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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#176438#6427. Just Another Game of StoneshazeTL 62ms229060kbC++143.1kb2023-09-11 17:10:512023-09-11 17:10:51

Judging History

你现在查看的是最新测评结果

  • [2023-09-11 17:10:51]
  • 评测
  • 测评结果:TL
  • 用时:62ms
  • 内存:229060kb
  • [2023-09-11 17:10:51]
  • 提交

answer

#include<bits/stdc++.h>
#define ll long long
#define irep(i,l,r) for(ll i = l; i <= r; ++i)
using namespace std;
inline ll read(){
	ll s=0; bool fl = 0;
	char chcc=getchar();
	while(chcc<'0'||chcc>'9'){if(chcc == '-')fl = 1;chcc = getchar();}
	while(chcc>='0'&&chcc<='9') s=(s<<3)+(s<<1)+(chcc^48),chcc=getchar();
	return fl?-s:s;
}
const int N = 1200999;
const int itinf = 1000000000;
int n, m;
struct node{
	vector<int>bsum;
	int xorsum, mn, smn, len, tag;
	node(){bsum.resize(32);}
}t[N];
void fdmn(vector<int>aa, int &mn, int &smn){
	sort(aa.begin(), aa.end());
	unique(aa.begin(), aa.end());
	mn = aa[0], smn = aa[1];
}
void update(int x){
	fdmn({t[x*2].mn, t[x*2].smn, t[x*2+1].mn, t[x*2+1].smn}, t[x].mn, t[x].smn);
	t[x].len = 0, t[x].xorsum = t[x*2].xorsum ^ t[x*2+1].xorsum;
	if(t[x*2].mn == t[x].mn)t[x].len += t[x*2].len;
	if(t[x*2+1].mn == t[x].mn)t[x].len += t[x*2+1].len;
	irep(i,0,31)t[x].bsum[i] = t[x*2].bsum[i] + t[x*2+1].bsum[i];
}

void operate(int x,int lim){
	if(t[x].len & 1)t[x].xorsum ^= (lim ^ t[x].mn);
	t[x].tag = lim;
	int od = t[x].mn, nw = lim;
	irep(i,0,31){
		t[x].bsum[i] += ((nw & 1) - (od & 1)) * t[x].len;
		nw >>= 1, od >>= 1;
	}
	t[x].mn = lim;
}

void pushdown(int x){
	int tag = t[x].tag;
	t[x].tag = 0;
	if(t[x*2].mn < tag)operate(x*2,tag);
	if(t[x*2+1].mn < tag)operate(x*2+1,tag);
}

void build(int x,int l,int r){
	if(l == r){
		int val;
		val = t[x].mn = t[x].xorsum = read();
		t[x].len = 1;
		t[x].smn = t[x].tag = itinf;
		irep(i,0,31){
			t[x].bsum[i] += val & 1;
			val >>= 1;
		}
		return;
	}
	int mid = (l + r) >> 1;
	build(x * 2,l, mid);
	build(x * 2 + 1, mid + 1, r);
	update(x);
	return;
}
void modify(int x,int l,int r,int L,int R, int lim){
	// x -> max(x, val)
	if(l > R || L > r)return;
	if(L <= l && r <= R){
		if(lim <= t[x].mn)return;
		pushdown(x);
		if(lim < t[x].smn){
			operate(x,lim);
			return;
		}
		int mid = (l + r) >> 1;
		if(l == r)return;
		modify(x * 2,l, mid, L,R,lim);
		modify(x * 2 + 1, mid + 1, r ,L,R,lim);
		update(x);
		return;
	}
	pushdown(x);
	int mid = (l + r) >> 1;
	modify(x * 2,l, mid, L,R,lim);
	modify(x * 2 + 1, mid + 1, r ,L,R,lim);
	update(x);
	return;
}
int xor_query(int x,int l,int r,int L,int R){
	if(l > R || L > r)return 0;
	if(L <= l && r <= R)return t[x].xorsum;
	if(l != r)pushdown(x);
	int mid = (l + r) >> 1;
	return xor_query(x*2,l,mid,L,R) ^ xor_query(x*2+1,mid+1,r,L,R);
}
int bit_cnt(int x,int l, int r, int L ,int R,int id){
//	cerr << x << ' '<<l << ' ' << r<<' '<< id<<endl;
	if(l != r)pushdown(x);
	if(l > R || L > r)return 0;
	if(L <= l && r <= R)return t[x].bsum[id];
	int mid = (l + r) >> 1;
	return bit_cnt(x *2 ,l,mid,L,R,id) + bit_cnt(x*2+1,mid+1,r,L,R,id);
}
int main(){
	n = read(), m = read();
	build(1,1,n);
	while(m --){
		int op = read(), l = read(), r = read(), x = read();
		if(op == 1){
			modify(1,1,n,l,r,x);
		}else{
			ll key = xor_query(1,1,n,l,r);
			if((key ^ x) == 0){
				puts("0");
				continue;
			}
			int hb = log2(key ^ x);
			ll ans = bit_cnt(1,1,n,l,r,hb);
			if(x & (1 << hb))++ ans;
			printf("%lld\n",ans);
		}
	}
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 62ms
memory: 229060kb

input:

5 4
1 2 1 4 1
2 1 3 1
1 2 4 3
2 2 4 4
2 1 4 4

output:

1
0
3

result:

ok 3 number(s): "1 0 3"

Test #2:

score: -100
Time Limit Exceeded

input:

200000 200000
962352030 173642520 1008864183 74920228 684681800 500911321 1001441054 257633652 185843534 59168654 317689197 731348417 123888883 708119712 340055368 876566011 980078202 969174443 814012870 715639041 596932238 173757742 314504576 1045746913 740811577 570187156 999816627 12441059 122507...

output:

38889
57353
46659
19709
34617
92781
1211
755
16087
26119
10557
9165
7337
14363
9129
21117
93233
16733
64611
737
32715
25031
148859
17395
76263
56261
19825
93349
48429
22291
31645
9833
35195
95623
184389
39321
153
6067
6495
25369
9041
35785
39783
111237
151543
54289
121169
165785
101803
14803
15271
1...

result: