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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#171786 | #6626. Real Mountains | shuopihua | 0 | 3ms | 35464kb | C++14 | 2.8kb | 2023-09-09 17:35:40 | 2023-09-09 17:35:41 |
Judging History
answer
#pragma GCC optimize("O2")
#pragma GCC optimize("Ofast")
#pragma GCC optimize("inline")
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <vector>
#include <set>
#define mod 1000003
#define ll long long
using namespace std;
int n;
int a[1000005];
int b[1000005];
int mn[4000005];
int id[4000005];
set <int> st;
vector <int> g[1000005];
inline void in(int &n){
n=0;
char c=getchar();
while(c<'0' || c>'9') c=getchar();
while(c>='0'&&c<='9') n=n*10+c-'0',c=getchar();
return ;
}
void build(int u,int l,int r){
if(l==r){id[l]=u;return ;}
int mid=(l+r)>>1;
build(u<<1,l,mid);
build(u<<1|1,mid+1,r);
return ;
}
inline void updata(int u,int x){
u=id[u];
mn[u]=x;
u>>=1;
while(u){
mn[u]=min(mn[u<<1],mn[u<<1|1]);
u>>=1;
}
return ;
}
int query(int u,int l,int r,int L,int R){
if(L<=l&&r<=R) return mn[u];
int mid=(l+r)>>1,mnn=2e9;
if(L<=mid) mnn=min(mnn,query(u<<1,l,mid,L,R));
if(R>mid) mnn=min(mnn,query(u<<1|1,mid+1,r,L,R));
return mnn;
}
void out(ll n){
if(n>9) out(n/10);
putchar(n%10+'0');
}
inline ll work(ll a,ll b){
if(a%2==0) return (a/2)%mod*b%mod;
return a%mod*((b/2)%mod)%mod;
}
signed main(){
// freopen("repair.in","r",stdin);
// freopen("repair.out","w",stdout);
in(n);
build(1,1,n);
for(int i=1;i<=4*n;i++) mn[i]=2e9;
for(int i=1;i<=n;i++) in(a[i]),b[i]=a[i],updata(i,a[i]);
sort(b+1,b+1+n);
int m=unique(b+1,b+1+n)-b-1;
for(int i=1;i<=n;i++) g[lower_bound(b+1,b+1+m,a[i])-b].push_back(i);
set <int> :: iterator it,ti;
ll ans=0;
for(int i=1;i<m;i++){
for(int j:g[i]) updata(j,2e9),st.insert(j);
it=st.begin();
if((*it)==1) st.erase(it);
if(st.empty()) continue;
it=st.end();
it--;
if((*it)==n) st.erase(it);
if(st.empty()) continue;
it=st.begin();
while(it!=st.end())
if(max(query(1,1,n,1,*it),query(1,1,n,*it,n))>1e9) ti=it,it++,st.erase(ti);
else break;
if(st.empty()) continue;
it=st.end();
it--;
while(it!=st.begin())
if(max(query(1,1,n,1,*it),query(1,1,n,*it,n))>1e9) ti=it,it--,st.erase(ti);
else break;
if(st.empty()) continue;
int l,r;
it=st.begin();
l=*it;
it=st.end();
it--;
r=*it;
int m1=query(1,1,n,1,l);
int m2=query(1,1,n,l,n);
int m3=query(1,1,n,1,r);
int m4=query(1,1,n,r,n);
ll s1=0,s2=0,x=mn[1];
if(l==r){
(ans+=1ll*(x-b[i])%mod*(m1+m2)%mod+work(b[i]+x-1,x-b[i]))%=mod;
continue;
}
ll mm=min(m1+m2+m4,m1+m3+m4);
(ans+=((x-b[i])%mod*mm%mod+(b[i]+x-1)%mod*(x-b[i])%mod+work(b[i]+x-1,x-b[i]))%mod)%=mod;
(ans+=min(s1,s2))%=mod;
ll tt=(ll)st.size()-2;
(ans+=tt%mod*(b[i]+x+1)%mod*(x-b[i])%mod+tt*(work(b[i]+x-1,x-b[i]))%mod)%=mod;
}
printf("%lld\n",ans);
return 0;
}
/*
10
72 33 22 22 13 49 53 57 72 85
10
4 1 2 5 4 5 1 2 9 5
*/
詳細信息
Subtask #1:
score: 0
Wrong Answer
Test #1:
score: 3
Accepted
time: 3ms
memory: 34880kb
input:
3 29 9 9
output:
0
result:
ok 1 number(s): "0"
Test #2:
score: 0
Accepted
time: 1ms
memory: 35188kb
input:
3 62 20 71
output:
7287
result:
ok 1 number(s): "7287"
Test #3:
score: -3
Wrong Answer
time: 3ms
memory: 35464kb
input:
10 72 33 22 22 13 49 53 57 72 85
output:
40353
result:
wrong answer 1st numbers differ - expected: '40403', found: '40353'
Subtask #2:
score: 0
Skipped
Dependency #1:
0%
Subtask #3:
score: 0
Skipped
Dependency #2:
0%
Subtask #4:
score: 0
Skipped
Dependency #3:
0%
Subtask #5:
score: 0
Skipped
Dependency #2:
0%
Subtask #6:
score: 0
Skipped
Dependency #3:
0%
Subtask #7:
score: 0
Skipped
Dependency #1:
0%