QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#178342#4295. Check MarkersNYCU_Yamada#WA 1ms3480kbC++201.9kb2023-09-13 21:23:472023-09-13 21:23:47

Judging History

你现在查看的是最新测评结果

  • [2023-09-13 21:23:47]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:3480kb
  • [2023-09-13 21:23:47]
  • 提交

answer

#ifndef Yamada
#define Yamada
#include Yamada __FILE__ Yamada

void solve() {
    int N; cin >> N;
    
    vector<int> A(N), B(N);
    for (int &x : A) cin >> x;
    for (int &x : B) cin >> x;
    
    int sumA = accumulate(ALL(A), int(0));
    for (int i = 0; i < N; ++i) B[i] += A[i];
    sort(RALL(B));
    
    if (B[1] > sumA) cout << "NO" << "\n";
    else             cout << "YES" << "\n";
}

signed main() {
    IOS();
    int t = 1; cin >> t;
    for (int i = 1; i <= t; ++i) solve();
    return 0;
}

#else

#ifdef local
#define _GLIBCXX_DEBUG 1
#endif
#pragma GCC optimize("Ofast", "unroll-loops")
#include <bits/stdc++.h>
using namespace std;

#define int int64_t
// #define double __float80
using pii = pair<int, int>;
template <typename T> using MaxHeap = std::priority_queue<T>;
template <typename T> using MinHeap = std::priority_queue<T, vector<T>, greater<T>>;

// #define X first
// #define Y second
#define eb emplace_back
#define ef emplace_front
#define ee emplace
#define pb pop_back
#define pf pop_front
#define SZ(a) (int)((a).size())
#define ALL(a) begin(a), end(a)
#define RALL(a) rbegin(a), rend(a)

#ifdef local
#define IOS() void()
#define debug(...) \
    fprintf(stderr, "%sAt [%s], line %d: (%s) = ", "\u001b[33m", __FUNCTION__, __LINE__, #__VA_ARGS__), \
    _do(__VA_ARGS__), fprintf(stderr, "%s", "\u001b[0m")
template <typename T> void _do(T &&_t) {cerr << _t << "\n";}
template <typename T, typename ...U> void _do(T &&_t, U &&..._u) {cerr << _t << ", ", _do(_u...);}
#else
#define IOS() ios_base::sync_with_stdio(0); cin.tie(0)
#define debug(...) void()
#define endl '\n'
#endif

// mt19937_64 rng(steady::chrono_clock::now().time_since_epoch().count());

template <typename T, typename U> bool chmin(T &lhs, U rhs) {return lhs > rhs ? lhs = rhs, 1 : 0;}
template <typename T, typename U> bool chmax(T &lhs, U rhs) {return lhs < rhs ? lhs = rhs, 1 : 0;}

#endif

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 3480kb

input:

3
3
1 2 1
2 1 1
2
1 1
2 2
4
1 1 1 1
2 1 2 1

output:

YES
NO
YES

result:

ok 3 token(s): yes count is 2, no count is 1

Test #2:

score: -100
Wrong Answer
time: 1ms
memory: 3460kb

input:

100
4
1 4 1 5
4 1 4 1
4
3 3 2 5
1 2 3 1
4
0 1 1 4
3 1 3 5
4
1 0 1 5
5 5 5 3
4
0 4 4 0
4 3 1 0
4
2 3 5 4
0 3 4 4
4
5 5 4 0
4 1 2 0
4
5 2 0 2
4 5 1 1
4
5 0 3 3
1 1 3 1
4
2 4 5 5
4 5 3 1
4
0 3 0 2
1 3 5 3
4
4 2 2 1
0 2 5 3
4
4 0 2 2
4 2 5 3
4
4 2 4 3
1 4 1 5
4
2 3 3 3
5 3 0 4
4
3 4 1 0
4 0 4 2
4
4 1 0 ...

output:

YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
NO
YES
NO
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
NO
YES
YES
YES
YES
YES
YES
NO
YES
YES
YES
YES
...

result:

wrong answer expected NO, found YES [3rd token]