#include <bits/stdc++.h>

using namespace std;

typedef long long ll;

template <typename T>
struct sparse_table{
    static const int N = 1e5 + 10, L = 20;
    T a[N];
    int d[N][L], rem[N];
    void build(int n) {
        for (int i = 1; i <= n; i++) { d[i][0] = i; }
        for (int j = 1; j <= L - 1; j++) {
            for (int i = 1; i <= n; i++) {
                if (i + (1 << j) - 1 > n) { continue; }
                d[i][j] = __gcd(a[d[i][j - 1]], a[d[i + (1 << (j - 1))][j - 1]]);
            }
        }
        for (int i = 1; i <= n; i++) { rem[i] = log2(i); }
    }
    T get(int l, int r) {
        int lg = rem[r - l + 1];
        return __gcd(a[d[l][lg]], a[d[r - (1 << lg) + 1][lg]]);
    }
};

sparse_table<ll> table;

const int N = 1e5 + 10;
ll a[N];
vector<pair<int, ll>> rig[N];

ll solve(int l, int r, int k) {
    if (k >= r - l + 1) {
        return 1;
    } else if (k == 0) {
        return table.get(l, r);
    } else {
        ll ans = max(solve(l + 1, r, k - 1), solve(l, r - 1, k - 1));
        for (auto [x, val] : rig[l]) {
            ans = max(ans, __gcd(val, solve(x + 2, r, k - 1)));
        }
        return ans;
    }
}

int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
#ifdef LOCAL
    freopen("input.txt", "r", stdin);
#endif

    int n, q;
    cin >> n >> q;
    for (int i = 1; i <= n; i++) {
        cin >> a[i];
    }
    for (int i = 1; i <= n; i++) {
        table.a[i] = a[i];
    }
    table.build(n);

    rig[n] = {{n, a[n]}};

    for (int l = n - 1; l >= 1; l--) {
        rig[l] = {{l, a[l]}};
        for (auto [r, val] : rig[l + 1]) {
            val = __gcd(val, a[l]);
            if (val == rig[l].back().second) {
                rig[l].back().first = r;
            } else {
                rig[l].emplace_back(r, val);
            }
        }
    }

//    for (int i = 1; i <= n; i++) {
//        for (auto [r, val] : rig[i]) {
//            cout << r << " " << val << "\n";
//        }
//        cout << "\n";
//    }

    while (q--) {
        int l, r, k;
        cin >> l >> r >> k;
        cout << solve(l, r, k) << "\n";
    }

#ifdef LOCAL
    cout << "\nTime elapsed: " << double(clock()) / CLOCKS_PER_SEC << " s.\n";
#endif
}