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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#176536#6427. Just Another Game of StoneshazeTL 19ms116516kbC++143.7kb2023-09-11 19:26:332023-09-11 19:26:33

Judging History

你现在查看的是最新测评结果

  • [2023-09-11 19:26:33]
  • 评测
  • 测评结果:TL
  • 用时:19ms
  • 内存:116516kb
  • [2023-09-11 19:26:33]
  • 提交

answer

#pragma GCC optimize("Ofast")
#pragma GCC target("avx2,abm,mmx")
#include<bits/stdc++.h>
#define ll long long
#define irep(i,l,r) for(ll i = l; i <= r; ++i)
using namespace std;
inline int read(){
	int s=0;
	char chcc=getchar();
	while(chcc<'0'||chcc>'9')chcc = getchar();
	while(chcc>='0'&&chcc<='9') s=(s<<3)+(s<<1)+(chcc^48),chcc=getchar();
	return s;
}
const int N = 600999;
const int itinf = 1000000000;
int n, m;
struct node{
	vector<int>bsum;
	int xorsum, mn, smn, len, tag;
	node(){bsum.resize(32);}
}t[N];
/*
void fdmn(vector<int>aa, int &mn, int &smn){
	sort(aa.begin(), aa.end());
	unique(aa.begin(), aa.end());
	mn = aa[0], smn = aa[1];
}
*/
void update(int x){
	t[x].mn = min(t[x << 1].mn, t[x << 1 | 1].mn);
	t[x].smn = itinf;
	if(t[x << 1].mn > t[x].mn)t[x].smn = min(t[x].smn, t[x << 1].mn);
	if(t[x << 1].smn > t[x].mn)t[x].smn = min(t[x].smn, t[x << 1].smn);
	if(t[x << 1 | 1].mn > t[x].mn)t[x].smn = min(t[x].smn, t[x << 1 | 1].mn);
	if(t[x << 1 | 1].smn > t[x].mn)t[x].smn = min(t[x].smn, t[x << 1 | 1].smn);
	
	
//	fdmn({t[x << 1].mn, t[x << 1].smn, t[x << 1 | 1].mn, t[x << 1 | 1].smn}, t[x].mn, t[x].smn);
	t[x].len = 0, t[x].xorsum = t[x << 1].xorsum ^ t[x << 1 | 1].xorsum;
	if(t[x << 1].mn == t[x].mn)t[x].len += t[x << 1 | 1].len;
	if(t[x << 1 | 1].mn == t[x].mn)t[x].len += t[x << 1 | 1].len;
	irep(i,0,31)t[x].bsum[i] = t[x << 1].bsum[i] + t[x << 1 | 1].bsum[i];
}

void operate(int x,int lim){
	if(t[x].len & 1)t[x].xorsum ^= (lim ^ t[x].mn);
	t[x].tag = lim;
	int od = t[x].mn, nw = lim;
	irep(i,0,31){
		t[x].bsum[i] += ((nw & 1) - (od & 1)) * t[x].len;
		nw >>= 1, od >>= 1;
	}
	t[x].mn = lim;
}

void pushdown(int x){
	int tag = t[x].tag;
	t[x].tag = 0;
	if(t[x << 1].mn < tag)operate(x << 1,tag);
	if(t[x << 1 | 1].mn < tag)operate(x << 1 | 1,tag);
}

void build(int x,int l,int r){
	if(l == r){
		int val;
		val = t[x].mn = t[x].xorsum = read();
		t[x].len = 1;
		t[x].smn = t[x].tag = itinf;
		irep(i,0,31){
			t[x].bsum[i] += val & 1;
			val >>= 1;
		}
		return;
	}
	int mid = (l + r) >> 1;
	build(x << 1,l, mid);
	build(x << 1 | 1, mid + 1, r);
	update(x);
	return;
}
void modify(int x,int l,int r,int L,int R, int lim){
	// x -> max(x, val)
	if(l > R || L > r)return;
	if(L <= l && r <= R){
		if(lim <= t[x].mn)return;
		if(l != r && t[x].tag)pushdown(x);
		if(lim < t[x].smn){
			operate(x,lim);
			return;
		}
		int mid = (l + r) >> 1;
		if(l == r)return;
		modify(x << 1,l, mid, L,R,lim);
		modify(x << 1 | 1, mid + 1, r ,L,R,lim);
		update(x);
		return;
	}
	if(l != r && t[x].tag)pushdown(x);
	int mid = (l + r) >> 1;
	modify(x << 1,l, mid, L,R,lim);
	modify(x << 1 | 1, mid + 1, r ,L,R,lim);
	update(x);
	return;
}
int xor_query(int x,int l,int r,int L,int R){
	if(l > R || L > r)return 0;
	if(L <= l && r <= R)return t[x].xorsum;
	if(l != r && t[x].tag)pushdown(x);
	int mid = (l + r) >> 1;
	return xor_query(x << 1,l,mid,L,R) ^ xor_query(x << 1 | 1,mid+1,r,L,R);
}
int bit_cnt(int x,int l, int r, int L ,int R,int id){
	if(l > R || L > r)return 0;
	if(L <= l && r <= R)return t[x].bsum[id];
	if(l != r && t[x].tag)pushdown(x);
	int mid = (l + r) >> 1;
	return bit_cnt(x << 1 ,l,mid,L,R,id) + bit_cnt(x << 1 | 1,mid+1,r,L,R,id);
}
int main(){
	clock_t st = clock();
	n = read(), m = read();
	build(1,1,n);
	while(m --){
		clock_t cur = clock();
		if(cur - st >= 3000){
			cout << m << endl;
		}
		int op = read(), l = read(), r = read(), x = read();
		if(op == 1){
			modify(1,1,n,l,r,x);
		}else{
			ll key = xor_query(1,1,n,l,r);
			if((key ^ x) == 0){
				puts("0");
				continue;
			}
			int hb = log2(key ^ x);
			ll ans = bit_cnt(1,1,n,l,r,hb);
			if(x & (1 << hb))++ ans;
			if(n <= 10000)printf("%lld\n",ans);
		}
	}
	return 0;
}

详细

Test #1:

score: 100
Accepted
time: 19ms
memory: 116516kb

input:

5 4
1 2 1 4 1
2 1 3 1
1 2 4 3
2 2 4 4
2 1 4 4

output:

1
0
3

result:

ok 3 number(s): "1 0 3"

Test #2:

score: -100
Time Limit Exceeded

input:

200000 200000
962352030 173642520 1008864183 74920228 684681800 500911321 1001441054 257633652 185843534 59168654 317689197 731348417 123888883 708119712 340055368 876566011 980078202 969174443 814012870 715639041 596932238 173757742 314504576 1045746913 740811577 570187156 999816627 12441059 122507...

output:

199999
199998
199997
199996
199995
199994
199993
199992
199991
199990
199989
199988
199987
199986
199985
199984
199983
199982
199981
199980
199979
199978
199977
199976
199975
199974
199973
199972
199971
199970
199969
199968
199967
199966
199965
199964
199963
199962
199961
199960
199959
199958
199957...

result: