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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#184995 | #5114. Cells Coloring | zwp1234 | TL | 0ms | 3712kb | C++17 | 3.2kb | 2023-09-21 15:33:24 | 2023-09-21 15:33:24 |
Judging History
answer
//# pragma GCC optimize(2)
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
const int inf = 0x3f3f3f3f;
const ll INF = 0x3f3f3f3f3f3f3f3f;
constexpr int N = 250 * 2 + 2 + 7;
constexpr int M = 250 * 250 + 250 * 2 + 7;
template <typename A, typename B>
bool smax(A &a, const B &b) { return a < b ? a = b, 1 : 0; }
template <typename A, typename B>
bool smin(A &a, const B &b) { return b < a ? a = b, 1 : 0; }
int n,m,k;
int S,T;
char s[N][N];
int col[N],row[N];
int h[N],e[M<<1],ne[M<<1],f[M<<1],tot;
void add(int u,int v, int x)
{
e[tot] = v,ne[tot] = h[u],f[tot] = x,h[u] = tot++;
e[tot] = u,ne[tot] = h[v],f[tot] = 0,h[v] = tot++;
}
int dep[N],cur[N],gap[N],q[N];
int nod;
void bfs()
{
int hd = 0, tl = 0;
q[++tl] = T, ++gap[dep[T] = 1];
while(hd < tl)
{
int u = q[++hd];
//cout << u << endl;
for(int i = h[u];~i;i = ne[i])
{
int v = e[i];
if(!dep[v] && f[i^1])
{
dep[v] = dep[u] + 1;
gap[dep[v]]++;
q[++tl] = v;
}
}
}
}
int dfs(int u,int a)
{
if(u == T || a == 0) return a;
int flow = 0,tmp;
for(int& i = cur[u];~i;i = ne[i])
{
int v = e[i];
if(dep[v] == dep[u] - 1 && (tmp = dfs(v,min(a,f[i]))))
{
flow += tmp;
f[i] -= tmp;
f[i^1] += tmp;
a -= tmp;
if(a == 0)
{
return flow;
}
}
}
--gap[dep[u]];
if(!gap[dep[u]]) gap[S] = nod + 1;
++gap[++dep[u]];
return flow;
}
int ISAP()
{
static int res = 0;
bfs();
while(dep[S] <= nod)
{
memcpy(cur,h,sizeof(*cur)*nod);
res += dfs(S,inf);
}
return res;
}
signed main()
{
ios::sync_with_stdio(0);
cin.tie(0),cout.tie(0);
#ifndef ONLINE_JUDGE
freopen("in.txt", "r+", stdin);
freopen("out.txt", "w+", stdout);
#endif
int c, d, mxk = 0, sum = 0;
cin >> n >> m >> c >> d;
for (int i = 1; i <= n; ++i)
{
cin >> (s[i] + 1);
for (int j = 1; j <= m; ++j)
s[i][j] = s[i][j] == '.', row[i] += s[i][j], col[j] += s[i][j], smax(mxk, col[j]);
smax(mxk, row[i]), sum += row[i];
}
S = 0, T = n + m + 1 ,nod = T + 1;
for(int i = S;i<=T;i++)
{
h[i] = -1;
}
for (int i = 1; i <= n; ++i)
add(S, i, 0);
for (int i = 1; i <= m; ++i)
add(i + n, T, 0);
for (int i = 1; i <= n; ++i)
for (int j = 1; j <= m; ++j)
if (s[i][j])
add(i, j + n, 1);
ll ans = LLONG_MAX;
for (int k = 0; k <= mxk; ++k)
{
if (k)
{
memset(gap, 0, sizeof(*gap) * nod);
memset(dep, 0, sizeof(*dep) * nod);
for (int i = 0; i < n; ++i)
++f[i * 2];
for (int i = 0; i < m; ++i)
++f[(i + n) * 2];
}
smin(ans, (ll)c * k + (ll)d * (sum - ISAP()));
}
cout << ans;
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 3660kb
input:
3 4 2 1 .*** *..* **..
output:
4
result:
ok 1 number(s): "4"
Test #2:
score: 0
Accepted
time: 0ms
memory: 3712kb
input:
3 4 1 2 .*** *..* **..
output:
2
result:
ok 1 number(s): "2"
Test #3:
score: -100
Time Limit Exceeded
input:
250 250 965680874 9042302 ..**.*****..**..**.*****..***..***.**......*.***.*...***.*....*.**.*.**.*.*.****...*.******.***.************....**.*..*..***.*******.*.***.*..**..****.**.*.*..***.****..**.....***.....*.****...*...*.***..****..**.*.*******..*.*******.*.*.*.****.*.*** ....**.*******.*.******...