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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#180160 | #6309. Aqre | ucup-team045# | WA | 2ms | 3520kb | C++20 | 1.7kb | 2023-09-15 16:15:31 | 2023-09-15 16:15:31 |
Judging History
answer
#include<iostream>
#include<cstring>
#include<vector>
using namespace std;
using LL = long long;
int main(){
#ifdef LOCAL
freopen("data.in", "r", stdin);
freopen("data.out", "w", stdout);
#endif
cin.tie(0);
cout.tie(0);
ios::sync_with_stdio(0);
int T;
cin >> T;
while(T--){
int n, m;
cin >> n >> m;
pair<int, int> best;
int mx = 0;
vector<pair<int, int> > p{{0, 1}, {1, 3}, {2, 0}, {3, 2}};
auto get = [&](int x, int y){
int ans = n * m;
for(int i = 0; i < n; i++){
for(int j = 0; j < m; j++){
int xx = (i + x) % 4, yy = (j + y) % 4;
for(auto &[tx, ty] : p){
if (xx == tx && yy == ty){
ans--;
}
}
}
}
return ans;
};
for(int i = 0; i < 4; i++){
for(int j = 0; j < 4; j++){
int t = get(i, j);
if (t > mx){
mx = t;
best = {i, j};
}
}
}
vector<string> g(n, string(m, '1'));
for(int i = 0; i < n; i++){
for(int j = 0; j < m; j++){
int xx = (i + best.first) % 4, yy = (j + best.second) % 4;
for(auto &[tx, ty] : p){
if (xx == tx && yy == ty){
g[i][j] = '0';
}
}
}
}
cout << mx << '\n';
for(auto &s : g) cout << s << '\n';
}
}
Details
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Test #1:
score: 100
Accepted
time: 1ms
memory: 3504kb
input:
3 2 2 3 4 3 8
output:
4 11 11 9 1011 1110 0111 18 10111011 11101110 01110111
result:
ok ok (3 test cases)
Test #2:
score: -100
Wrong Answer
time: 2ms
memory: 3520kb
input:
361 2 2 2 3 2 4 2 5 2 6 2 7 2 8 2 9 2 10 2 11 2 12 2 13 2 14 2 15 2 16 2 17 2 18 2 19 2 20 3 2 3 3 3 4 3 5 3 6 3 7 3 8 3 9 3 10 3 11 3 12 3 13 3 14 3 15 3 16 3 17 3 18 3 19 3 20 4 2 4 3 4 4 4 5 4 6 4 7 4 8 4 9 4 10 4 11 4 12 4 13 4 14 4 15 4 16 4 17 4 18 4 19 4 20 5 2 5 3 5 4 5 5 5 6 5 7 5 8 5 9 5 1...
output:
4 11 11 5 101 111 6 1011 1110 8 10111 11101 10 110111 111011 11 1011101 1110111 12 10111011 11101110 14 101110111 111011101 16 1101110111 1110111011 17 10111011101 11101110111 18 101110111011 111011101110 20 1011101110111 1110111011101 22 11011101110111 11101110111011 23 101110111011101 111011101110...
result:
wrong answer ans finds a larger answer (test case 2)