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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#179103 | #7103. Red Black Tree | notyour_young# | TL | 0ms | 8276kb | C++17 | 2.2kb | 2023-09-14 18:02:30 | 2023-09-14 18:02:30 |
Judging History
answer
#include<bits/stdc++.h>
#define endl '\n'
#define int long long
using namespace std;
using i64 = long long;
using PII = pair<int, int>;
const int N = 1e5+10;
int dfn[N], fa[N][18], dep[N], ti, dis[N], dr[N];
vector<PII> g[N];
bool red[N];
void dfs(int u, int father)
{
dep[u] = dep[father] + 1;
dfn[u] = ++ ti;
fa[u][0] = father;
for(int k = 1;k < 18;k ++)
fa[u][k] = fa[fa[u][k - 1]][k - 1];
if(red[u])
dr[u] = 0;
for(auto [v, w] : g[u])
{
if(v == father)
continue;
dis[v] = dis[u] + w;
dr[v] = dr[u] + w;
dfs(v, u);
}
}
int lca(int a, int b)
{
if(dep[a] < dep[b])
swap(a, b);
for(int k = 17;k >= 0;k --)
if(dep[fa[a][k]] >= dep[b])
a = fa[a][k];
if(a == b)
return a;
for(int k = 17;k >= 0;k --)
if(fa[a][k] != fa[b][k])
a = fa[a][k], b = fa[b][k];
return fa[a][0];
}
vector<int> v;
int k;
bool check(i64 x)
{
vector<int> st;
for(int u : v)
if(dr[u] > x)
st.push_back(u);
// sort(st.begin(), st.end(), [&](int a, int b){
// return dfn[a] < dfn[b];
// });
if(st.size() <= 1)
return true;
int a = st[0], b = st[0];
for(int u : st)
{
if(dfn[u] < dfn[a])
a = u;
if(dfn[u] > dfn[b])
b = u;
}
int anc = lca(a, b);
for(int u : st)
if(dis[u] - dis[anc] > x)
return false;
return true;
}
void solve()
{
int n, m, q;
cin >> n >> m >> q;
for(int i = 1, v;i <= m;i ++)
cin >> v, red[v] = true;
for(int i = 1;i < n;i ++)
{
int u, v, w;
cin >> u >> v >> w;
g[u].push_back({v, w});
g[v].push_back({u, w});
}
dfs(1, 0);
// for(int i = 1;i <= n;i ++)
// cout << "u : " << i << ' ' << dr[i] << endl;
while(q --)
{
cin >> k;
v.clear();
for(int i = 1, u;i <= k;i ++)
cin >> u, v.push_back(u);
i64 l = 0, r = 1e18;
while(l < r)
{
i64 mid = l + r >> 1;
if(check(mid))
r = mid;
else
l = mid + 1;
}
cout << l << endl;
}
for(int i = 1;i <= n;i ++)
for(int k = 0;k < 18;k ++)
fa[i][k] = 0;
ti = 0;
for(int i = 1;i <= n;i ++)
red[i] = false, g[i].clear();
}
signed main()
{
ios::sync_with_stdio(false), cin.tie(0);
int tc;
cin >> tc;
while(tc --)
solve();
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 8276kb
input:
2 12 2 4 1 9 1 2 1 2 3 4 3 4 3 3 5 2 2 6 2 6 7 1 6 8 2 2 9 5 9 10 2 9 11 3 1 12 10 3 3 7 8 4 4 5 7 8 4 7 8 10 11 3 4 5 12 3 2 3 1 2 1 2 1 1 3 1 1 1 2 1 2 3 1 2 3
output:
4 5 3 8 0 0 0
result:
ok 7 lines
Test #2:
score: -100
Time Limit Exceeded
input:
522 26 1 3 1 1 4 276455 18 6 49344056 18 25 58172365 19 9 12014251 2 1 15079181 17 1 50011746 8 9 2413085 23 24 23767115 22 2 26151339 26 21 50183935 17 14 16892041 9 26 53389093 1 20 62299200 24 18 56114328 11 2 50160143 6 26 14430542 16 7 32574577 3 16 59227555 3 15 8795685 4 12 5801074 5 20 57457...
output:
148616264 148616264 0 319801028 319801028 255904892 317070839 1265145897 1265145897 1072765445 667742619 455103436 285643094 285643094 285643094 317919339 0 785245841 691421476 605409472 479058444 371688030 303203698 493383271 919185207 910180170 919185207 121535083 181713164 181713164 181713164 181...