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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#177471 | #6634. Central Subset | tovarisch | RE | 0ms | 13888kb | C++17 | 1.7kb | 2023-09-13 00:00:51 | 2023-09-13 00:00:51 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
using pii = pair<int, int>;
const int maxn = 2e5 + 10;
int n, m, limit;
int vis[maxn], height[maxn], dis[maxn];
vector <int> graph[maxn] ,tree[maxn], ans;
void dfs(int u) {
vis[u]=1;
for (int &v : graph[u]) {
if (vis[v]) continue;
tree[u].push_back(v);
tree[v].push_back(u);
dfs(v);
}
}
void dfs2(int u, int p, int d, bool f=0) {
if (d >= limit) {
ans.push_back(u);
d=0;
f=1;
}
int in=0;
for(int&v : tree[u]) {
if (v == p) continue;
in=1;
dfs2(v, u, d+1, f);
}
if (!in && !f) ans.push_back(u);
}
void clean() {
for (int i=0; i<n; i++) {
graph[i].clear();
tree[i].clear();
vis[i]=0, height[i]=0, dis[i]=maxn;
}
ans.clear();
}
int main() {
ios_base::sync_with_stdio(0), cin.tie(0);
#ifdef LOCAL
freopen("input.txt", "r", stdin);
freopen("output.txt", "w", stdout);
#endif // LOCAL
int tt; cin >> tt;
while (tt--) {
cin >> n >> m;
for (int i=0; i < m; i++) {
int u, v; cin >> u >> v;
u--, v--;
graph[u].push_back(v);
graph[v].push_back(u);
}
dfs(0);
limit = ceil(sqrt(n));
dfs2(0, 0, 0);
if (ans.empty()) ans.push_back(0);
sort(ans.begin(), ans.end());
ans.resize(unique(ans.begin(), ans.end()) - ans.begin());
assert(ans.size()<= limit);
cout << ans.size() << endl;
for(int& i : ans) cout << i+1 << ' ';
cout << endl;
clean();
}
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 13888kb
input:
2 4 3 1 2 2 3 3 4 6 7 1 2 2 3 3 1 1 4 4 5 5 6 6 4
output:
1 3 2 3 6
result:
ok correct (2 test cases)
Test #2:
score: -100
Runtime Error
input:
10000 15 14 13 12 5 4 9 8 11 12 15 14 10 9 14 13 2 3 2 1 6 5 10 11 3 4 7 6 8 7 6 5 2 1 2 4 4 6 2 3 3 5 10 9 8 3 9 4 5 6 5 10 3 2 5 4 2 7 1 2 4 3 2 1 2 1 2 1 2 1 9 8 9 8 5 4 1 2 6 5 3 4 3 2 7 8 7 6 2 1 1 2 14 13 3 10 5 6 2 9 11 4 2 3 2 1 8 7 13 6 5 4 5 12 6 7 4 3 7 14 16 15 2 3 2 1 6 10 6 9 6 4 9 11 ...
output:
3 5 9 13 2 5 6 4 5 7 8 9 1 2 1 2 2 4 7 1 2 4 5 9 10 11 3 5 6 15