QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#175774#6880. Operation HopeNyansRE 0ms0kbC++141.9kb2023-09-10 23:11:062023-09-10 23:11:07

Judging History

你现在查看的是最新测评结果

  • [2023-09-10 23:11:07]
  • 评测
  • 测评结果:RE
  • 用时:0ms
  • 内存:0kb
  • [2023-09-10 23:11:06]
  • 提交

answer

#include <cstdio>
#include <vector>
#include <algorithm>
int T, n, a[3][200010], id[3][200010];
std::vector <int> e[1600010];
int dfn[1600010], low[1600010], tm, stk[1600010], tp, col[1600010], cnt;
void tarjan(int u) {
	dfn[u] = low[u] = ++tm, stk[++tp] = u;
	for (int v: e[u]) {
		if (dfn[v]) low[u] > dfn[v]? low[u] = dfn[v]: 0;
		else tarjan(v), low[u] > low[v]? low[u] = low[v]: 0;
	}
	if (low[u] == dfn[u]) 
		for (++cnt, stk[tp + 1] = -1; stk[tp + 1] != u; --tp) 
            col[stk[tp]] = cnt, low[stk[tp]] = 1e9;
}
int main() {
	scanf("%d", &T);
	while (T--) {
		scanf("%d", &n); n *= 2;
		for (int i = 0; i < n; ++i) for (int k = 0; k < 3; ++k) scanf("%d", &a[k][i]);
		for (int i = 0; i < n * 7; ++i) e[i].clear();
		for (int i = 0; i < 3; ++i) {
			for (int j = 0; j < n; ++j) id[i][j] = j;
			std::sort(id[i], id[i] + n, [i](int x, int y) { return a[i][x] < a[i][y]; });
			int L = (i * 2 + 1) * n, R = L + n;
			for (int j = L + 1; j < R; ++j) e[j].push_back(j - 1), e[j + n - 1].push_back(j + n);
			for (int j = 0; j < n; ++j) e[L + j].push_back(id[i][j] ^ 1), e[R + j].push_back(id[i][j] ^ 1);
		}
		int L = 0, R = 1e9;
		while (L <= R) {
			int mid = (L + R) / 2;
			for (int i = 0; i < n; ++i) e[i].clear();
			for (int i = 0; i < 3; ++i) {
				int L = (i * 2 + 1) * n, R = L + n;
				for (int k = 0, r = 0; k < n; ++k) {
					int j = id[i][k];
					while (a[i][id[i][r]] + mid < a[i][j]) ++r;
					if (r) e[j].push_back(L + r - 1);
				}
				for (int k = n - 1, l = n - 1; k >= 0; --k) {
					int j = id[i][k];
					while (a[i][j] + mid < a[i][id[i][l]]) --l;
					if (l != n - 1) e[j].push_back(R + l + 1);
				}
			}
			for (int i = 0; i < n * 7; ++i) dfn[i] = 0; tm = 0;
			for (int i = 0; i < n; ++i) if (!dfn[i]) tarjan(i);
			int F = 1;
			for (int i = 0; i < n; i += 2) if (col[i] == col[i + 1]) F = 0;
			if (F) R = mid - 1;
			else L = mid + 1;
		}
		printf("%d\n", L);
	}
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 0
Runtime Error

input:

99
1000
532114032 55099632 197592060 601440117 964448551 693620489
68503446 149314803 308777541 408078601 977772348 978400861
185066959 236214410 460480442 842502015 709303988 675932475
793016330 161748857 511444978 852914351 281720292 552030608
9982160 15933748 8254470 175080600 567563770 461489051...

output:


result: