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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#182829 | #5422. Perfect Palindrome | KAZE_mae# | AC ✓ | 33ms | 3916kb | C++17 | 1.2kb | 2023-09-18 16:35:15 | 2023-09-18 16:35:15 |
Judging History
answer
#include<iostream>
#include<algorithm>
#include<vector>
#include<set>
#include<queue>
#include<map>
#include<math.h>
#include <functional>
#include<list>
#include<string>
#include<bitset>
#include<stack>
#include<cstring>
#include<stdio.h>
#define int long long
#define endl '\n'
#define mod 998244353
#define ffor(n) for(int i = 0;i < n;++i)
const int N = 2000006;
using namespace std;
void build_log();
int mv_x[4] = {1,0,-1,0};
int mv_y[4] = {0,1,0,-1};
int year[2][15] = {{31,28,31,30,31,30,31,31,30,31,30,31},{31,29,31,30,31,30,31,31,30,31,30,31}};//1æ¯é°å¹´,0æ¯éé°å¹´
int t;
int m_log2[500005]; // log2(x) + 1
int k;
int n,m;
int h;
int ss;
int tt;
signed main()
{
//ios::sync_with_stdio(false), cin.tie(nullptr), cout.tie(nullptr);
cin>>t;
while(t--)
{
string s;
cin>>s;
map<char,int>mm;
int mmax = 0;
ffor(s.size())
{
mm[s[i]]++;
mmax = max(mmax,mm[s[i]]);
}
cout<<s.size()-mmax<<endl;
}
return 0;
}
void build_log()
{
for(int i = 1;i <= n;i++)
{
m_log2[i] = m_log2[i-1] + ((1 << m_log2[i-1]) == i);
}
}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 3548kb
input:
2 abcb xxx
output:
2 0
result:
ok 2 number(s): "2 0"
Test #2:
score: 0
Accepted
time: 33ms
memory: 3916kb
input:
11107 lfpbavjsm pdtlkfwn fmb hptdswsoul bhyjhp pscfliuqn nej nxolzbd z clzb zqomviosz u ek vco oymonrq rjd ktsqti mdcvserv x birnpfu gsgk ftchwlm bzqgar ovj nsgiegk dbolme nvr rpsc fprodu eqtidwto j qty o jknssmabwl qjfv wrd aa ejsf i npmmhkef dzvyon p zww dp ru qmwm sc wnnjyoepxo hc opvfepiko inuxx...
output:
8 7 2 8 4 8 2 6 0 3 7 0 1 2 5 2 4 6 0 6 2 6 5 2 5 5 2 3 5 6 0 2 0 8 3 2 0 3 0 6 5 0 1 1 1 2 1 8 1 7 5 3 4 4 1 8 5 5 8 8 6 3 0 2 3 2 1 5 0 0 9 3 3 4 8 4 0 4 2 6 6 0 8 7 4 3 9 3 4 2 5 8 8 8 6 1 4 4 2 7 2 8 6 4 4 8 7 8 4 9 3 8 0 7 7 2 6 0 0 5 4 0 7 5 4 2 1 6 7 5 2 4 4 7 3 3 2 5 4 8 5 0 3 5 1 2 3 0 4 7 ...
result:
ok 11107 numbers