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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#181054#5433. Absolute Differenceysghwzp#WA 0ms3888kbC++141.9kb2023-09-16 15:29:182023-09-16 15:29:19

Judging History

你现在查看的是最新测评结果

  • [2023-09-16 15:29:19]
  • 评测
  • 测评结果:WA
  • 用时:0ms
  • 内存:3888kb
  • [2023-09-16 15:29:18]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
#define For(i,l,r) for(int i=(int)(l);i<=(int)(r);i++)
const int N=100005;
#define ld double
int n,m,q[N<<4];
int con[2];
ll tot[2];
#define pb push_back
#define PI pair<int,int>
#define fi first
#define se second
#define mp make_pair
vector<PI> v[2];
ld solve(int o){
    ld ans=0;
    unsigned cur=0;
    int sum=0;
    for(auto [l,r]:v[o^1]){
        ld fac=con[o^1]?(ld)(r-l)/tot[o^1]:(ld)1/tot[o^1];
        while(cur<v[o].size()&&v[o][cur].se<=l){sum+=con[o]?v[o][cur].se-v[o][cur].fi:1; cur++;}
        ans+=fac*sum/tot[o]*(r+l)/2;
        //cerr<<l<<" "<<r<<" "<<cur<<" "<<sum<<" "<<ans<<endl;
        if(cur<v[o].size()&&v[o][cur]==mp(l,r)){
            ans+=fac*(r-l)/6/tot[o];
            sum+=con[o]?r-l:1;
            cur++;
        }
        //cerr<<l<<" "<<r<<" "<<cur<<" "<<sum<<" "<<ans<<endl;
        ans-=fac*(tot[o]-sum)/tot[o]*(r+l)/2;
        //cerr<<l<<" "<<r<<" "<<cur<<" "<<sum<<" "<<ans<<endl;
    }
    return ans;
}
int main(){
    ios::sync_with_stdio(0); cin.tie(0);
    cin>>n>>m;
    vector<int> q;
    vector<PI> qj[2];
    For(o,0,1)For(i,1,n){
        int l,r;
        cin>>l>>r;
        q.pb(l); q.pb(r);
        con[o]|=r-l;
        tot[o]+=r-l;
        qj[o].pb(mp(l,r));
    }
    For(o,0,1)sort(qj[o].begin(),qj[o].end());
    sort(q.begin(),q.end());
    For(o,0,1){
        unsigned cur=0;
        For(i,0,n-1){
            int L=qj[o][i].fi,R=qj[o][i].se;
            while(cur<q.size()&&q[cur]<=L)cur++;
            while(cur<q.size()&&q[cur]<R){
                v[o].pb(mp(L,q[cur]));
                L=q[cur];
                cur++;
            }
            v[o].pb(mp(L,R));
        }
    }
    For(o,0,1)if(!con[o])tot[o]=n;
    For(o,0,1)sort(v[o].begin(),v[o].end());
    ld ans=0;
    For(o,0,1)ans+=solve(o);
    printf("%.10f\n",ans);
}

Details

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Test #1:

score: 100
Accepted
time: 0ms
memory: 3732kb

input:

1 1
0 1
0 1

output:

0.3333333333

result:

ok found '0.333333333', expected '0.333333333', error '0.000000000'

Test #2:

score: 0
Accepted
time: 0ms
memory: 3888kb

input:

1 1
0 1
1 1

output:

0.5000000000

result:

ok found '0.500000000', expected '0.500000000', error '0.000000000'

Test #3:

score: -100
Wrong Answer
time: 0ms
memory: 3728kb

input:

1 1
-1000000000 1000000000
-1000000000 1000000000

output:

0.3333333333

result:

wrong answer 1st numbers differ - expected: '666666666.6666666', found: '0.3333333', error = '1.0000000'