78
AE1
C01
511
D87
EF20
3873
2742
73D0
DC9B0
FB2A3
9C011
9B4E0
95DC00
A7B980
F43531
6A6245
5347BE0
1A6C8A1
88E46D6
64CF3AE
D25F63C1
C894E4C3
1C0AFD73
EC1C3F9A
087CE17C0
22149A380
B28038AF1
B9CA21C7F
D78F5307C1
49045489A2
72C4DE6FD1
7713F40D05
EEE8878EEC1
310E62812B1
DA9D5B...

output:


result:


Subtask #2:

score: 0
Skipped

Dependency #1:

0%

Subtask #3:

score: 0
Skipped

Dependency #1:

0%

Subtask #4:

score: 0
Skipped

Dependency #1:

0%

Subtask #5:

score: 0
Skipped

Dependency #1:

0%