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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#184061 | #5668. Cell Nuclei Detection | ucup-team1209# | AC ✓ | 270ms | 139080kb | C++20 | 2.3kb | 2023-09-20 11:18:20 | 2023-09-20 11:18:22 |
Judging History
answer
#include<bits/stdc++.h>
using std::cin;
using std::cout;
const int N = 50005;
const int M = 2000;
std::vector<int> ia[M][M];
struct rg {
int l, r;
int L()const{ return std::max(r-l,0); }
};
int n, m;
int last[N];
rg un(rg x, rg y) { return {std::max(x.l, y.l), std::min(x.r, y.r)}; }
struct mat {
rg x, y;
int s()const{ return x.L()*y.L(); }
} a[N], b[N];
mat un(mat x, mat y){ return {un(x.x, y.x), un(x.y, y.y)}; }
std::vector<int> edge[N];
std::vector<int> L, R, vis, matchl, matchr;
bool bfs(int nl, int nr) {
L.assign(nl + 1, 0);
R.assign(nr + 1, 0);
static std::queue<int> Q;
for(int i = 1;i <= nl;++i) if(!matchl[i]) L[i] = 1, Q.push(i);
int succ = 0;
for(;Q.size();) {
int x = Q.front(); Q.pop();
for(int i : edge[x]) if(!R[i]) {
R[i] = L[x] + 1;
if(int p = matchr[i]) {
L[p] = R[i] + 1, Q.push(p);
} else {
succ = 1;
}
}
}
return succ;
}
bool dfs(int x) {
for(int i : edge[x]) if(R[i] == L[x] + 1 && !vis[i]) {
vis[i] = 1;
if(!matchr[i] || dfs(matchr[i])) {
return matchl[x] = i, matchr[i] = x, 1;
}
}
return 0;
}
int match(int nl, int nr) {
matchl.assign(nl + 1, 0);
matchr.assign(nr + 1, 0);
vis.resize(nr + 1);
for(;bfs(nl, nr);) {
memset(vis.data(), 0, vis.size() << 2);
for(int i = 1;i <= nl;++i) if(!matchl[i]) dfs(i);
}
return matchl.size() - count(matchl.begin(), matchl.end(), 0);
}
int main() {
#ifdef zqj
freopen("$.in", "r", stdin);
#endif
std::ios::sync_with_stdio(false), cin.tie(0);
int t;
cin >> t;
for(int i = 0;i < t;++i) {
cin >> n >> m;
for(int i = 0;i < M;++i)
for(int j = 0;j < M;++j)
ia[i][j].clear();
for(int i = 1;i <= n;++i) {
cin >> a[i].x.l >> a[i].y.l;
cin >> a[i].x.r >> a[i].y.r;
for(int x = a[i].x.l;x < a[i].x.r;++x)
for(int y = a[i].y.l;y < a[i].y.r;++y)
ia[x][y].push_back(i);
last[i] = 0;
edge[i].clear();
}
for(int j = 1;j <= m;++j) {
cin >> b[j].x.l >> b[j].y.l;
cin >> b[j].x.r >> b[j].y.r;
for(int x = b[j].x.l;x < b[j].x.r;++x)
for(int y = b[j].y.l;y < b[j].y.r;++y) {
for(int id : ia[x][y]) {
if(last[id] == j) continue;
if(un(a[id], b[j]).s() * 2 >= a[id].s()) {
edge[id].push_back(j);
last[id] = j;
}
}
}
}
cout << match(n, m) << '\n';
}
}
詳細信息
Test #1:
score: 100
Accepted
time: 31ms
memory: 100232kb
input:
3 2 2 1 1 3 3 3 3 5 5 2 2 4 4 4 4 6 6 2 3 1 1 3 3 3 3 5 5 1 3 3 5 2 1 4 5 3 1 5 3 3 3 1 1 2 2 2 2 3 3 3 3 4 4 1 1 3 3 2 2 4 4 3 3 5 5
output:
0 1 3
result:
ok 3 lines
Test #2:
score: 0
Accepted
time: 24ms
memory: 100196kb
input:
3 2 2 1 1 3 3 3 3 5 5 2 2 4 4 4 4 6 6 2 3 1 1 3 3 3 3 5 5 1 3 3 5 2 1 4 5 3 1 5 3 3 3 1 1 2 2 2 2 3 3 3 3 4 4 1 1 3 3 2 2 4 4 3 3 5 5
output:
0 1 3
result:
ok 3 lines
Test #3:
score: 0
Accepted
time: 204ms
memory: 132464kb
input:
5 50000 50000 0 0 4 4 4 0 8 4 8 0 12 4 12 0 16 4 16 0 20 4 20 0 24 4 24 0 28 4 28 0 32 4 32 0 36 4 36 0 40 4 40 0 44 4 44 0 48 4 48 0 52 4 52 0 56 4 56 0 60 4 60 0 64 4 64 0 68 4 68 0 72 4 72 0 76 4 76 0 80 4 80 0 84 4 84 0 88 4 88 0 92 4 92 0 96 4 96 0 100 4 100 0 104 4 104 0 108 4 108 0 112 4 112 ...
output:
50000 50000 0 50000 3150
result:
ok 5 lines
Test #4:
score: 0
Accepted
time: 205ms
memory: 139080kb
input:
5 50000 50000 0 0 1 1 1 0 2 1 2 0 3 1 3 0 4 1 4 0 5 1 5 0 6 1 6 0 7 1 7 0 8 1 8 0 9 1 9 0 10 1 10 0 11 1 11 0 12 1 12 0 13 1 13 0 14 1 14 0 15 1 15 0 16 1 16 0 17 1 17 0 18 1 18 0 19 1 19 0 20 1 20 0 21 1 21 0 22 1 22 0 23 1 23 0 24 1 24 0 25 1 25 0 26 1 26 0 27 1 27 0 28 1 28 0 29 1 29 0 30 1 30 0 ...
output:
50000 25050 12500 16000 8000
result:
ok 5 lines
Test #5:
score: 0
Accepted
time: 212ms
memory: 121680kb
input:
5 50000 50000 0 0 2 4 4 0 7 1 8 0 10 1 12 0 15 3 16 0 19 1 20 0 22 2 24 0 26 4 28 0 30 4 32 0 36 3 36 0 40 1 40 0 44 1 44 0 47 2 48 0 49 3 52 0 54 1 56 0 59 4 60 0 64 3 64 0 68 3 68 0 70 1 72 0 76 4 76 0 80 3 80 0 84 4 84 0 87 2 88 0 90 1 92 0 94 4 96 0 98 1 100 0 104 1 104 0 107 2 108 0 110 4 112 0...
output:
10594 10779 10618 10381 10779
result:
ok 5 lines
Test #6:
score: 0
Accepted
time: 270ms
memory: 108928kb
input:
5 50000 50000 0 0 4 4 1 0 5 4 2 0 6 4 3 0 7 4 4 0 8 4 5 0 9 4 6 0 10 4 7 0 11 4 8 0 12 4 9 0 13 4 10 0 14 4 11 0 15 4 12 0 16 4 13 0 17 4 14 0 18 4 15 0 19 4 16 0 20 4 17 0 21 4 18 0 22 4 19 0 23 4 20 0 24 4 21 0 25 4 22 0 26 4 23 0 27 4 24 0 28 4 25 0 29 4 26 0 30 4 27 0 31 4 28 0 32 4 29 0 33 4 30...
output:
50000 50000 50000 50000 49600
result:
ok 5 lines
Test #7:
score: 0
Accepted
time: 12ms
memory: 100136kb
input:
1 4 4 1 1 3 3 2 1 4 3 1 2 3 4 2 2 4 4 2 1 4 3 3 2 5 4 1 2 3 4 2 3 4 5
output:
3
result:
ok single line: '3'