#include <bits/stdc++.h>
using namespace std;
#define fo(i,j,k) for(int i=(j),end_i=(k);i<=end_i;i++)
#define ff(i,j,k) for(int i=(j),end_i=(k);i< end_i;i++)
#define fd(i,j,k) for(int i=(j),end_i=(k);i>=end_i;i--)
#define debug(x) cerr<<#x<<"="<<x<<endl
#define debugv(x) cerr<<#x<<" : "; ff(i,0,(x).size()) cerr<<(x)[i]<<(i==(x).size()-1?'\n':' ')
#define all(x) (x).begin(),(x).end()
#define cle(x) memset(x,0,sizeof(x))
#define lowbit(x) ((x)&-(x))
#define VI vector<int>
#define ll long long
#define ull unsigned ll
#define lll __int128
#define db double
#define lb long db
#define pb push_back
#define mp make_pair
#define fi first
#define se second
#define endl "\n"
template<class T>inline void read(T &x) {
    x=0; char ch=getchar(); bool f=0;
    for(;ch<'0'||ch>'9';ch=getchar()) f|=(ch=='-');
    for(;ch>='0'&&ch<='9';ch=getchar()) x=x*10+(ch^48);
    if(f) x=-x;
}
template<class T, class... V>
inline void read(T &a, V&... b){read(a); read(b...);}
mt19937_64 rnd(chrono::steady_clock::now().time_since_epoch().count());

int A,B;
ll ha,hb,hc,C;
const int N = 110;
bool vis[N * N];
ll g[N * N];

inline ll ask(ll k, ll i) {
    k *= 2;
    ll l = 0, r = 2e9, mid;
    for (;l + 1 < r;) {
        mid = (l + r) >> 1;
        if (mid * (mid + i + i - 1) >= k)
            r = mid;
        else
            l = mid;
    }
    return r;
}
inline ll ask2(int k, int i) {
    if (k >= C)
        return 0;
    return ask(C-k, i);
}
namespace Sub1 {
    const ll inf = 0x3f3f3f3f3f3f3f3f;
    ll f[N][N<<1][N<<1];
    inline void getmin(ll &a, ll b) {
        a = min(a, b);
    }
    inline ll solve() {
        ll ans = inf;
        memset(f,0x3f,sizeof(f));
        f[0][0][0] = 0;
        fo(i,1,105)
            fo(j,0,A + 100)
                fo(k,0,B + 100)
                    if (f[i-1][j][k] < inf) {
                        if (j >= A && k >= B) {
                            //debug(i-1); debug(j); debug(k); debug(f[i-1][j][k]);
                            ans = min(ans, f[i-1][j][k] + ask2(i*(i-1)/2-j-k, i) * hc);
                            continue;
                        }
                        if (i == 105)
                            continue;
                        getmin(f[i][min(A + 100, j + i)][k], f[i-1][j][k] + (j >= A ? 0 : ha) + (k >= B ? 0 : hb) + ((i*(i-1)/2-j-k) >= C ? 0 : hc));
                        getmin(f[i][j][min(B + 100, k + i)], f[i-1][j][k] + (j >= A ? 0 : ha) + (k >= B ? 0 : hb) + ((i*(i-1)/2-j-k) >= C ? 0 : hc));
                        getmin(f[i][j][k], f[i-1][j][k] + (j >= A ? 0 : ha) + (k >= B ? 0 : hb) + ((i*(i-1)/2-j-k) >= C ? 0 : hc));
                    }
        return ans;
    }
}

inline ll ask(ll k) {
    k *= 2;
    ll l = 0, r = 2e9, mid;
    for (;l + 1 < r;) {
        mid = (l + r) >> 1;
        if (mid * (mid + 1) >= k)
            r = mid;
        else
            l = mid;
    }
    return r;
}
void Solve() {
    read(A,B,C,ha,hb,hc);
    ll ans = Sub1::solve();
    if (C > 5000) {
        ll tc = ask(C);
        ans = min(ans, tc * (ha + hb + hc) + ha + hb + min(ha, hb));
        ans = min({ans, ask(A) * ha + ask(A + C) * (hb + hc) + hb, ask(B) * hb + ask(B + C) * (ha + hc) + ha});
    }
    printf("%lld\n", ans);
}
int main() {
    //ios::sync_with_stdio(0); cin.tie(0);
    int T = 1;
    read(T);
    for(;T--;) Solve();
    return 0;
}