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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#180544#5669. Traveling in Jade Cityarseny_yRE 12ms223544kbC++204.9kb2023-09-15 23:08:362023-09-15 23:08:36

Judging History

你现在查看的是最新测评结果

  • [2023-09-15 23:08:36]
  • 评测
  • 测评结果:RE
  • 用时:12ms
  • 内存:223544kb
  • [2023-09-15 23:08:36]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

typedef long long ll;
typedef long double ld;
#define all(a) (a).begin(), (a).end()
#define X first
#define Y second

const int MOD = 1e9 + 7, MAXN = 2e6 + 1337;
const ld EPS = 1e-6;

void solve();

int main() {
#ifdef LOCAL
    freopen("../main_cpp/input.txt", "r", stdin);
#else
    cin.tie(nullptr)->sync_with_stdio(false);
#endif
    int _ = 1;
//    cin >> _;
    while (_--) {
        solve();
    }
}

#define int ll

const int INF = LLONG_MAX / 10000;

const int R = 1 << 20;

struct Tree {
    vector<int> t;

    Tree() {
        t.resize(R * 2, 1);
    }

    void relax(int i) {
        while (i) {
            t[i] = min(t[i * 2], t[i * 2 + 1]), i /= 2;
        }
    }

    void add(int i) {
        t[i += R] = 1, i /= 2, relax(i);
    }

    void del(int i) {
        t[i += R] = 0, i /= 2, relax(i);
    }

    int mn(int ql, int qr) {
        int mn = 1;
        for (ql += R, qr += R; ql <= qr; ql >>= 1, qr >>= 1) {
            if (ql & 1) mn = min(mn, t[ql++]);
            if (~qr & 1) mn = min(mn, t[qr--]);
        }
        return mn;
    }
};

int n, k, m, q;

struct Round {
    Tree tree;
    vector<int> indv, indedge_dick, indedge_round;
    vector<int> c_dick, c_round;
    vector<int> pref;

    int all_sm;

    void init(const vector<tuple<int, int, int, int>> t) {
        c_dick.resize(MAXN, 1), c_round.resize(MAXN, 1), indv.resize(MAXN, -1), indedge_dick.resize(MAXN,
                                                                                                      -1), indedge_round.resize(
                MAXN, -1);
        pref.resize(MAXN, 0);
        all_sm = 0;
        for (int i = 0; i < t.size(); ++i) {
            tree.add(i);
            auto [w, vertex, index_edge, f] = t[i];
            indv[vertex] = i;
            all_sm += w;
            if (f) {
                indedge_dick[index_edge] = i;
            } else {
                indedge_round[index_edge] = i;
            }
            pref[i] = w + (i > 0 ? pref[i - 1] : 0);
        }
    }

    void change_dick(int i) {
        c_dick[i] = -c_dick[i];
        if (indedge_dick[i] == -1) return;
        if (c_dick[i] == -1) {
            tree.del(indedge_dick[i]);
        } else {
            tree.add(indedge_dick[i]);
        }
    }

    void change_round(int i) {
        c_round[i] = -c_round[i];
        if (indedge_round[i] == -1) return;
        if (c_round[i] == -1) {
            tree.del(indedge_round[i]);
        } else {
            tree.add(indedge_round[i]);
        }
    }

    int gett(int l, int r) {
        return pref[r - 1] - (l == 0 ? 0 : pref[l - 1]);
    }

    int get(int l, int r) {
        if (tree.mn(l, r - 1) == 0) return INF;
        return gett(l, r);
    }

    int find(int u, int v) {
        if (u == v) return 0;
        int i1 = indv[u], i2 = indv[v];
        if (min(i1, i2) == -1) return INF;
        if (i1 > i2) swap(i1, i2);
        int ans = get(i1, i2);
        if (min(tree.mn(i2, R - 1), tree.mn(0, i1 - 1)) > 0) {
            ans = min(ans, all_sm - gett(i1, i2));
        }
        return ans;
    }
};

void solve() {
    cin >> n >> k >> m >> q;
    vector<int> a(n + 1);
    for (int i = 1; i <= n; ++i) {
        cin >> a[i];
    }
    ++m;
    vector<int> b(m);
    for (auto &i: b) {
        cin >> i;
    }
    Round roundleft, roundright;
    {
        vector<tuple<int, int, int, int>> t; // {w, vertex, index_edge}
        for (int i = 1; i < k; ++i) {
            t.emplace_back(a[i], i, i, 0);
        }
        for (int i = m - 1, v = n + m; i >= 0; --i, --v) {
            t.emplace_back(b[i], (v == n + m ? k : v), i, 1);
        }
        roundright.init(t);
    }
    {
        vector<tuple<int, int, int, int>> t; // {w, vertex, index_edge}
        for (int i = k; i <= n; ++i) {
            t.emplace_back(a[i], i, i, 0);
        }
        for (int i = 0, v = n; i < m; ++i, ++v) {
            t.emplace_back(b[i], (v == n ? 1 : v), i, 1);
        }
        roundleft.init(t);
    }
    auto get = [&](int u, int v) -> int {
        return min(roundleft.find(u, v), roundright.find(u, v));
    };
    while (q--) {
        char c;
        cin >> c;
        if (c == 'c') {
            int i;
            cin >> i;
            roundleft.change_round(i), roundright.change_round(i);
        } else if (c == 'x') {
            int i;
            cin >> i;
            roundleft.change_dick(i), roundright.change_dick(i);
        } else {
            int u, v;
            cin >> u >> v;
            int dst1k = get(1, k);
            int ans = get(u, v);
            ans = min({ans, min(get(u, 1) + get(k, v), get(u, k) + get(1, v)) + dst1k});
            ans = min({ans, get(u, 1) + get(1, v), get(u, k) + get(k, v)});
            cout << (ans >= INF ? "impossible" : to_string(ans)) << "\n";
        }
    }
}

詳細信息

Test #1:

score: 100
Accepted
time: 4ms
memory: 223496kb

input:

4 3 1 9
2 3 8 4
1 1
q 3 4
x 0
q 3 4
c 3
q 3 4
c 1
q 3 4
x 0
q 3 4

output:

6
8
9
impossible
6

result:

ok 5 lines

Test #2:

score: 0
Accepted
time: 12ms
memory: 223544kb

input:

4 3 1 9
2 3 8 4
1 1
q 3 4
x 0
q 3 4
c 3
q 3 4
c 1
q 3 4
x 0
q 3 4

output:

6
8
9
impossible
6

result:

ok 5 lines

Test #3:

score: -100
Dangerous Syscalls

input:

1000000 999999 1000000 1000000
200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 2...

output:

177406400
122264600
70328400
impossible
impossible
impossible
impossible
impossible
impossible
impossible
impossible
impossible
29295200
impossible
22163200
impossible
impossible
impossible
11422200
impossible
62579800
impossible
35339400
impossible
20157200
impossible
impossible
impossible
impossib...

result: